a) \(\dfrac{x^7}{81}=27\) => \(x^7=81.27=3^4.3^3=3^7\)=> \(x=3\)
b) \(\dfrac{x^8}{9}=729\)=> \(x^8=9.729=\)(\(\pm\)\(3^2\)).(\(\pm\)\(3^6\))=(\(\pm\)\(3^{^8}\)) => x = \(\pm\)3
a) \(\dfrac{x^7}{81}=27\) => \(x^7=81.27=3^4.3^3=3^7\)=> \(x=3\)
b) \(\dfrac{x^8}{9}=729\)=> \(x^8=9.729=\)(\(\pm\)\(3^2\)).(\(\pm\)\(3^6\))=(\(\pm\)\(3^{^8}\)) => x = \(\pm\)3
tìm x biết
a)\(\dfrac{x^7}{81}=27\)
b)\(\dfrac{x^8}{9}=729\)
Tìm \(P=x.y.z\) biết x y z thỏa mãn
\(\dfrac{x^4y^3}{z=2018}\\ \dfrac{x^3z^4}{y=\dfrac{1}{2018}}\\ \dfrac{y^4z^3}{x=729}\)
\(\dfrac{\left(-3\right)^x}{81}\)=27
Tìm x biết : a)\(1-\dfrac{1}{2}.\left(\dfrac{3}{2}-2.x\right)=4.x-\dfrac{1}{4}\) b):\(x^{10}=1024\) c) 3x = 81
1,Tìm x,biết
a,\(\left(-1\dfrac{3}{5}+x\right)\div\dfrac{12}{13}=2\dfrac{1}{6}\)
b,\(\dfrac{-4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}\div\left(-1\dfrac{2}{3}\right)\)
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)
Tìm x; y biết:
a) \(\dfrac{x}{4}\)= \(\dfrac{y}{3}\)=\(\dfrac{2}{9}\) và x - 3y + 42 = 62
b) \(\dfrac{x}{y}\)=\(\dfrac{7}{9}\) và \(\dfrac{y}{z}\)= \(\dfrac{7}{3}\) và x - y + z = -15
c)\(\dfrac{x}{y}\)=\(\dfrac{7}{20}\); \(\dfrac{y}{z}\)=\(\dfrac{5}{8}\) và 2x + 5y - 2z =100
d) 5x = 8y = 20 và x-y-z = 3
e) \(\dfrac{6}{11}\) . x =\(\dfrac{2}{2}\). y =\(\dfrac{18}{5}\). z và (-x) +y + 2 = -120
f ) \(\dfrac{x}{12}\)=\(\dfrac{y}{9}\)=\(\dfrac{2}{5}\) và x . y . z =20
Tìm x biết:
a) \(x:\left(-\dfrac{1}{2}\right)^3=-\dfrac{1}{2}\); b) \(\left(\dfrac{3}{4}\right)^5.x=\left(\dfrac{3}{4}\right)^7\)
Nhờ mọi người giúp mình vs!
Tìm x thuộc Q khi:
a)3x-1 =243
b)\(\left(\dfrac{2}{3}\right)^{x+1}=\dfrac{8}{4}\)
c) 3x+3x+2=270
d) \(\left(x-\dfrac{5}{2}\right)^2=144\)
e) \(\left(2x+1\right)^3=\dfrac{215}{27}\)
f) (2x-1)5 = -243
h) (27-1)2 = (2x-1)2
i) (2x+1)2 + (x+1)10 = 0
k) \(\dfrac{x-2}{5}=\dfrac{X+3}{2}\)
l) \(\dfrac{2}{x}=\dfrac{x}{50}\)
m) \(\dfrac{\left(x-3\right)}{4}=\dfrac{4}{x+3}\)
n) \(|x+\dfrac{3}{5}|-|x-\dfrac{7}{3}|\)