a) \(2^x+2^{x+3}=144\)

\(2^x\left(1+2^3\right)=144\)

\(2^x.9=144\)

\(2^x=144:9=16\)

=> \(2^x=2^4\Rightarrow x=4\)

b) \(2^{x-1}+5.2^{x-2}=224\)

\(2^{x-2}\left(2+5\right)=224\)

\(2^{x-2}.7=224\Rightarrow2^{x-2}=32\Rightarrow2^{x-2}=2^5\)

=> x - 2 = 5 => x = 7

a ) 2^x + 2^{x + 3} = 144
=> 2^x . ( 1 + 2³ ) = 144

=> 2^x . 9  = 144

=> 2^x = 16

=> 2^x = 2⁴

=> x = 4
Vậy x = 4

b ) 2^{x - 1}  + 5. 2^{x - 2} = 224

=> 2^{x - 2} . ( 2 + 5 ) = 224

=> 2^{x - 2} . 7 = 224

=> 2^{x - 2} =  32

=> 2^{x - 2} = 2⁵

=> x - 2 = 5

=> x = 7

Vậy x = 7

a) 

\(2^{x+3}+5\cdot2^{x+2}=224\)

\(2^x\cdot2^3+5\cdot2^x\cdot2^2=224\)

\(2^x\cdot8+2^x\cdot20=224\)

\(2^x\cdot\left(20+8\right)=224\)

\(2^x\cdot28=224\)

\(2^x=8\)

\(x=3\)

2^x+3+5*2^x+2 = 224

VT=7*2^x+2

pt trở thành 7*2^x+2=224

<=>7*2^x+2=2⁵*7

<=>2^x+2=2⁵

<=>x+2=5

<=>x=3

x=3 nhé

a) \(2^{x-1}+5\cdot2^{x-2}=224\)

\(2^x:2+5\cdot2^x:4=224\)

\(2^x\left(\frac{1}{2}+\frac{5}{4}\right)=224\)

\(2^x=128\)

\(x=7\)

b) \(5^{x-2017}+5^{x-2015}=650\)

\(5^{x-2015}\left(\frac{1}{25}+1\right)=650\)

\(5^{x-2015}=625\)

\(x=2019\)

c) \(2^x-2^y=256\left(x>y\right)\)

(ko biết)

giup mink ai nhanh tick 3 lan nghia la 1 lan tra loi mot lan noi lam rui mot lan noi cam on

a: \(2^7+\left(x-3^7\right)=5^7-4^7\)

=>\(128+x-2187=78125-16384\)

=>\(x-2059=61741\)

=>\(x=61741+2059=63800\)

c: \(7^2-\left(x+15\right)=5\cdot2^2\)

=>49-(x+15)=5*4=20

=>x+15=29

=>x=14

d: 7^3-7(13-x)=14

=>343-7(13-x)=14

=>7(13-x)=343-14=329

=>13-x=47

=>x=13-47=-34

Answer:

\(5.2^2+(x+3)=5^2\)

\(⇒5.4+x+3=25\)

\(⇒20+x+3=25\)

\(⇒(20+3)+x=25\)

\(⇒23+x=25\)

\(⇒x=2\)

\(3^2.2+(x+5)^2=10^2\)

\(⇒9.2+x+25=100\)

\(⇒x+43=100\)

\(⇒x=57\)

dễ tích mình rồi mình giải cho