Tính nhanh : 2022 : 0,25 + 2022 : 0,1 - 2022 : 0,5 + 2022 : 1/6
tính nhanh: ( 2022 x 0,75 + 2022 : 4) - ( 2021 : 0,1 : 10}
A = ( 2022 x 0,75 + 2022 : 4) - ( 2021 : 0,1 : 10)
= (2022 x 0,75 + 2022 x 0,25) - ( 2021 : 1/10 : 10)
= 2022 x(0,75+0,25) - 2021x 10 : 10
= 2022x 1 - 2021
= 2022 - 2021
=1
tính nhanh : 2022 +2022 : 1/3 +2022+2022:1/5 =
`2022+2022:1/3+2022+2022:1/5`
`=2022+2022xx3+2022+2022xx5`
`=2022xx(1+3+1+5)`
`=2022xx10=20220`
`->2022+2022×3+2022+2022×5`
`->`\( 2022 × ( 1 + 3 + 1 + 5 )\)
`->2022xx10`
`->20220`
Tính nhanh: A= \(\dfrac{2022}{1.2}+\dfrac{2022}{2.3}+\dfrac{2022}{3.4}+...+\dfrac{2022}{2021.2022}\)
A=2022(1/1-1/2+1/2-1/3+...+1/2021-1/2022)
=2022(1/1-1/2022)
=2022.2021/2022
ket qua tu tinh nha
A = \(\dfrac{2022}{1.2}+\dfrac{2022}{2.3}+\dfrac{2022}{3.4}+...+\dfrac{2022}{2021.2022}\)
= \(\dfrac{2022}{1}-\dfrac{2022}{2}+\dfrac{2022}{2}-\dfrac{2022}{3}+\dfrac{2022}{3}-\dfrac{2022}{4}+...+\dfrac{2022}{2021}-\dfrac{2022}{2022}\)
= \(\dfrac{2022}{1}-\dfrac{2022}{2022}\)
= \(2021\)
Chúc bạn học tốt!! ^^
2022.( 1/1.2+ 1/2.3+...+ 1/2021+2022)
2022. ( 1-1/2+1/2-1/3+......+1/2021-1/2022)
2022.( 1-1/2022)
2022.2021/2022
2021
Tính nhanh: 2022 x 57 + 2022 x 42 + 2022
= 2022 x ( 57 + 42 + 1 )
= 2022 x 100
= 202200
Tính nhanh: 2022 x 57 + 2022 x 42 + 2022
\(2022\times57+2022\times42+2022=2022\times\left(57+42+1\right)=2022\times\left(57+43\right)=2022\times100=202200.\)
X+X:0,5+X:0,25+X:0,125=2022
X : (1+0,5+0,25+0,125)=2022
X : 1,875 = 2022
X = 1078,4
x+x:0,5+x:0,25+x:0,125 = 2022
x.(1+1/2+1/4+1/8) = 2022
x.15/8 = 2022
x = 2022: 15/8
x = 1078,4
tìm x biết:X+X:0,5+X:0,25+X:0,125=2022
làm nhanh hộ mình với.ai làm đủ và nhanh nhất mình vote cho
\(x+x:0,5+x:0,25+x:0,125=2022\)
\(x\text{×}1+x\text{×}2+x\text{×}4+x\text{×8}=2022\)
\(x\text{×}\left(1+2+4+8\right)=2022\)
\(x\text{×}15=2022\)
\(x=2022:15\)
\(x=134,8\)
tính C=a^2022+3^2022/b^2022+5^2022 biết a,b khác 0 thõa mãn 3a-b=1/2(a+b)
mình cần gấp, mọi người làm nhanh giúp mình
Tính nhanh:
2022 x 2023 - 1/2023 x 2021 + 2022
\(\dfrac{2022\times2023-1}{2023\times2021+2022}\)
= \(\dfrac{\left(2021+1\right)\times2023-1}{2023\times2021+2022}\)
= \(\dfrac{2023\times2021+2023-1}{2023\times2021+2022}\)
= \(\dfrac{2023\times2021+2022}{2023\times2021+2022}\)
= 1