bạn rút gọn các phân số đó thành các phân số có mẫu là 10 rồi cộng lại thôi

rút gọn hết các ps trong biểu thức, ta được:

 3/10+3/10+3/10+3/10+3/10+3/10+3/10

=21/10

rut gon la duoc ...tich nhe hiha

1/15.18 + 1/18.21 + 1/21.24 + ... + 1/87.90

= 1/3.(3/15.18 + 3/18.21 + 3/21.24 + ... + 3/87.90)

= 1/3.(1/15 - 1/18  + 1/18 - 1/21 + 1/21 - 1/24 + ... + 1/97 - 1/90)

= 1/3.(1/15 - 1/90)

= 1/3.1/18

= 1/54

   Đặt tổng trên là A

3A = \(\frac{1\cdot3}{15\cdot18}+\frac{1\cdot3}{18\cdot21}+...+\frac{1\cdot3}{87\cdot90}\)

\(=\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{87}-\frac{1}{90}\)

\(=\frac{1}{15}-\frac{1}{90}\)

\(=\frac{1}{30}\)

\(A=\frac{1}{30}\div3=\frac{1}{30\cdot3}=\frac{1}{90}\)

                                 \(#Louis\)

\(D=\frac{6}{15\times18}+\frac{6}{18\times21}+\frac{6}{21\times24}+...+\frac{6}{87\times90}\)

\(=2\times\left(\frac{3}{15\times18}+\frac{3}{18\times21}+...+\frac{3}{87\times90}\right)\)

\(=2\times\left(\frac{18-15}{15\times18}+\frac{21-18}{18\times21}+...+\frac{90-87}{87\times90}\right)\)

\(=2\times\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{87}-\frac{1}{90}\right)\)

\(=2\times\left(\frac{1}{15}-\frac{1}{90}\right)=\frac{1}{9}\)

\(s=\frac{6}{15\times18}+\frac{6}{18\times21}+\frac{6}{21\times24}+....+\frac{6}{87\times90}\)

\(s-3=\frac{3}{15\times18}+\frac{3}{18\times21}+\frac{3}{21\times24}+....+\frac{3}{87\times90}\)

\(s-3=\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+\frac{1}{21}-\frac{1}{24}+....+\frac{1}{87}-\frac{1}{90}\)

\(s-3=\frac{1}{15}-\frac{1}{90}\)

\(s-3=\frac{1}{18}\)

\(s=\frac{1}{18}+3\)

\(s=\frac{55}{18}\)

\(A=\frac{9}{15.18}+\frac{9}{18.21}+.....+\frac{9}{89.92}\)

\(A=3.\left(\frac{3}{15.18}+\frac{3}{18.21}+....+\frac{3}{89.92}\right)\)

\(A=3.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+......+\frac{1}{89}-\frac{1}{92}\right)\)

\(A=3.\left(\frac{1}{15}-\frac{1}{92}\right)\)

\(A=3.\frac{77}{1380}=\frac{77}{460}\)

$A=\frac{9}{15.18}+\frac{9}{18.21}+.....+\frac{9}{89.92}$

$A=3.\left(\frac{3}{15.18}+\frac{3}{18.21}+....+\frac{3}{89.92}\right)$

$A=3.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+......+\frac{1}{89}-\frac{1}{92}\right)$

$A=3.\left(\frac{1}{15}-\frac{1}{92}\right)$

$A=3.\frac{77}{1380}=\frac{77}{460}$

`->B`

`3/5 =(3xx7)/(5xx7)=21/35`

`->C`

`2/3=(2xx4)/(3xx4)=8/12`

`-> D`

`3/3=1 ; 90/90=1`

`->E`

`1/3=(1xx9)/(3xx9)=9/27`

Các nhóm có hai phân số bằng nhau:
\(b,c,d\) và \(e\)

Các nhóm bằng nhau là:

\(b,\dfrac{3}{5}=\dfrac{21}{35}\\ c,\dfrac{8}{12}=\dfrac{2}{3}\\ d,\dfrac{3}{3}=\dfrac{90}{90}\\ e,\dfrac{9}{27}=\dfrac{1}{3}\)

2, 

a) \(315-\left(135-x\right)=215\)

\(\Rightarrow135-x=315-215\)

\(\Rightarrow135-x=100\)

\(\Rightarrow x=135-100\)

\(\Rightarrow x=35\)

b) \(x-320:32=25\cdot16\)

\(\Rightarrow x-10=5^2\cdot4^2\)

\(\Rightarrow x-10=20^2\)

\(\Rightarrow x-10=400\)

\(\Rightarrow x=410\)

c) \(3\cdot x-2018:2=23\)

\(=3\cdot x-1009=23\)

\(\Rightarrow3\cdot x=1032\)

\(\Rightarrow x=1032:3\)

\(\Rightarrow x=344\)

d) \(280-9\cdot x-x=80\)

\(\Rightarrow280-x\cdot\left(9+1\right)=80\)

\(\Rightarrow280-10\cdot x=80\)

\(\Rightarrow10\cdot x=280-80\)

\(\Rightarrow10\cdot x=200\)

\(\Rightarrow x=20\)

e) \(38\cdot x-12\cdot x-x\cdot16=40\)

\(\Rightarrow x\cdot\left(38-12-16\right)=40\)

\(\Rightarrow x\cdot10=40\)

\(\Rightarrow x=40:10\)

\(\Rightarrow x=4\)

bài 1 cậu ko giải giúp mình dc à

a,8

b,30

c,12

d,4

e,1

g,18

h,6

k,1

a) ƯCLN ( 16, 24 )

16 = 2³              24 = 2².3

ƯCLN ( 16;24 ) = 2²= 4

b) ƯCLN ( 60, 90 )

60 = 2².3.5          90=2.3².5

ƯCLN ( 60;90 ) = 2.3.5 = 30

c)  ƯCLN ( 24, 84 )

24 = 2³.3                       84 = 2².3.7

ƯCLN ( 24;84 ) = 2².3 = 12

d) ƯCLN ( 16, 60 )

16 = 2⁴              60 = 2².3.5

ƯCLN ( 16;60 ) = 2²=4

e) ƯCLN ( 18, 77 )

18 = 2.3²             77=7.11

 ƯCLN ( 18; 77 ) = 1

g) ƯCLN ( 18, 90 )

18 = 2.3²           90=2.3².5

 ƯCLN ( 18;90 ) = 2.3² = 18

h) ƯCLN ( 18, 30, 42 )

18 = 2.3²             30 = 2.3.5         42 = 2.3.7

 ƯCLN ( 18;30;42 ) = 2.3=6

k) ƯCLN ( 26, 39, 48 )

26 = 2.13           39 = 3.13      48 = 2⁴.3

 ƯCLN ( 26;39;48 ) = 1

sai 30 :18 = ?