Giúp mk làm vs ạ mk đang cần gấp
Mn làm nhanh giúp mk vs ạ mk đang cần gấp
Làm bài 8 giúp mk vs, mk đang cần gấp ạ
Giúp mình vs an, mk đang cần gấp ạ. Xin đừng làm tất ạ
\(a,=\dfrac{4xy-1-2xy+1}{5x^2y}=\dfrac{6xy}{5x^2y}=\dfrac{6}{5x}\\ b,=\dfrac{x^2+8x-2x+8}{x\left(x-4\right)\left(x+4\right)}=\dfrac{\left(x+2\right)\left(x+4\right)}{x\left(x-4\right)\left(x+4\right)}=\dfrac{x+2}{x\left(x-4\right)}\\ c,=\dfrac{x^2+3x-x+1}{x\left(x+1\right)\left(x-1\right)}=\dfrac{\left(x+1\right)^2}{x\left(x-1\right)\left(x+1\right)}=\dfrac{x+1}{x\left(x-1\right)}\\ d,=\dfrac{x-3-x-3-2x}{\left(x-3\right)\left(x+3\right)}=\dfrac{-2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{2}{3-x}\\ e,=\dfrac{x+1-1}{x+1}=\dfrac{x}{x+1}\\ f,=\dfrac{3x+5-5+9x}{6x^2y}=\dfrac{12x}{6xy}=\dfrac{2}{y}\)
\(g,=\dfrac{x^2+6x-2x+4}{x\left(x+2\right)\left(x-2\right)}=\dfrac{\left(x+2\right)^2}{x\left(x+2\right)\left(x-2\right)}=\dfrac{x+2}{x\left(x-2\right)}\\ h,=\dfrac{3x+1-3x+1+2x-3}{\left(3x-1\right)\left(3x+1\right)}=\dfrac{2x-1}{\left(3x-1\right)\left(3x+1\right)}\\ j,=\dfrac{5x+30+x^2-30}{x\left(x+6\right)}=\dfrac{x^2+5x}{x^2+6x}\\ k,=\dfrac{\left(x-7\right)\left(x+7\right)}{2x+1}\cdot\dfrac{-3}{x-7}=\dfrac{-3\left(x+7\right)}{2x+1}\\ l,=\dfrac{x\left(3x-2\right)}{x^2-1}\cdot\dfrac{\left(x^2+1\right)\left(x^2-1\right)}{\left(3x-2\right)^3}=\dfrac{x\left(x^2+1\right)}{\left(3x-2\right)^2}\)
giúp mk vs ạ, mk đang cần gấp ạ
a: Xét ΔADM và ΔCBN có
AD=CB
\(\widehat{DAM}=\widehat{BCN}\)
AM=CN
Do đó: ΔADM=ΔCBN
Suy ra: DM=BN
Giúp mk vs mk đang cần gấp ạ
giúp mk vs ạ mk đang cần gấp
giúp mk vs ạ mk đang cần gấp
Giúp mk vs mk đang cần gấp ạ
41. have been used
42. making
43. driving
44. be finished
45. to post
46. mending
47. is being sung
48. work
49. were blown
50. do
51. will
52. were reading
53. has bought
54. listening
55. stopped
56. is spoken
57. to practice
Giúp mk vs ạ! Mk đang cần gấp