a: \(=\dfrac{2^{13}\cdot5^7\left(2^{17}+5^{20}\right)}{2^{10}\cdot5^7\left(2^{17}+5^{20}\right)}=2^3\)

b: \(M=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}\)

\(=3^{2\cdot1\cdot13\cdot12}=3^{312}\)

\(36.\left(\frac{1}{1}-\frac{1}{3}-\frac{1}{5}+\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}-\frac{1}{29}\right).x=\frac{4}{25}\)

Triệt tiêu còn

\(36.\left(\frac{1}{1}-\frac{1}{29}\right).x=\frac{4}{25}\)

từ đây dễ rồi, tình lần lượt rồi tìm x nhé

\(15-\left\{2.\left[\left(2x-4\right).5\right].3.\left(x+1\right)\right\}=12-x\)

\(15-\left\{\left[10x-20\right].6.\left(x+1\right)\right\}=12-x\)

\(15-\left\{10x-20.6x+1\right\}=12-x\)

\(15-\left\{10x-120x+1\right\}=12-x\)

\(15-\left(-110x\right)-1=12-x\)

\(15+110x-1=12-x\)

\(110x+x=12-15+1\)

\(111x=-2\)

\(x=\dfrac{-2}{111}\)

a.15-(5-2x)=-4

\(\Leftrightarrow\)15-5+2x=-4

\(\Leftrightarrow\)2x=-4-15+5

\(\Leftrightarrow\)2x=-14

\(\Leftrightarrow\)x=-7

b.TH1:x-3\(\ge\)0 \(\Rightarrow\)x\(\ge\)3

Ta có \(|\)x-3\(|\)=x-3

PT trên\(\Leftrightarrow\)x-3+1=4

             \(\Leftrightarrow\)x=4+3-1

            \(\Leftrightarrow\)x=6(nhận)

TH2:x-3<0\(\Leftrightarrow\)x<3

Ta có:\(|\)x-3\(|\)=-x+3

PT trên\(\Leftrightarrow\)-x+3+1=4

                       -x=4-3-1

                       x=0(nhận)

Vậy S={0;6}

chỗ 100000 là 1000000000000000000.mười tám chữ số 0

\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}=\frac{2.2.2.5.7.5.5.7.7.7}{2.5.7.7.2.5.7.7}=\frac{2.5}{1}=10\)

Ko biết có đúng ko

\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}=\frac{2^3.\left(5.5^2\right).\left(7.7^3\right)}{2^2.5^2.7^{2^2}}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=2.5=10\)

Đặt A=\(\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)

A=\(\dfrac{2^3.5.7.5^2.7^3}{2^2.5^2.7^4}\)

A=\(\dfrac{2^3.5^3.7^4}{2^2.5^2.7^4}\)

A=2.\(5^2\)

A=2.25

A=50

B=(2/5)⁷.5⁷+(9/4)³:(3/16)³/2⁷.5²+512

B=(2/5.5)⁷+(9/4:3/16)³/2⁷.25+512

B=2⁷+12³/2⁷.25+512

B=1856/3200+512

B=1856/3712

B=1/2

\(B=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3}{2^7\cdot5^2+2^9}\)

\(=\dfrac{1+12^3}{2^7\left(5^2+2^2\right)}=\dfrac{\left(12+1\right)\left(12^2-12+1\right)}{2^7\cdot29}\)

\(=\dfrac{13\cdot133}{2^7\cdot29}=\dfrac{1729}{3712}\)

E = \(\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=\frac{2^2.2.5^2.5.7^4}{2^2.5^2.7^4}=2.5=10\)

\(E=\frac{2^3.5.7.5^2.7^3}{2^2.5^2.7^4}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=2.5=10\)

E=\(\frac{2^3.5.7.5^2.7^3}{2^2.5^27^4}=>E=\frac{2^3.5^3.7^4}{2^2.5^27^4}=>E=2.5=10\)10