a) \(\frac{x^7}{81}=27\)

=> x⁷ = 27.81

=> x⁷ = 3³.3⁴

=> x⁷ = 3⁷

=> x = 3

Vậy x = 3

b) \(\frac{x^8}{9}=729\)

=> x⁸ = 729.9

=> x⁸ = 3⁶.3²

=> x⁸ = 3⁸ = (-3)⁸

=> \(x\in\left\{3;-3\right\}\)

Vậy \(x\in\left\{3;-3\right\}\)

\(\frac{x^7}{81}=27\Rightarrow x^7=27.81\Rightarrow x^7=3^3.3^4\Rightarrow x^7=3^7\Rightarrow x=3\)

\(\frac{x^8}{9}=729\Rightarrow x^8=729.9\Rightarrow x^8=3^6.3^2\Rightarrow x^8=3^8\Rightarrow x=3\)

a) Ta có: \(\frac{x^7}{81}=27\)

\(\Rightarrow x^7=27.81=2187\)

Mà \(2187=3^7\) \(\Rightarrow x^7=3^7\Leftrightarrow x=3\)

Vậy x = 3

b) Ta có: \(\frac{x^8}{9}=729\)

\(\Rightarrow x^8=729.9=6561\)

Mà \(6561=3^8\) \(\Rightarrow x^8=3^8\Leftrightarrow x=3\)

Vậy x = 3

CHÚC BẠN HỌC TỐT

\(\frac{x^7}{81}=27\Rightarrow27.81=x^7\Rightarrow x=3\)

\(\frac{x^8}{9}=729\Rightarrow x^8=729.9\Rightarrow x=3\)

tíc mình

nha

\(a.\)\(\frac{x^7}{81}=27\)

\(\Rightarrow x^7=27.81\)

\(\Leftrightarrow x^7=2187\)

\(\Leftrightarrow x^7=3^7\)

\(\Leftrightarrow x=3\)

\(b.\)\(\frac{x^8}{9}=729\)

\(\Rightarrow x^8=729.9\)

\(\Leftrightarrow x^8=6561\)

\(\Leftrightarrow x^8=3^8\)

\(\Leftrightarrow x=3\)

Vậy : Ở cả 2 câu x đều bằng 3 nhé.

~ Rất vui vì giúp đc bn ~

\(\frac{x^7}{81}\) = 27

x⁷ : 81 = 27

x⁷        = 27 . 81 = 3³ . 3⁴

x⁷         = 3⁷

Suy ra : x = 3

Bài 2 :

   \(\frac{x^8}{9}\) = 729

x⁸ : 9     = 729

x⁸          =  729 . 9

x⁸          =     3⁶ . 3²

x⁸              =              3⁸

Suy ra : x = 3

â)\(\dfrac{x^7}{81}=27\Leftrightarrow x^7=27\times81=2187\Leftrightarrow x=3\)

b)\(\dfrac{x^8}{9}=729\Leftrightarrow x^8=729\times9=6561\Leftrightarrow x=3\)

a, \(\dfrac{x^7}{81}=27\)=> x⁷=27. 81=>x⁷=2187=>x=3

b, \(\dfrac{x^8}{9}=729\)=>x⁸=729. 9= 6561=>x=3 hoặc -3

\(\dfrac{x^7}{81}=27\)

\(\Rightarrow x^7=2187\)

\(\Rightarrow x=3\)

\(\dfrac{x^8}{9}=729\)

\(\Rightarrow x^8=6561\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

a) \(\dfrac{x^7}{81}=27\) => \(x^7=81.27=3^4.3^3=3^7\)=> \(x=3\)

b) \(\dfrac{x^8}{9}=729\)=> \(x^8=9.729=\)(\(\pm\)\(3^2\)).(\(\pm\)\(3^6\))=(\(\pm\)\(3^{^8}\)) => x = \(\pm\)3

a) \(\left(2x+3\right)^2=\frac{9}{144}\)

\(\Leftrightarrow\left(2x+3\right)^2=\left(\frac{1}{4}\right)^2=\left(-\frac{1}{4}\right)^2\)

\(\Rightarrow\orbr{\begin{cases}2x+3=\frac{1}{4}\\2x+3=\frac{-1}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=\frac{-11}{4}\\2x=\frac{-13}{4}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{-11}{8}\\x=\frac{-13}{8}\end{cases}}}\)

Vậy ...

b) Ta có: \(\left(3x-1\right)^3=\frac{-8}{27}=\left(\frac{-2}{3}\right)^3\)

\(\Leftrightarrow3x-1=\frac{-2}{3}\Leftrightarrow3x=\frac{1}{3}\Leftrightarrow x=\frac{1}{9}\)

Vậy ....

c) \(x^{10}=25x^8\Leftrightarrow x^{10}:x^8=25\Leftrightarrow x^2=25\Leftrightarrow x=\left\{5;-5\right\}\)

Vậy ...

d) \(\frac{x^7}{81}=27\Leftrightarrow x^7=27.81=2187\)

Mà 3⁷ = 2187 => x⁷ = 3⁷ => x = 3

Vậy ....

e) \(\frac{x^8}{9}=729\Leftrightarrow x^8=729.9=6561\)

Mà 3⁸ = (-3)⁸ = 6561

=> x⁸ = 3⁸ = (-3)⁸

=> x = {-3;3}

Vậy ...