tim x c N biet
a, 10 + 2x = 415 :413
b, x c U ( 30) va x > 12
tim cac so tu nhien x , biet :
a, x thuoc U(18) va x thuoc B(4)
b, x thuoc U(36) va x > hoac = 12
c, x thuoc B(12) VA 30 < HOAC = X < HOAC = 100
d, x thuoc U(28) va x thuoc U (21)
a: \(x\in\left\{1;2;3;6;9;18\right\}\)
mà \(x\in B\left(4\right)\)
nên \(x\in\varnothing\)
b: \(x\in\left\{1;2;3;4;6;9;12;18;36\right\}\)
mà x>=12
nên \(x\in\left\{12;18;36\right\}\)
c: \(x\in\left\{0;12;24;36;48;60;72;84;96;108;...\right\}\)
mà 30<=x<=100
nên \(x\in\left\{36;48;60;72;84;96\right\}\)
d: \(x\inƯC\left(28;21\right)\)
\(\Leftrightarrow x\inƯ\left(7\right)\)
hay \(x\in\left\{1;7\right\}\)
tim x thuoc N bieta, 125.n 5 7b, 2 3.n 3 4 2 5 5c, 2 3 2 n 3 2.n.5 10 10 2d, 5 n=
125
Tim x c N, biet :
a/ x chia hết cho 12 và 0 < x be hoac bang 30
b/ 70 chia het cho x; 84 chia het cho x; va x > 8
c/x chia hết 12; x chia hết 25; x chia het 30; va 0 < x< 500.
c,
x chia hết cho 12
x chia hết cho 25
=> x thuộc BC(12 , 25)
12 = 2^2.3 ; 25 = 5^2
=> BCNN(12,25) = 2^2.3.5^2 = 300
B(300) = {0;300;600;....}
Vậy x = 300
tim x c N biet
30 chia het cho x; 45 chia het cho x ; va 2< x < 10
30 chia hết cho x; 45 chia hết cho x ; va 2< x < 10
=> x thuộc ỨC(30;45)
=> WCLN(30;45) = 15
=> x = Ư(15) = {1;3;5;15}
Vì 2 < x < 10 => x= 3;5
a) 28 + 2x = 35 – (- 13) ; b) - 25 – (x + 5) = 415 + 5(x – 83)
c) 2 (x + 1)2 = - 7 + 15 ; f) (x – 4)2 – 48 = - 12 ;
g) (x + 3)3:3 – 1 = - 10 ; h) (3x + 9)(11 – x) = 0.
a, 28 + 2x = 35 - ( -13 )
=> 2x = 35 + 13 - 28
=>2x = 20
=> x = 10. vậy x = 10
a, \(28+2x=35+13\Leftrightarrow28+2x=48\Leftrightarrow2x=20\Leftrightarrow x=10\)
b, \(-25-x-5=415+5x-415\Leftrightarrow-6x=30\Leftrightarrow x=-5\)
Tim x,y,z biet :x/10 =y/7=z/23 va 2x+y-z =12
\(\frac{x}{10}=\frac{y}{7}=\frac{z}{23}\Rightarrow\frac{x}{10}=\frac{y}{7}=\frac{z}{23}=\frac{2x+y-z}{20+7-23}=\frac{12}{4}=3\)
\(\Rightarrow x=30;y=21;z=69\)
Tìm x
a) 1800 : [(3^6-14)+30] = 72 va` x E Z
b) 11 - (x-6) = 9
c) 2x + 1 E U(x+5) va` x E N
giup minh` voi
tim tap hop cac so tu nhien x,sao cho
a,x thuoc U(100) va x thuoc U(12);b,x thuoc U(125) va x thuoc B(70);C, x thuoc U(12) va x thuoc B(19);d, x thuoc U(17) va x thuoc B(25)
Bài 6: Tìm số nguyên x, biết
A, 3 – (17 – x) = 289 – (36 + 289)
B, 25 – (x + 5) = -415 – (15 – 415)
C, 34 + (21 – x) = (3747 – 30) – 3746
D, -2x – (x – 17) = 34 – (-x + 25)
E, 17x + (-16x – 37) = 2x + 43
G, (x + 12). (x – 3) = 0
H, (-x + 5). (3 – x) = 0
K, -28 – 7. |-3x + 15| = - 70
M, 12 – 2. (-x + 3)2 = - 38
N, - {-3x + 2. [45 – x – 3. (3x + 7) – 2x] + 4x} = 55
Bài 7: So sánh
A, (-99). 98. (-97) với 0
B, (-5). (-4). (-3). (-2). (-1) với 0
C, (-245). (-47). (-199) với 123. (+315)
D, 2987. (-1974). (+243). 0 với 0
E, (-12). (-45) : (-27) với |-1|
A , 3 - ( 17 - x ) = 289 - ( 36 + 289 )
3 - 17 + x = 0 - 36
-14 + x = -36
x = -36 - ( - 14 ) = -22
B, 25 - ( x + 5 ) = -415 - ( 15 - 415 )
25 - x - 5 = 0 - 15
20 - x = -15
x = 20 - ( - 15 ) = 35
C , 34 + ( 21 - x ) = ( 3747 - 30 ) - 3746
34 + 21 - x = 1 - 30
55 - x = -29
x = 55 - (-29 ) = 74
D , -2x - ( x -17 ) = 34 - ( -x + 25 )
- 2x - x + 17 = 34 - 25 + x
- 3x + 17 = 9 + x
- 3x - x = 9 - 17
-4x = -8
x = -8 : ( - 4 )
x = 2
E , 17x + ( -16x - 37 ) = x + 43
17x - 16x -37 = x + 43
x - 37 = x + 43
-37 - 43 = x - x
- 80 = 0 ( vô lý )
G , ( x + 12 ) . (x - 3 ) = 0
\(\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\)
\(\hept{\begin{cases}x=-12\\x=3\end{cases}}\)