=>x/16=7/8+7/16=14/16+7/16=21/16

=>x=21

bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\) 

     \(x\times\dfrac{11}{16}=2\) 

     \(x=2:\dfrac{11}{16}\) 

    \(x=\dfrac{32}{11}\)

Bài 1 : 

 \(\dfrac{x}{16}\times\left(2017-1\right)=2\)

          \(\dfrac{x}{16}\times2016=2\)

                      \(\dfrac{x}{16}=\dfrac{2}{2016}\)

                         \(x=\dfrac{2}{2016}\times16\)

                         \(x=\dfrac{1}{63}\)

1- (5\(\dfrac{4}{9}\) +x+7\(\dfrac{7}{18}\)) : 15\(\dfrac{3}{4}\) = 0 

1- (\(\dfrac{49}{9}+x+\dfrac{133}{18}\)) : \(\dfrac{63}{4}=0\) 

 (\(\dfrac{49}{9}+\dfrac{133}{18}\)+\(x\) ) : \(\dfrac{63}{4}\) = 1 - 0 

       (\(\dfrac{77}{6}\) + \(x\) ) : \(\dfrac{63}{4}\) = 1

         \(\dfrac{77}{6}+x\)         = 1 x \(\dfrac{63}{4}\) 

          \(\dfrac{77}{6}\) + \(x\)          = \(\dfrac{63}{4}\)

                  \(x\)            = \(\dfrac{63}{4}\) - \(\dfrac{77}{6}\)

                  \(x=\) \(\dfrac{35}{12}\)

dễ mà

x+7=-16-2

x=7=-18

x=-18:7

x=-18/7

x-9=7 

x= 7+9

x=16

x-5 = 0 hoặc x+7= 0

x=5 hoặc x=-7

=> x thuộc { 5,-7}

tức vờ lờ

a) x – 9 = -14

x = -14 + 9

x = -5

b) 2( x + 7 ) = -16

2( x + 7 ) = 2 . ( -8 )

x + 7 = -8

x = -8 – 7 = -15

c) | x – 9 | = 7

x – 9 = 7 hoặc x – 9 = -7

x = 7 + 9 hoặc x = -7 + 9

x = 16 hoặc x = 2

d) ( x – 5 )( x + 7 ) = 0

x – 5 = 0 hoặc x + 7 = 0

x = 5 hoặc x = -7

24 − x = 7

X = 24 − 7

 X = 17

59 − x = 16

X = 59 − 16

X = 43

60 − x = 38

X = 60 − 38

X = 22

Đề bài sai, pt này ko giải được

Đề đúng: \(\dfrac{4x^2+16}{x^2+6}=...\)

Mẫu số bên trái thừa mất số 1

a) \(\left(x+4\right)^2-\left(x+1\right)\left(x-1\right)=16\)

(x + 4)² - (x + 1) (x - 1) = 16

<=> (x² + 8x + 16) - (x² - 1) = 16

<=> x² + 8x + 16 - x² + 1 = 16

<=> 8x + 17 = 16

<=> 8x = -1

<=> x = 

\(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)

\(4x^2+1-4x+\left(x^2+9+6x\right)-5\left(x^2-7^2\right)=0\)

\(4x^2+1-4x+x^2+9+6x-5x^2+245=0\)

\(\left(4x^2+x^2-5x^2\right)-\left(4x+6x\right)+\left(1+9+245\right)=0\)

\(2x+255=0\)

\(2x=-255\)

\(x=\dfrac{-255}{2}\)

P/s: Nhớ tick cho mình nha. Thanks bạn

a) Ta có: \(\left(x+4\right)^2-\left(x+1\right)\left(x-1\right)=16\)

\(\Leftrightarrow x^2+8x+16-x^2+1=16\)

\(\Leftrightarrow8x+17=16\)

\(\Leftrightarrow8x=-1\)

hay \(x=-\dfrac{1}{8}\)

b) Ta có: \(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)

\(\Leftrightarrow4x^2-4x+1+x^2+6x+9-5\left(x^2-49\right)=0\)

\(\Leftrightarrow5x^2+2x+10-5x^2+245=0\)

\(\Leftrightarrow2x=-255\)

hay \(x=-\dfrac{255}{2}\)

a) X + 15 = 20

       X = 20 – 15

       X = 5

b) X – 18 = 16

       X = 16 + 18

       X = 34

c) 72 – x = 50

       X = 72 -50

       X =22

d) X x 7 = 42

       X= 42 : 7

       X = 6

e) X : 7 = 5

       X = 5 x 7

       X = 35

f) 49 : x = 7

       X = 49: 7

       X = 7

Bài 2:

a: Ta có: \(2x+79=x+45\)

nên 2x-x=45-79

hay x=-24

b: Ta có: \(15-\left(x+7\right)=\left(x-8\right)+22\)

\(\Leftrightarrow8-x-x-14=0\)

\(\Leftrightarrow2x=22\)

hay x=11