Question

Tính

1) \((\)\(\frac{55}{3}\)\(\div\)15+\(\frac{26}{3}\)\(\times\)\(\frac{7}{2}\)\()\)\(\div\)\([(\)\(\frac{37}{3}+\frac{62}{7})\times\frac{7}{18}]\div\frac{-1704}{445}\)

2) (\(\frac{1771}{25}\div23)\div\frac{77}{10}+11,45-(2,225-\frac{11}{8})]\times\frac{8}{55}\)

3) \([\frac{109}{6}-\left(0,06\div\frac{15}{2}+\frac{17}{5}\times0,38\right)]\div\left(19-\frac{8}{3}\times\frac{19}{4}\right)\)

Answer 1

1) ( \(\frac{55}{3}\): 15 + \(\frac{26}{3}\) . \(\frac{7}{2}\)) : [(\(\frac{37}{3}\) + \(\frac{62}{7}\)) . \(\frac{7}{18}\)] : \(\frac{-1704}{445}\)

= ( \(\frac{55}{3}\). \(\frac{1}{15}\) + \(\frac{91}{3}\)) : [ \(\frac{445}{21}\) . \(\frac{7}{18}\)] . \(\frac{-445}{1704}\)

= ( \(\frac{11}{9}\)+ \(\frac{91}{3}\)) : \(\frac{445}{54}\). \(\frac{-445}{1704}\) = \(\frac{284}{9}\). \(\frac{54}{445}\). \(\frac{-445}{1704}\)

= \(\frac{284}{9}\). (\(\frac{54}{445}\). \(\frac{-445}{1704}\))

= \(\frac{284}{8}\). \(\frac{-9}{284}\)

= \(\frac{-9}{8}\)