A=1.2.3+2.3.4+...2016.2017.2017-2.3.4+.....2015.2016.2017

A=1.2017=2017 :D làm sai nhá

Trần Đức Hùng lần đầu t soi bài m Hùng xinh gái ak :>

\(A=1.2+2.3+3.4+4.5+...+2016.2017\)

\(3A=1.2.3+2.3.\left(4-1\right)+...+2016.2017.\left(2018-2015\right)\)

\(3A=1.2.3+2.3.4-1.2.3+...+2016.2017.2018-2015.2016.2017\)

\(3A=2016.2017.2018\Rightarrow A=\frac{2016.2017.2018}{3}\)

p/s: lần sau lèm cẩn thận nha bn iu dấu, để mấy em lớp 6 bt nhục mặt vl :D

cc ok nhé :D tú vụm

Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
 3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101  3S = 3.33.100.101 
 S=33.100.101= 333300

Đặt

S= 1.2 + 2.3 + 3.4 + ...+ 99.100  

3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3

3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)

3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100

3S = 99.100.101  3S = 3.33.100.101  

S=33.100.101= 333300

A=1.2+2.3+3.4+4.5+...+2014.2015

=>3A=1.2.3+2.3.3+3.4.3+4.5.3+...+2014.2015.3

=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+2014.2015.(2016-2013)

=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+2014.2015.2016-2013.2014.2015

=(1.2.3-1.2.3)+(2.3.4-2.3.4)+(3.4.5-3.4.5)+(4.5.6-4.5.6)+...+(2013.2014.2015-2013.2014.2015)+0.1.2+2014.2015.2016

=0+2014.2015.2016

=>A=\(\frac{2014.2015.2016}{3}\)

S = 1.2 + 2.3 + ... + 99.100

4S = 1.2.(3 - 0) + 2.3.(4 - 1) + ... + 99.100.(101 - 98)

4S = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 +...+ 99.100.101 - 98.99.100

4S = (1.2.3 + 2.3.4 +...+ 99.100.101) - (0.1.2 + 1.2.3 +...+ 98.99.100)

4S = 99.100.101 - 0.1.2

4S = 99.100.101

S = 99.25.101

S = 249975

\(S=1.2+2.3+3.4+4.5+5.6+...+99.100\)

\(3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3\)

\(3S=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+4.5.\left(6-3\right)+...+99.100.\left(101-98\right)\)\(1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101+98.99.100\)

\(3S=\left(1.2.3-1.2.3\right)+\left(2.3.4-2.3.4\right)+...+\left(98.99.100-98.99.100\right)+99.100.101\)

\(3S=99.100.101=9999000\)

\(S=9999000:3=3333000\)

\(\Rightarrow S=3333000\)

ta có \(3S=1\cdot2\cdot3+2\cdot3\cdot3+.....+99\cdot100\cdot3\)

\(3S=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)....+99\cdot100\cdot\left(101-98\right)\)

\(3S=1\cdot2\cdot3-1\cdot2\cdot3+2\cdot3\cdot4-......-98\cdot99\cdot100+99\cdot100\cdot101\)

\(3S=99.100.101\)

\(S=\frac{99\cdot100\cdot101}{3}\)

S=...

3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3

3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100

3S=99.100.101

S=33.100.101

S=333300

Vậy S=333300

( 99,1 - 1,2 ) : 1,1 + 1 = 90

S là :

( 99,1 + 1,2 ) x 90 : 2 = 4513,5

A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101

3.A = 1.2.3 + 2.3.3 +3.4.3 + ... + 100.101.3

3A= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 100.101.(102 - 99)

3A = 1.2.3 + 2.3.4 - 1.2.3 + 2.3.4 -3.4.5 + ... +99.100.101 -100.101.102

3A = 99.100.101

A = 99.100.101 : 3

A = 33.100.101

Vậy A = 33. 100 .101 (Tự tính)

A=1.2+2.3+3.4+.....+99.100+100.101

333300

246

A = 1.2 + 2.3 + 3.4 + ....... + 99.100

3A = 1.2.3 + 2.3.3 + 3.4.3 + ....... + 99 . 100 . 3

3A = 1.2.3 + 2.3.(4-1) + 3.4.(5-2)  +.... + 99.100.(101-98)

3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ..... + 99 . 100 . 101 - 98 . 99 . 100

3A = (1.2.3 - 1.2.3) + (2.3.4-2.3.4) + ... + (98.99.100 - 98.99.100) + 99  . 100 . 101

3A = 99 . 100 . 101 = 999900

A = 999900 : 3 = 333300

A=1*2+2*3+3*4+...+99*100

A=100*101*102:3

A=343400(công thức)

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