a>
\(x+2617\cdot5=22219\)(. là x)
\(b>\left(x-9587\right):8=1415\)
Những câu hỏi liên quan
A=\(\dfrac{2^{30}\cdot5^7+3^{13}\cdot5^{27}}{2^{27}\cdot5^7+2^{10}\cdot5^{27}}\)
M=\(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}\) tại x=7
a: \(=\dfrac{2^{13}\cdot5^7\left(2^{17}+5^{20}\right)}{2^{10}\cdot5^7\left(2^{17}+5^{20}\right)}=2^3\)
b: \(M=\left(7-4\right)^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}\)
\(=3^{2\cdot1\cdot13\cdot12}=3^{312}\)
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Tìm x:
a,\(15-\left(5-2x\right)=-4\)
b,\(\left|x-3\right|+1=4\)
c,\(5^x\cdot5^{x+1}\cdot5^{x+2}=10000000\div2^{18}\)
a.15-(5-2x)=-4
\(\Leftrightarrow\)15-5+2x=-4
\(\Leftrightarrow\)2x=-4-15+5
\(\Leftrightarrow\)2x=-14
\(\Leftrightarrow\)x=-7
b.TH1:x-3\(\ge\)0 \(\Rightarrow\)x\(\ge\)3
Ta có \(|\)x-3\(|\)=x-3
PT trên\(\Leftrightarrow\)x-3+1=4
\(\Leftrightarrow\)x=4+3-1
\(\Leftrightarrow\)x=6(nhận)
TH2:x-3<0\(\Leftrightarrow\)x<3
Ta có:\(|\)x-3\(|\)=-x+3
PT trên\(\Leftrightarrow\)-x+3+1=4
-x=4-3-1
x=0(nhận)
Vậy S={0;6}
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chỗ 100000 là 1000000000000000000.mười tám chữ số 0
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\(\left(x\cdot5\right)+\left(x\cdot5\right)=25\)
\(\left(5.x\right)+\left(x.5\right)=25\)
\(\Leftrightarrow10x=25\)
\(\Leftrightarrow x=\frac{5}{2}\)
Vậy \(x=\frac{5}{2}\)
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1. Tìm xa) 2^x+521b) 2^x-1+3^25^2+2cdot5c) left(2x-1right)^3+5130d) 5^{2x-3}-2cdot5^25^2e) 3^{2x+1}-23^2+left[5^2-3left(2^2-1right)right]f) left(7^x-11right)^32^5cdot5^2+200g) 2cdot3^x10cdot3^{12}+8cdot27^4
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1. Tìm x
a) \(2^x+5=21\)
b) \(2^x-1+3^2=5^2+2\cdot5\)
c) \(\left(2x-1\right)^3+5=130\)
d) \(5^{2x-3}-2\cdot5^2=5^2\)
e) \(3^{2x+1}-2=3^2+\left[5^2-3\left(2^2-1\right)\right]\)
f) \(\left(7^x-11\right)^3=2^5\cdot5^2+200\)
g) \(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
a) \(2^x+5=21\)
\(\Rightarrow2^x=21-5=16\Rightarrow2^x=2^4\)
Vậy x = 4
b) \(2^x-1+3^2=5^2+2.5\)
\(\Rightarrow2^x-1+9=35\)
\(\Rightarrow2^x=35-9+1=27\)
Vậy x không có giá trị
c;d;e;f làm tương tự
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Bài 2 : Tìm x , biết :
a, \(\left(19x+2\cdot5^2\right)\text{ : }14=\left(13-8\right)^2-4^2\)
b, \(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
c, \(11-\left(-53+x\right)=97\)
d, \(-\left(x+84\right)+213=-16\)
e, \(13-12+11+10-9+8-7-6+5-4+3+2-1=x\)
\(a,\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=9\)
\(\Leftrightarrow19x+50=126\)
\(\Leftrightarrow19x=76\Leftrightarrow x=4\)
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b) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 30 ) = 1240
x + x + 1 + x + 2 + ... + x + 30 = 1240
( x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240
Số số hạng là : ( 30 - 1 ) : 1 + 1 = 30 ( số )
Tổng là : ( 30 + 1 ) . 30 : 2 = 465
=> 31x + 465 = 1240
=> 31x = 775
=> x = 25
Vậy........
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c) 11 - ( -53 + x ) = 97
11 + 53 - x = 97
64 - x = 97
x = 64 - 97
x = -33
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Xem thêm câu trả lời
Tìm STN x biết rằng:
a)\(720:[41-\left(2x-5\right)]=2^3\cdot5\)
b)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5+50\)
d)\(\left(x+3\right)^{10}=\left(x-3\right)^{17}\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:20\)
\(41-\left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x=23+5\)
\(x=28:2=14\)
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Bài 1: Tìm n1/4*2/6*3/8*4/10*5/12*.....* 30/62*31/642^nBài 2: Tínha) frac{left(-5right)^{60}cdot30^5}{15^5cdot5^{61}} b)2^3+3cdotleft(frac{1}{3}right)^0-2^{-2}cdot4+left[left(-2right)^3:frac{1}{2}right]cdot8(GỢI Ý CÂU B:^{2^{-2}frac{1}{2^2}}Bài 3: Tìm xa)^{2^x16}b)^{left(frac{x}{13}right)^2frac{49}{169}}c)left(frac{-1}{5}right)^xleft(frac{-1}{125}right)^3cdot x^4frac{-16}{625}d)^{6^{4-x}216}Bài 4:Tìm na)3^ncdot3^{-2}3^5b)Tìm x:1)frac{2^{4-x}}{16^5}32^62)^{9cdot5^x6cdot5^6+3cdot5^6}3)frac{2^3}{2...
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Bài 1: Tìm n
1/4*2/6*3/8*4/10*5/12*.....* 30/62*31/64=2^n
Bài 2: Tính
a) \(\frac{\left(-5\right)^{60}\cdot30^5}{15^5\cdot5^{61}}\)
b)\(2^3+3\cdot\left(\frac{1}{3}\right)^0-2^{-2}\cdot4+\left[\left(-2\right)^3:\frac{1}{2}\right]\cdot8\)
(GỢI Ý CÂU B:\(^{2^{-2}=\frac{1}{2^2}}\)
Bài 3: Tìm x
a)\(^{2^x=16}\)
b)\(^{\left(\frac{x}{13}\right)^2=\frac{49}{169}}\)
c)\(\left(\frac{-1}{5}\right)^x=\left(\frac{-1}{125}\right)^3\cdot x^4=\frac{-16}{625}\)
d)\(^{6^{4-x}=216}\)
Bài 4:Tìm n
a)\(3^n\cdot3^{-2}=3^5\)
b)Tìm x:
1)\(\frac{2^{4-x}}{16^5}=32^6\)
2)\(^{9\cdot5^x=6\cdot5^6+3\cdot5^6}\)
3)\(\frac{2^3}{2^x}=4^5\)
Các bạn giúp mik!!!Mik sắp kiểm tra 45p r
Tìm \(x\in N\)
a)\(\left(157-3x\right)\cdot5^7=4\cdot5^9\)
b)\(\left(170-6x\right)\cdot7^8=2\cdot7^{10}\)
a) (157 - 3x).57 = 4.59
157 - 3x = 4.59:57
157 - 3x = 22.52
157 - 3x = 100
3x = 157 - 100
3x = 57
x = 19
b) (170 - 6x).78 = 2.710
170 - 6x = 2.710:78
170 - 6x = 2.72
170 - 6x = 98
6x = 170 - 98
6x = 72
x = 72:6
x = 12
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a) => (157 - 3x) = 4 . 52 = 100
=> 3x = 157 - 100 = 57
=> x = 57 : 3 = 19
b) => (170 - 6x) = 2 . 72 = 98
=> 6x = 170 - 98 = 72
=> x = 72 : 6 = 12
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1: \(15-\left\{2\cdot\left[x-\left(2x-4\right)\cdot5\right]\cdot3\cdot\left(x+1\right)\right\}=12-x\)
\(15-\left\{2.\left[\left(2x-4\right).5\right].3.\left(x+1\right)\right\}=12-x\)
\(15-\left\{\left[10x-20\right].6.\left(x+1\right)\right\}=12-x\)
\(15-\left\{10x-20.6x+1\right\}=12-x\)
\(15-\left\{10x-120x+1\right\}=12-x\)
\(15-\left(-110x\right)-1=12-x\)
\(15+110x-1=12-x\)
\(110x+x=12-15+1\)
\(111x=-2\)
\(x=\dfrac{-2}{111}\)
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