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\(3^2x-4-x^0=8\)

9x-4-1=8

9x-5=8

9x=13

=>x=\(\frac{13}{9}\)

trả lời nhanh giúp tôi

a) (5x - 12 ) : 4 = 3¹⁸ : 3¹⁵

( 5x - 12 ) : 4 = 3³

( 5x - 12 ) : 4 = 27

5x - 12 = 108

5x = 120

x = 24

b) 5x³ - 10² = 35

5x³ - 100 = 35

5x³ = 135

x³ = 27

x³ = 3³

=> x = 3

c) 65 - 4^x+2 = 2018⁰

65 - 4^x+2 = 1

4^x+2 = 64

4^x+2 = 4³

x + 2 = 3

=> x = 1

d) 2^x+1 - 2^x = 32

2^x . ( 2 - 1 ) = 32

2^x . 1 = 32

2^x = 32

2^x = 2⁵

=> x = 5

e) 30 - [ 4( x - 2) + 15 ] = 3

4(x-2) + 15 = 27

4( x-2) = 12

x - 2 = 3

x = 5

f) 740 : ( x + 10 ) = 10² - 2.13

740 : ( x + 10 ) = 100 - 26

740 : ( x + 10 ) = 74

x + 10 = 10

x = 0

\(740:\left(x+10\right)=10^2-2.13\)

\(=>740:\left(x+10\right)=100-26\)

\(=>740:\left(x+10\right)=74\)

\(=>x+10=740:74\)

\(=>x+10=10\)

\(=>x=10-10\)

\(=>x=0\)

mik nhớ câu này vừa nãy bn hỏi r mà-_-

\(740:\left(x+10\right)=102-26\)

\(\Leftrightarrow740:\left(x+10\right)=76\)

\(\Leftrightarrow x+10=\dfrac{740}{76}\)

\(\Leftrightarrow x=-\dfrac{5}{19}\)

\(a,[\left(8.x-12\right):4].3^3.3=3^6.6\)

\(\left(8x-12\right):4=54\)

\(8x-12=216\)

\(8x=228\)

\(x=28,5\)

\(b,41-2^{x+1}=9\)

\(2^{x+1}=41-9\)

\(2^{x+1}=32\)

\(2^{x+1}=2^5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=4\)

=500-[1200-{36-26}²].1

=500-[1200-{10²}

=500-[1200-100}

=500-1100

=-600