Bài 9: Đúng điền Đ, sai điền S:
34 = 9/12 5/8 < 3/8 4/5 > 4/7 1 < 15 /16
Bài 1 : Đúng ghi Đ , sai ghi S :
a , 11/9 + 5/6 > 5/2 ( Điền Đ or S )
b , 12/17 x 51/44 < 8/9 ( Điền Đ or S )
c , 2/5 + 4/7 > 2 - 6/7 ( Điền Đ or S )
d , 2 : 6/5 < 3/2 : 4/5 ( Điền Đ or S )
Trả lời nhanh lên tôi k cho
AI GIÚP MÌNH MÌNH K CHO 3KKKKKKKKKK
Điền dấu : >,<,=
a,5/3 x 7/10 .... 5/7 : 7/10
b, 4/5 x 5/6 ..... 8/9 : 4/3
c, 5/11 x 33/15 ..... 6/17 x 34/25
d, 15/19 x 38/5 ..... 15/16 : 3/8
Mong mn làm giúp ạ
a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)
\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)
=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)
b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)
Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)
c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)
\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)
=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)
d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)
\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6
=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)
Điền dấu > , < , =
9 + 6...16 9 + 9...9 + 7
9 + 4...4 + 9 9 + 6...15
9 + 8...9 + 9 9 + 3...5 + 9
Phương pháp giải:
- Tính giá trị các vế.
- So sánh rồi điền dấu thích hợp vào chỗ trống.
Lời giải chi tiết:
9 + 6 < 16 9 + 9 > 9 + 7
9 + 4=4 + 9 9 + 6=15
9 + 8 < 9 + 9 9 + 3 < 5 + 9
Điền dấu > ; < hoặc = vào chỗ chấm cho thích hợp:
a) \(\dfrac{3}{4}.....\dfrac{4}{5}\) b) \(\dfrac{11}{12}.....\dfrac{7}{8}\) c) \(\dfrac{5}{7}+\dfrac{3}{5}.....\dfrac{6}{7}:\dfrac{5}{8}\) d) \(\dfrac{9}{16}-\dfrac{5}{9}.....\dfrac{1}{16}x\dfrac{1}{9}\)
1) 5/7.37 13/23-51 13/23.5/7
2) -2/3 +1/3+0,5+2 1/2
3)-0,5+2/3+1/2
4) (8+2 1/3-3/5) -(5+0,4)-(3 1/2 -2)
5) (2/9-7/12):3/4+(16/9-5/12):3/4
6) -(2021.0,7+19,75) +0,7- (8-19,75)
7)15/34+7/21+19/34-20/15
8) 2 5/6+1/6:(-5/8)
9) (-2)^2 +2/9. (4/5-2/3)
10) (-1/5+3/7):5/4+(-4/5+4/7):5/4
11) 2022,2021 . 1954,1945+ 2022,2021 . (-1954,1945)
12) -5,2 .72 +69,1 +5,2 . (-28)+(-1,1)
13) (7 -1/2-3/4) : (5-1/4-5/8)
14) (8+ 2 1/3 -3/5) -(5+0,4) -( 3 1/3 - 2)
`@` `\text {Ans}`
`\downarrow`
`1)`
`5/7*37 13/23 - 51 13/23*5/7`
`= 5/7* (37 13/23 - 51 13/23)`
`= 5/7* (-14)`
`= -10`
`2)`
`-2/3 +1/3+0,5+2 1/2`
`= -2/3 + 1/3 + 1/2 + 5/2`
`= (-2/3+1/3) + (1/2+5/2)`
`= -1/3 + 3`
`=8/3`
`3)`
`-0,5+2/3+1/2`
`= -1/2 + 2/3 + 1/2`
`= (-1/2 + 1/2) + 2/3`
`= 2/3`
`4)`
`(8+2 1/3-3/5) -(5+0,4)-(3 1/2 -2)`
`= 8+ 7/3 - 3/5 - 5 - 0,4 - 7/2 + 2`
`= (8+2-5) + (-3/5 - 2/5) + (7/3 - 7/2)`
`= 5 - 1 - 7/6`
`= 4 - 7/6 = 17/6`
`5)`
`(2/9-7/12):3/4+(16/9-5/12):3/4`
`= (2/9 - 7/12) \times 4/3 + (16/9 - 5/12) \times 4/3`
`= 4/3 *(2/9 - 7/12 + 16/9 - 5/12)`
`= 4/3 * [(2/9 + 16/9) + (-7/12 - 5/12)]`
`= 4/3 * ( 2 - 1)`
`= 4/3 * 1 = 4/3`
`6)`
`-(2021.0,7+19,75) +0,7- (8-19,75)`
`= -2021*0,7 -19,75 + 0,7 - 8 + 19,75`
`= 0,7*(-2021 + 1) - 8`
`= -1414-8`
`= -1422`
`7)`
`15/34+7/21+19/34-20/15`
`= (15/34 + 19/34) + 7/21 - 20/15`
`= 1 + 7/21 - 20/15`
`= 4/3 - 20/15 =0`
`8)`
`2 5/6+1/6:(-5/8)`
`= 17/6 + (-4/15)`
`= 77/30`
`9)`
`(-2)^2 +2/9. (4/5-2/3)`
`= 4 + 2/9*2/15`
`= 4+4/135`
`= 544/135`
`10)`
`(-1/5+3/7):5/4+(-4/5+4/7):5/4`
`= (-1/5+3/7) * 4/5 + (-4/5+4/7) * 4/5`
`= 4/5*(-1/5 +3/7-4/5+4/7)`
`= 4/5*[(-1/5-4/5)+(3/7+4/7)]`
`= 4/5* (-1+1)`
`= 4/5*0=0`
`11)`
`2022,2021 . 1954,1945+ 2022,2021 . (-1954,1945)`
`= 2022,2021 * [1954,1945 + (-1954,1945)]`
`= 2022,2021*0 `
`= 0`
`12)`
`-5,2 .72 +69,1 +5,2 . (-28)+(-1,1)`
`= -5,2*72 + 69,1 - 5,2*28 - 1,1`
`= -5,2*(72+28) + (69,1 - 1,1)`
`= -5,2*100 + 68`
`= -520 + 68`
`= -452`
`13)`
`(7 -1/2-3/4) : (5-1/4-5/8)`
`= 23/4 \div 33/8`
`=46/33`
`14)`
`(8+ 2 1/3 -3/5) -(5+0,4) -( 3 1/3 - 2)`
`= 8+ 2 1/3 - 3/5 - 5 - 0,4 - 3 1/3 + 2`
`= (8+2-5) + (2 1/3 - 3 1/3) - (0,6 + 0,4) `
`= 5 - 1 - 1`
`= 3`
2: \(=\dfrac{-1}{3}+3=\dfrac{8}{3}\)
3: =1/2-1/2+2/3=2/3
5: \(=\dfrac{4}{3}\left(\dfrac{2}{9}-\dfrac{7}{12}+\dfrac{16}{9}-\dfrac{5}{12}\right)=\dfrac{4}{3}\)
12: \(=5.2\left(-72-28\right)+68=-520+68=-452\)
13: \(\dfrac{23}{4}:\dfrac{33}{8}=\dfrac{46}{33}\)
Điền dấu (>,<,=) thích hợp vào chỗ chấm:
9+7…15 9+4…15 |
8+3…4+8 8+5…9+5 |
9+7…7+9 9+3…3+9 |
|
điền Đ hay S
a) 3/4+5/12 =7/6
b) 6/11 nhân 22/9 =2/3
c) 5/12 : 3/4= 5/9
d) 5/2 - 4/5 nhân 3/8= 5/9
Đúng ghi đ sai ghi s vào ô trống: a) 15/17 > 13/15 b) 9/7 < 11/9 c) 5/9 < 3/7 d) 12/17 = 24/34
+ giải thích = 1 tích
tinh
a 7/15 + (5/6 - 1/3) =
b 4/7 *21/16 : 5/8 =
c 15/8 - 4/9 * 6/8+ 1/6 =
d 5/12+(3/4 + 2/3 ) : 34/3 =
a 7/15 + (5/6 - 1/3) = 7/15 + 1/2 = 14/30 + 15/30 = 29/30
b 4/7 *21/16 : 5/8 = 3/4 : 5/8 = 6/5
c 15/8 - 4/9 * 6/8+ 1/6 =15/8 - 1/3 + 1/6 = 37/24 + 1/6 = 41/24
d 5/12+(3/4 + 2/3 ) : 34/3 =
a/\(\frac{7}{15}+\left(\frac{5}{6}-\frac{1}{3}\right)=\frac{7}{15}+\frac{1}{2}=\frac{29}{30}\)
b/\(\frac{4}{7}\cdot\frac{21}{16}:\frac{5}{8}=\frac{4}{7}\cdot\frac{2}{16}\cdot\frac{8}{5}=\frac{4}{35}\)
c/\(\frac{15}{8}-\frac{4}{9}\cdot\frac{6}{8}+\frac{1}{6}=\frac{15}{8}-\frac{1}{3}+\frac{1}{6}=\frac{41}{24}\)
d/ \(\frac{5}{12}+\left(\frac{3}{4}+\frac{2}{3}\right):\frac{34}{3}=\frac{5}{12}+\frac{17}{12}:\frac{34}{3}=\frac{5}{12}+\frac{1}{8}=\frac{13}{24}\)
a/ \(\frac{7}{15}+\left(\frac{5}{6}-\frac{1}{3}\right)\)
= \(\frac{7}{15}+\frac{1}{2}\)
= \(\frac{29}{30}\)
b/ \(\frac{4}{7}.\frac{21}{16}:\frac{5}{8}\)
= \(\frac{4}{7}.\frac{21}{16}.\frac{8}{5}\)
= \(\frac{6}{5}\)
c/ \(\frac{15}{8}-\frac{4}{9}.\frac{6}{8}+\frac{1}{6}\)
= \(\frac{15}{8}-\frac{1}{3}+\frac{1}{6}\)
= \(\frac{41}{24}\)
d/ \(\frac{5}{12}+\left(\frac{3}{4}+\frac{2}{3}\right):\frac{34}{3}\)
= \(\frac{5}{12}+\frac{17}{12}\)\(:\frac{34}{3}\)
= \(\frac{5}{12}+\frac{1}{8}\)
= \(\frac{13}{24}\)