3/5 + 1/6 + 7/30 3/4 - 1/2 + 2/5
Mk đang cần gấp các bn giải giúp mk với!
1,62/7:x=29/9:3/56
2, 1/5:x=1/5-1/7
3,2/3.x-4/7=1/8
4,2/7-8/9.x=2/3
5,4/7+5/9:x=1/5
6,2/5-2/5.x=2/5
7,2/3+1/3:x=-1
các bn ơi giúp mk vs mk đang cần gấp mong các bn giúp đỡ mk mai mk pải nộp ruì
ai nhanh tay lm mk tick cho
\(a,\frac{62}{7}:x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}:x=\frac{1624}{27}\)
\(x=\frac{62}{7}:\frac{1624}{27}=\frac{837}{5684}\)
\(b,\frac{1}{5}:x=\frac{1}{5}-\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{2}{35}\)
\(x=\frac{1}{5}:\frac{2}{35}=\frac{7}{2}\)
\(c,\frac{2}{3}.x-\frac{4}{7}=\frac{1}{7}\)
\(\frac{2}{3}.x=\frac{1}{7}+\frac{4}{7}=\frac{5}{7}\)
\(x=\frac{5}{7}:\frac{2}{3}=\frac{15}{14}\)
\(d,\frac{2}{7}-\frac{8}{9}.x=\frac{2}{3}\)
\(\frac{8}{9}.x=\frac{2}{7}-\frac{2}{3}=-\frac{8}{21}\)
\(x=-\frac{8}{21}:\frac{8}{9}=-\frac{3}{7}\)
\(e,\frac{4}{7}+\frac{5}{9}:x=\frac{1}{5}\)
\(\frac{5}{9}:x=\frac{1}{5}-\frac{4}{7}=-\frac{13}{35}\)
\(x=\frac{5}{9}:-\frac{13}{35}=\frac{175}{117}\)
\(i,\frac{2}{5}-\frac{2}{5}.x=\frac{2}{5}\)
\(\frac{2}{5}.\left(1-x\right)=\frac{2}{5}\)
\(1-x=\frac{2}{5}:\frac{2}{5}=1\)
\(x=1-1=0\)
\(g,\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\frac{1}{3}:x=-1-\frac{2}{3}=-\frac{5}{3}\)
\(x=\frac{1}{3}:-\frac{5}{3}=-\frac{1}{5}\)
học tốt nha
Thực hiện phép tính
a,7/12-3/4.5/6
b,(2/1/3+1/3/4).12/13
c,12÷(3/4-5/6)2
d,7/22÷3/11+7/22:4/11
Các bn ơi giúp mk với mk cần gấp
a, 7/12 - 3/4 . 5/6
= 7/12 - 5/8
= 14/24- 15/24
= -1/24
b,( 2/1/3 + 1/3/4 ) . 12/13
= ( 6/3 + 7/3 ) . 12/13
= 13/3 . 12/13
=4
c, 12 : ( 3/4 -5/6 ) . 2
= 12 : ( -1/12 ) .2
= 12 . -12 . 2
= -228
d, 7/22 : 3/11 + 7/22 : 4/11
= 7/22 . 11/3 + 7/22 . 11/4
= 7/22 . ( 11/3 + 11/4 )
....
tiếp theo bạn tự làm nhé!
1+2+3+4+5+6+7+8+9=???
Giúp mk với mk đang cần gấp!!!
1+2+3+4+5+6+7+8+9
=(1+9)+(2+8)+(3+7)+(4+6)+5
=10+10+10+10+5
=10×4+5
=40+5
=45
Học tốt
= (1+9) + (2+8) + ( 3+7 ) + (4+6) + 5
= 10+10+10+10+5
= 10*4+5
=40+5
=45
=( 1+ 9) +( 2+8) +(3+ 7) +(4+ 6) + 5
=10 + 10 + 10 + 10 + 5
=10 x 4 + 5
=45
Các bn giúp mk với, mk đang cần gấp. Các bn giải chi tiết giúp mk nha.
Tìm số tự nhiên x lớn nhất thỏa mãn: 27 chia x dư 3; 38 chia x dư 2 và 49 chia x dư 1.
a,-8/3+7/5+-71/15<x<-13/7+19/14+-7/2
b,-19/6+-15/2+11/3<x<-5/4+19/12+-10/3
c,-6/7+3/35<x<-2/5+3/7
d,x=3/4+1/-12
e,x/14=1/7+-3/14
f,11/18+13/6=85/x
g,8/17+5/17<x/17<6/17+9/17
mong các bn giúp đỡ mk vs mk cần rát gấp
ai nhanh giúp mk thì mk tick cho 3 tick mk thề có lòng tự trọng
ai lm nhanh mk cho 10 tick lun nhanh nha đang cần gấp
các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
- \(\dfrac{19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}\) < \(x\) < - \(\dfrac{5}{4}\) + \(\dfrac{19}{12}\) - \(\dfrac{10}{3}\)
- \(\dfrac{32}{3}+\dfrac{11}{3}< x< \) \(\dfrac{1}{3}\) - \(\dfrac{10}{3}\)
-7 < \(x\) < - 3
Vì \(x\in\) Z nên \(x\in\) {-6;-5;-4}
1+2+3+....+199+20
3+5+7+.....+97+99
2+4+6+.......+98+10
Mong các bạn giải rõ ràng dùm mk với nha mk đang cần gấp chieu mk nộp rồi 😭😭😭😭
1 + 2 + 3 + ... + 199 + 200
Ta có : 1 + 2 + 3 + ... + 199 + 200 ( có 200 số )
= (200 + 1) x 200 : 2 = 20100
3 + 5 + 7 + ... + 97 + 99
Ta có : 3 + 5 + 7 + ... + 97 + 99 (có 49 số )
= (99 + 3) . 49 : 2 = 2499
A = 1 + 2 + 3 + ... + 199 + 20
A = ( 199 + 1 ) . 199 : 2 +20 = 19920
B = 3 + 5 + 7 +... + 97 + 99
có số số B là : ( 99 - 3 ) :2 + 1 = 49
B = ( 99 + 3 ) . 49 : 2 = 2499
có số số C là : ( 98 - 2 ) : 2 + 1 = 49
C = ( 98 + 2 ) . 49 : 2 = 2450
tìm x biết:
a)2/3x-3/2x=5/12
b)2/5+3/5.(3x-3,7)=-53/10
c)7/9:(2+3/4x)+5/9=23/27
d)-2/3.x+1/5=3/10
e)|x|-3/4=5/3
f)|2x-1/3|+5/6=1
giúp mik vs mik đang cần gấp bn nào giải mik cũng tick nha
giải hết giúp mik các bn nhé
a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)
(\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)
- \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)
\(x\) = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))
\(x=\) - \(\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)
3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)
3\(x\) - 3,7 = - \(\dfrac{19}{2}\)
3\(x\) = - \(\dfrac{19}{2}\) + 3,7
3\(x\) = - \(\dfrac{29}{5}\)
\(x\) = - \(\dfrac{29}{5}\) : 3
\(x\) = - \(\dfrac{29}{15}\)
Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\)
c; \(\dfrac{7}{9}\) : (2 + \(\dfrac{3}{4}\)\(x\)) + \(\dfrac{5}{9}\) = \(\dfrac{23}{27}\)
\(\dfrac{7}{9}\): (2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{23}{27}\) - \(\dfrac{5}{9}\)
\(\dfrac{7}{9}\):(2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{8}{27}\)
2 + \(\dfrac{3}{4}\)\(x\) = \(\dfrac{7}{9}\) : \(\dfrac{8}{27}\)
2 + \(\dfrac{3}{4}\)\(x\) = \(\dfrac{21}{8}\)
\(\dfrac{3}{4}x\) = \(\dfrac{21}{8}\) - 2
\(\dfrac{3}{4}\)\(x\) = \(\dfrac{5}{8}\)
\(x\) = \(\dfrac{5}{8}\) : \(\dfrac{3}{4}\)
\(x\) = \(\dfrac{5}{6}\)
Vậy \(x=\dfrac{5}{6}\)
Mk có mấy bài toàn cần các bạn giải giúp:
Câu 1: 4/3.7+4/7.11+4/11.15+4/15.19+4/19.23+4/23.27
Câu 2:3/14+3/84+3/204+3/374+3/594+3/864
Câu 3:1/10+1/40+1/88+1/154+1/238+1/340
Câu 4:37/7+37/91+37/247+37/475+37/775+37/1147
Câu 5:1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90+109/110
Mk đang cần gấp đề ko sai đâu nha thầy mk cho đấy
Nhớ giải cho mk trong thời gian sớm nhất nhoa
1.\(\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+\frac{4}{15.19}+\frac{4}{19.23}+\frac{4}{23.27}\)
\(=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{4}{23}-\frac{4}{27}\)
\(=\frac{1}{3}-\frac{1}{27}=\frac{9}{27}-\frac{1}{27}=\frac{8}{27}\)
2. Đặt \(A=\frac{3}{14}+\frac{3}{84}+\frac{3}{204}+\frac{3}{374}+\frac{3}{594}+\frac{3}{864}\)
\(\Rightarrow A=\frac{3}{2.7}+\frac{3}{7.12}+...+\frac{3}{27.32}\)
\(\Rightarrow5A=3.\left(\frac{5}{2.7}+\frac{5}{7.12}+...+\frac{5}{27.32}\right)\)
\(\Rightarrow5A=3.\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+...+\frac{1}{27}-\frac{1}{32}\right)\)
\(\Rightarrow5A=3.\left(\frac{1}{2}-\frac{1}{32}\right)\)
\(\Rightarrow5A=3.\frac{15}{32}=\frac{45}{32}\Rightarrow A=\frac{45}{32}:5=\frac{9}{32}\)
3. Đặt \(S=\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+...+\frac{1}{340}\)
\(\Rightarrow3S=\frac{3}{10}+\frac{3}{40}+...+\frac{3}{340}\)
\(\Rightarrow3S=\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{17.20}\)
\(\Rightarrow3S=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{17}-\frac{1}{20}\)
\(\Rightarrow3S=\frac{1}{2}-\frac{1}{20}=\frac{9}{20}\Rightarrow S=\frac{9}{20}:3=\frac{3}{20}\)
Câu 1:
\(\frac{4}{3.7}+\frac{4}{7.11}+\frac{4}{11.15}+\frac{4}{15.19}+\frac{4}{19.23}+\frac{4}{23.27}\)
\(\Rightarrow\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+\frac{1}{15}-\frac{1}{19}+\frac{1}{19}-\frac{1}{23}+\frac{1}{23}-\frac{1}{27}\)
\(\Rightarrow\frac{1}{3}-\frac{1}{27}\)
\(=\frac{8}{27}\)
Câu 1:
\(\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
Áp dụng tính chất \(\frac{b}{a\left[a+b\right]}=\frac{1}{a}-\frac{1}{a+b}\), ta có:
\(\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(=\frac{1}{3}-\frac{1}{27}=\frac{9}{27}-\frac{1}{27}=\frac{8}{27}\)
Câu 2 tương tự nhưng phải phân
\(\frac{3}{14}+\frac{3}{84}+\frac{3}{204}+...+\frac{3}{864}=\frac{3}{2\cdot7}+\frac{3}{7\cdot12}+\frac{3}{12\cdot17}+...+\frac{3}{27\cdot32}\)
Cái này áp dụng công thức \(\frac{a}{b\left[b+c\right]}=\frac{a}{c}\left[\frac{1}{b}-\frac{1}{b+c}\right]\), ta có:
\(\frac{3}{2\cdot7}+\frac{3}{7\cdot12}+\frac{3}{12\cdot17}+...+\frac{3}{27\cdot32}=\frac{3}{5}\left[\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{17}+...+\frac{1}{27}-\frac{1}{32}\right]\)
\(=\frac{3}{5}\left[\frac{1}{2}-\frac{1}{32}\right]=\frac{3}{5}\cdot\frac{15}{32}=\frac{9}{32}\)
Câu 3:
tương tự quy laautj mẫu là 2.5; 5.8 ....
Câu 4: qL mẫu là 1.7; 7.13; ....
Câu 5: \(=\left[1-\frac{1}{2}\right]+\left[1-\frac{1}{6}\right]+...+\left[1-\frac{1}{110}\right]\)
\(=\left[1-\frac{1}{1\cdot2}\right]+\left[1-\frac{1}{2.3}\right]+\left[1-\frac{1}{3\cdot4}\right]+...+\left[1-\frac{1}{10.11}\right]\)
\(=10-\frac{9}{10}=\frac{91}{10}\)
tính 1 2 3 4 5 6 7 8 9 10 11 12 ..... 2015 2016 giúp mk với đang cần gấp