a) (3x-12) :8 +10= 13

<=> (3x-12):8 = 13-10 = 3

<=> 3x-12 = 3 .8 = 24

<=> 3x = 24+12=36

<=> x=36:3=12

b) (x+5).8-20 = 60

<=> (x+5) .8 = 60+20=80

<=> x+5 = 80:8 = 10

<=> x=10-5 = 5

c) 3.[35+(x-10)]-375 = 0

<=> 3.[35+(x-10)] = 0 +375=375

<=> 35+(x-10) = 375 :3 = 125

<=> x-10 = 125-35=90

<=> x = 90+10 = 100

d) ( 158x+173-24) :35 = 81

<=> 158x+149 = 81 . 35 = 2835

<=> 158x = 2835 -149= 2686

<=> x= 2686 : 158 = 17

e) x - 140 : 35 = 0

<=> x-4 = 0

<=> x=0+4 = 4

(3x - 12 ) : 8 + 10 = 13 

(3x - 12 ) : 8 = 13 - 10 = 3

(3x - 12 ) = 3 x 8 = 24

3x = 24 - 12 = 12

x =13 : 3 = 4

( x + 5 ) 

dài quá ko làm nha!!!

1)\(\left(x-280\right):35=56.5\)

\(\left(x-280\right):35=280\)

\(x-280=280.35\)

\(x-280=9800\)

\(x=9800+280\)

\(x=10080\)

2) \(\left(x-128+20\right):192=0\)

\(\Rightarrow\left(x-148\right):192=0\)

\(\Rightarrow x-148=0\)

\(\Rightarrow x=0+148\)

\(\Rightarrow x=148\)

3) \(460+85.4=\left(x+200\right).4\)

\(\Rightarrow\left(x+200\right).4=460+340\)

\(\Rightarrow\left(x+200\right).4=800\)

\(\Rightarrow x+200=800:4=200\)

\(\Rightarrow x+200=200\)

\(\Rightarrow x=200-200=0\)

4) \(x+5.2-\left(32+16.3:16-15\right)=0\)

\(\Rightarrow x+10-\left(32+3-15\right)=0\)

\(\Rightarrow x+10-20=0\)

\(\Rightarrow x+10=20\)

\(\Rightarrow x=20-10=10\)

nha m.n

ta có

x = { 15 ; 3750 ; -7 ; 0 }

 giải 

x- 20 = 35          x: 25 = 150                  x + 19 = 12                x*0=0

x= 35 + 20           x= 150 * 25                C = ∅                         x= 0

x= 55                      x= 3750                                                     D ={ 0}

A={55}                    B={ 3750 }

Nếu nói đến số tự nhiên chứ không phải số âm ở X+19=12 thì chỉ có ba phần tử:

X = { 55 ; 3625 ; 0 }

Đáp án C

Nếu có T → ADN ; có U → ARN

Nếu G=X; A=T hoặc A=U → Mạch kép ; còn lại mạch đơn

C sai

a/ (3x -12 ):8+10=13

 <=>(3x-12):8=3

<=>3x-12=24

<=>3x=36

<=>x=12

b/(x+5)x8-20=60

<=>(x+5)x8=80

<=>x+5=80:8

<=>x+5=10

x=5

c/3x[35+(x-10)]-375=0

<=>3x[35+(x-10)]=375

<=>35+(x+10)=125

<=>x+10=90

x=80

d/(158x+173-24):35=81

<=>158x+173-24=2835

<=>158x+173=2859

<=>158x=2686

<=>x=17

e/x-140:35=0

<=>x-140=0

<=>x=140+0

x=140

a)  ( 3x - 12 ) : 8 + 10 = 13

=>  (3x - 12) : 8 = 3

=>  3x - 12 = 24

=> 3x = 12

=> x = 4

a)  ( 3x - 12 ) : 8 + 10 = 13

=>  (3x - 12) : 8 = 3

=>  3x - 12 = 24

=> 3x = 12

=> x = 4

1. \(x^2+2x-15=0\)

\(\Rightarrow x^2+2x+1^2-16=0\)

\(\Rightarrow\left(x+1\right)^2=16\)

\(\Rightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\).

2. \(x^2-7x-44=0\)

\(\Rightarrow x^2-2.x.\dfrac{7}{2}+\dfrac{49}{4}-\dfrac{49}{4}-44=0\)

\(\Rightarrow\left(x-\dfrac{7}{4}\right)^2=\left(\dfrac{15}{2}\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{7}{4}=\dfrac{15}{2}\\x-\dfrac{7}{4}=-\dfrac{15}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{37}{4}\\x=\dfrac{-23}{4}\end{matrix}\right.\).

3.4 Tương tự.

2) hãy dành 5(s)

\(x^2-7x-44=0\Rightarrow\left(x^2+4x\right)-\left(11x+44\right)=0\)

\(x\left(x+4\right)-11\left(x+4\right)=0\)

\(\left(x+4\right)\left(x-11\right)=0\)\(\left[{}\begin{matrix}x=-4\\x=11\end{matrix}\right.\)