\(2\frac{2}{3}\div\left\{\left[\left(3,72-0,02\times x\right)\frac{10}{37}\right]\div\frac{5}{6}+2,8\right\}-\frac{7}{15}=0,2\)
Những câu hỏi liên quan
\(\left(2\frac{1}{3}+3,5\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+75\%\)\(\left(-6\frac{3}{5}\div6-8\times12,5\%-\frac{2}{15}\div0,3\right)\times\left(-0,5\right)+1\)\(\left(2\frac{1}{3}+3\frac{1}{2}\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+2\frac{15}{43}\)
\(\frac{\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right)\div\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)}{\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)\div\left(\frac{1}{4}-\frac{1}{6}\right)}\)
25 tháng 8 2020 lúc 9:38
\(4\times\left(\frac{1}{4}\right)^2+25\times\left[\left(\frac{3}{4}\right)^3\div\left(\frac{5}{4}\right)^3\right]\div\left(\frac{3}{2}\right)^3\)
\(2^3+3\times\left(\frac{1}{2}\right)^0-1+\left[\left(-2\right)^2\div\frac{1}{2}\right]-8\)
\(4.\left(\frac{1}{4}\right)^2+25\left[\left(\frac{3}{4}\right)^3:\left(\frac{5}{4}\right)^3\right]:\left(\frac{3}{2}\right)^3=4.\frac{1}{16}+25\left(\frac{27}{64}.\frac{64}{125}\right).\frac{8}{27}\)
\(=\frac{1}{4}+25.\frac{27}{125}.\frac{8}{27}=\frac{1}{4}+\frac{8}{5}=\frac{37}{20}\)
\(2^3+3\left(\frac{1}{2}\right)^0-1+\left[\left(-2\right)^2:\frac{1}{2}\right]-8=8+3-1+4.2-8=10\)
tìm x biết
\(\left[\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right).2,8+1,75\right]:0,05=235\)
\(\left[\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8+1,75\right]:0,05=235\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8+1,75=11,75\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8=10\)
\(\Leftrightarrow\left(6\frac{3}{7}-\frac{0,75x-2}{0,35}\right)\cdot2,8=10\)
\(\Leftrightarrow6\frac{3}{7}-\frac{0,75x-2}{0,35}=\frac{25}{7}\)
\(\Leftrightarrow\frac{0,75x-2}{0,35}=\frac{20}{7}\)
\(\Leftrightarrow0,75x-2=1\)
\(\Leftrightarrow0,75x=3\)
\(\Leftrightarrow x=4\)
Vậy \(x=4\)
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Tính:
\(\left(-2\frac{1}{5}\right)\times\left(\frac{-9}{11}\right)\times\left(-1\frac{1}{14}\right)\times\frac{2}{5}+\left(\frac{-4}{7}+\frac{6}{11}\right)\div\)\(\frac{-3}{5}\)
\(=\frac{11}{-5}\cdot\frac{-9}{11}\cdot\frac{15}{-14}\cdot\frac{2}{5}+-\frac{2}{77}\cdot\frac{5}{-3}\)
\(=\frac{9}{5}\cdot-\frac{15}{14}\cdot\frac{2}{5}+\frac{10}{231}\)
\(=-\frac{841}{1155}\)
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\frac{\left(\frac{2}{5}\right)^7\times 5^{7\:}+\left(\frac{9}{4}\right)^3\div \left(\frac{3}{16}\right)^3}{2^7\times 5^2+512}
tìm\(x\in z\)biết :
a.\(\frac{13}{15}-\left(\frac{13}{21}+x\right)\times\frac{7}{12}=\frac{7}{10}\)
b.\(\left(x+\frac{1}{4}-\frac{1}{3}\right)\div\left(2+\frac{1}{6}-\frac{1}{4}\right)=\frac{7}{46}\)
Tính : a) \(\frac{1}{9}\div\frac{8}{27}\times-3\div\frac{81}{128}\)
b) \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\times230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Tính
1) (frac{55}{3}div15+frac{26}{3}timesfrac{7}{2})div[(frac{37}{3}+frac{62}{7})timesfrac{7}{18}]divfrac{-1704}{445}
2) (frac{1771}{25}div23)divfrac{77}{10}+11,45-(2,225-frac{11}{8})]timesfrac{8}{55}
3) [frac{109}{6}-left(0,06divfrac{15}{2}+frac{17}{5}times0,38right)]divleft(19-frac{8}{3}timesfrac{19}{4}right)
Đọc tiếp
Tính
1) \((\)\(\frac{55}{3}\)\(\div\)15+\(\frac{26}{3}\)\(\times\)\(\frac{7}{2}\)\()\)\(\div\)\([(\)\(\frac{37}{3}+\frac{62}{7})\times\frac{7}{18}]\div\frac{-1704}{445}\)
2) (\(\frac{1771}{25}\div23)\div\frac{77}{10}+11,45-(2,225-\frac{11}{8})]\times\frac{8}{55}\)
3) \([\frac{109}{6}-\left(0,06\div\frac{15}{2}+\frac{17}{5}\times0,38\right)]\div\left(19-\frac{8}{3}\times\frac{19}{4}\right)\)
1) ( \(\frac{55}{3}\): 15 + \(\frac{26}{3}\) . \(\frac{7}{2}\)) : [(\(\frac{37}{3}\) + \(\frac{62}{7}\)) . \(\frac{7}{18}\)] : \(\frac{-1704}{445}\)
= ( \(\frac{55}{3}\). \(\frac{1}{15}\) + \(\frac{91}{3}\)) : [ \(\frac{445}{21}\) . \(\frac{7}{18}\)] . \(\frac{-445}{1704}\)
= ( \(\frac{11}{9}\)+ \(\frac{91}{3}\)) : \(\frac{445}{54}\). \(\frac{-445}{1704}\) = \(\frac{284}{9}\). \(\frac{54}{445}\). \(\frac{-445}{1704}\)= \(\frac{284}{9}\). (\(\frac{54}{445}\). \(\frac{-445}{1704}\))
= \(\frac{284}{8}\). \(\frac{-9}{284}\)
= \(\frac{-9}{8}\)
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