giúp e với e camon
Giúp e b7 với ạ:) e camon
Giúp em với ạ e camon
Ex6
1 was
2 had been
3 found
4 had talked
5 had spoken
6 snowed
7 were
8 painted
9 had
10 had known
Ex7
2 had got
3 had hurt
4 were
5 were
6 was
7 wanted
8 ?
9 stopped
10 had eaten
mb giúp em và giải thích giúp e nx ạ e camon
9. is/ tells
10. are
11. has
12. isn't
--------
B3
1. is
2. teaches
3. learn
4. comes
5. has
6. goes
7. meets
8. drinks
------------
B4
1. plays
2. drink
3. starts
4. live
5. do
6. speak
7. watches
------------
B5
1. does -> do
2. Do -> Does
3. watch -> watches
4. goes -> go
5. carries -> carry
6. don't -> doesn't
7. plays -> play
8. are -> is
9. is/ tells.
10. are.
11. has.
12. isn't.
B3
1. is.
2. teaches.
3. learn.
4. comes.
5. has.
6. goes.
7. meets.
8. drinks.
B4
1. plays.
2. drink.
3. starts.
4. live.
5. do.
6. speak.
7. watches.
B5
1. does -> do.
2. Do -> Does.
3. watch -> watches.
4. goes -> go.
5. carries -> carry.
6. don't -> doesn't.
7. plays -> play.
8. are -> is.
Write around 120-140 words, write a paragraph giving your opinions of what make a person successful in life.
P/s: mn giúp e với ạ:) e camon.
giúp em vs ạ. e camon:)
MN ơi giúp e vs ạ ! Em camon .
Lm giúp e vs ạ, camon mn nhìu <3
giúp e nhanh bài này nhé ac e camon ac rất nhiều
tính nhanh
66 * ( 12-12)*(132*6+66)
66 * ( 12-12)*(132*6+66) = 66 x 0 x *(132*6+66) = 0
66 x ( 12 - 12 ) x ( 132 x 6 + 66 )
= 66 x 0 x ( 132 x 6 + 66 )
= 0
Ta thấy 12-12=0 Vậy =>Tích trên bằng 0
Giúo e vs E camon ạ
Vì tam giác ABH vuông tại H
\(\Rightarrow AH^2+x^2=AB^2\)
mà AH = 4,8 cm; AB = 6 cm
\(\Rightarrow4,8^2+x^2=6^2\) \(\Rightarrow23,04+x^2=36\) \(\Rightarrow x^2=36-23,04=12,96\) \(\Rightarrow x=3,6\left(cm\right)\)
Vì tam giác ACH vuông tại H
\(\Rightarrow AH^2+y^2=AC^2\)
mà AH = 4,8 cm; AC = 8 cm
\(\Rightarrow4,8^2+y^2=8^2\) \(\Rightarrow23,04+y^2=64\) \(\Rightarrow y^2=64-23,04=40,96\) \(\Rightarrow y=6,4\left(cm\right)\)
Vậy x = 3,6 cm; y = 6,4 cm
~~ Chúc bạn học tốt ~~
áp dụng định lí Py-ta-go vào \(\Delta\) vuông AHC, ta có:
\(AC^2=AH^2+HC^2\)
\(\Rightarrow\)\(HC^2=AC^2-AH^2\)
\(HC^2=8^2-4,8^2\)
\(HC^2=64-23,04\)
\(HC^2=40,96\)
\(\Rightarrow\)\(HC=\sqrt{40,96}=6,4\)
vậy \(y\)\(=\)\(6,4\)
Xét ΔAHB vuông tại H có
\(AH^2+HB^2=AB^2\)
\(\Leftrightarrow x^2=6^2-4.8^2=12,96\)
hay x=3,6(cm)
Xét ΔAHC vuông tại H có
\(AC^2=AH^2+y^2\)
\(\Leftrightarrow y^2=8^2-4.8^2=6.4^2\)
hay y=6,4(cm)