11/12-(5/42-x)=-(15-11/13)

=>11/13-(5/42-x)=184/13

=>5/42-x=11/13- (-184/13)

=>5/42-x=15

=>x=5/42-15

=>x=-625/42

5/42-x=11/13- [-(15-11/13)]=11/13+15-11/13

5/42-x=(11/13-11/13)+15=15

x=5/42-15=5/42-630/42

x=-625/42

Vậy x=-625/42

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\(\frac{1}{13}-\left(\frac{5}{42}-x\right)=-\left(-\frac{113}{364}\right)\)

=>\(\frac{1}{13}-\frac{5}{42}+x=\frac{113}{364}\)

=>\(-\frac{23}{546}+x=\frac{113}{364}\)

=>\(x=\frac{113}{364}-\left(-\frac{23}{546}\right)\)

=>\(x=\frac{113}{364}+\frac{23}{546}\)

=>\(x=\frac{55}{156}\)

\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)

Đặt \(A=\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...+\frac{20}{53.55}\)

\(A=\frac{10.2}{11.13}-\frac{10.2}{13.15}-\frac{10.2}{15.17}-...-\frac{10.2}{53.55}\)

\(A=10\left(\frac{2}{11.13}-\frac{2}{13.15}-\frac{2}{15.17}-...-\frac{2}{53.55}\right)\)

\(A=10\left(\frac{1}{11}-\frac{1}{55}\right)\)

\(A=10.\frac{4}{55}\)

\(A=\frac{40}{55}\)\(A=10.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)\)

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)

\(\frac{-5}{42}+x=-\frac{15}{28}+\left(\frac{11}{13}-\frac{11}{13}\right)\)

\(\frac{-5}{42}+x=-\frac{15}{28}\)

\(x=-\frac{15}{28}+\frac{5}{42}\)

\(x=-\frac{45}{84}+\frac{10}{84}\)

\(x=-\frac{35}{84}\)

Vậy \(x=-\frac{35}{84}\).

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)

\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)

\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)

\(x=\frac{5}{42}-\frac{15}{28}\)

\(x=-\frac{5}{12}\)

vậy \(x=-\frac{5}{12}\)

                              Bài làm :

Ta có :

\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

\(\Leftrightarrow\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)

\(\Leftrightarrow\frac{5}{42}-x=\frac{11}{13}-\frac{113}{364}\)

\(\Leftrightarrow\frac{5}{42}-x=\frac{15}{28}\)

\(\Leftrightarrow x=\frac{5}{42}-\frac{15}{28}=-\frac{5}{12}\)

Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

`(2/(11.13)+2/(13.15)+....+2/(19.21)).462-[0,04/(x+1,05):0,12=19`

`=>(1/11-1/13+1/13-1/15+....+1/19-1/21).462-(2/(50(x+1,05)).25/3=19`

`=>(1/11-1/21).462-1/(3(x+1,05))=19`

`=>10/231. 462-1/(3x+3,15)=19`

`=>20-1/(3x+3,15)=19

`=>1/(3x+3,15)=1`

`=>3x+3,15=1`

`=>3x=-2,15`

`=>x=-43/60`

Vậy `x=-43/60`

Giải: 

\(\left(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}\right).462-\left[\dfrac{0,04}{x+1,05}:0,12\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{\dfrac{25}{x+\dfrac{21}{20}}}:\dfrac{3}{25}\right]=19\) 

\(\left(\dfrac{1}{11}-\dfrac{1}{21}\right).462-\left[\dfrac{1}{25.\left(x+\dfrac{21}{20}\right)}:\dfrac{3}{25}\right]=19\) 

                             \(20-\left[\dfrac{25.1}{3.25.\left(x+\dfrac{21}{20}\right)}\right]=19\) 

                                              \(\dfrac{1}{3.\left(x+\dfrac{21}{20}\right)}=20-19\) 

                                               \(\dfrac{1}{3.x+\dfrac{63}{20}}=1\) 

                                      \(1:\left(3.x+\dfrac{63}{20}\right)=1\) 

                                                \(3.x+\dfrac{63}{20}=1:1\) 

                                                \(3.x+\dfrac{63}{20}=1\) 

                                                         \(3.x=1-\dfrac{63}{20}\) 

                                                         \(3.x=\dfrac{-43}{20}\) 

                                                            \(x=\dfrac{-43}{20}:3\) 

                                                            \(x=\dfrac{-43}{60}\)

chiu thoi

\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)

\(\frac{10}{231}\times462-x=19\)

\(20-x=19\)

\(\Rightarrow x=20-19=1\)