\(\frac{4^7.8^3}{2^{20}}\)
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\(\frac{4^7.8^3}{2^{20}}\)
giúp mk vs nhe
Rút gọn rồi tính:
\(\frac{2^{15}.9^4}{6^7.8^3}\)
Bài làm :
Ta có :
\(\frac{2^{15}.9^4}{6^7.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^7.3^72^9}=\frac{3}{2}\)
Bài làm :
\(\frac{2^{15}.9^4}{6^7.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)
\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)
\(=\frac{3}{2}\)
Học tốt nhé
\(\frac{2^{15}.9^4}{6^7.8^3}\)\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)\(=\frac{2^{15}.3^8}{2^{16}.3^7}\)\(=\frac{1.3^1}{2^1.1}\)\(=\frac{3}{2}\)
CHÚC BẠN HỌC TỐT
Help me! I can't do this. It's very difficult.
\(\frac{\left(4^3\right)^2.9^4}{6^7.8^2}\)
Tính
M = 7.8+8.9+9.10+...+19.20
CMR: \(\dfrac{1}{2^2}+\dfrac{1}{3^2}+...+\dfrac{1}{20^2}< 1\)
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)\(=\frac{7.512-5.1024}{\left(-256\right)}\)\(=\frac{3583-5120}{\left(-256\right)}\)\(=\frac{1537}{256}\)
Mình học hơi kém nếu sai mong mn đừng gạch đá .
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1) Tính:
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)
2)Tìm x:
a)\(\frac{108}{12}\le x\le\frac{91}{7}\)
b)\(\frac{-28}{4}\le x\le\frac{-21}{7}\)
1)
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)
= \(\frac{7.2^8.2-5.2^8.2^2}{16^2}\)
= \(\frac{2^8.\left(2.7-5.2^2\right)}{2^8}\)
= \(\frac{2^8.\left(-6\right)}{2^8}\)
= \(-6\)
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2)
b)\(\frac{-28}{4}\le x\le\frac{-21}{7}\)
\(\Rightarrow-7\le x\le-3\)
\(\Rightarrow x=\left\{-7;-6;-5;-4;-3\right\}\)
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2)
a)\(\frac{108}{12}\le x\le\frac{91}{7}\)
\(\Rightarrow9\le x\le13\)
\(\Rightarrow x=\left\{9;10;11;12;13\right\}\)
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Xem thêm câu trả lời
1) 1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
2) \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
3)13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 -4 +3 +2 -1
Câu 1 dễ mà :
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.9 - 1.2.3...8.1 - 1.2.3...7.8.8
= 1.2.3...8.( 9 - 1 - 8 )
= 1.2.3...8.0
= 0
còn câu 2 và 3 thì sao
K ghi lại đề câu 2 nha :
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{35}.2}\)
\(=\frac{3^2.2^{36}}{2^{35}\left(11-2\right)}\)
\(=\frac{3^2.2^{36}}{2^{35}.3^2}\)
\(=\frac{3^2}{3^2}.\frac{2^{36}}{2^{35}}\)
\(=1.2=2\)
Xem thêm câu trả lời
Tính B = \(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)+ (2,15 *4 + 2,12 *5 )\(^0\)
Tính nhanh, biết
a) \(A=\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}-\frac{1}{8.9}-\frac{1}{9.10}\)
b) \(B=1+\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{49}-\frac{1}{50}\)
\(A=\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}-\frac{1}{8.9}-\frac{1}{9.10}\)
A= 1/3 + 1/4-1/4+1/5-1/5+1/6-1/6+1/7-1/7+1/8-1/8+1/9-1/9+1/10
A=1/3+1/10
A=13/30
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a,\(A=\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-....-\frac{1}{8.9}-\frac{1}{9.10}\)
\(=\frac{1}{12}-\left(\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{8.9}+\frac{1}{9.10}\right)\)
\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{12}-\frac{1}{4}+\frac{1}{10}=\frac{5}{60}-\frac{15}{60}+\frac{6}{60}=\frac{-1}{15}\)
Vậy \(A=\frac{-1}{15}\)
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