a) 27 . 75 + 25 . 27 - 150 = 2025 + 675 - 150 = 2700 - 150 = 2550.

Lưu ý. Có thể dùng tính chất phân phối của phép nhân đối với phép cộng để nhẩm:

27 . 75 + 25 . 27 - 150 = 27 . (75 + 25) - 150 = 27 . 100 - 150 = 2700 - 150 = 2550.

b) 12 : {390 : [500 - (125 + 35 . 7)]} = 12 : {390 : [500 - (125 + 245)]}

= 12 : [390 : (500 - 370)] = 12 : (390 : 130) = 12 : 3 = 4.

a,27+75.25+27-150

= 27.(75+25)-150

=27.100-150

=2700-150

=2550

b,12:{390:[500-(125+35.7)]}

=12:{390:[500-(125+245)]}

=12:{390:[500-370]}

=12:{390:130}

=12:3

=4

Thank you very much

a)\(27.75+25.27-150=27\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

b)\(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)

\(=12:\left[390:\left(500-370\right)\right]\)

\(=12:\left(390:130\right)\)

\(=12:3\)

=4

a, 25.(75 + 27 - 150 )

= 25 . (-48)

= - 1200

b, 12 : { 390 : [500 - 370 ]

= 12 : { 390 : 130 }

= 12 : 3

= 4

a) \(27.75+25.27-150\)

\(=27.\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

b) \(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)

\(=12:\left\{390:\left[500-370\right]\right\}\)

\(=12:\left\{390:130\right\}\)

\(=12:3\)

\(=4\)

a, 27.75+25.27-150=27.(75+25)-150

                               =27.100-150

                              =2700-150

                              =2550

b,12:{390:[500-(125+35.7)]}

=12:{390:[500-(125+245)]}

=12:{390:[500-370]}

=12:{390:130}

=12:3

=4.

các bạn ơi xin các bạn tội ngiệp cho tôi vài lik eSky Nguyễn

a).

= 27. (75+25)- 150

= 27. 100 -150

= 2700    - 150

= 2550

a, = 27 . ( 75 + 25 ) - 150 
    = 27 . 100 - 150
    = 2700 - 150
    = 2550
b, = 12 : { 390 : [ 500 - 370 ]
    = 12 : { 390 : 130 }
    = 12 : 3 
    = 4
 

a) 27.75+25.27-150=2025+675-150

                            =2700-150

                            =2550

b) 12:{390:[500-(125+35.7)]}=12:{390:[500-(125+245)]}

                                        =12:[390:(500-370)]

                                        =12:(390:130)

                                        =12:3

                                        =4

Thực hiện phép tính: 

a) 

27 . 75 + 25 . 27 - 150

= 27 . ( 75 + 25) - 150

= 27 . 100 - 150

= 2700 - 150

= 2550

b)

12: {390: [ 500  - ( 125 + 35 . 7 ) ] }

= 12 : { 390 : [ 500 - ( 125 + 245 ) ]  }

= 12 : { 390 : [ 500 - 370 ] }

=12 : { 390 : 130 }

= 12 : 3

= 4 

Ủng hộ nha! :) 

a) \(27\cdot75+25\cdot27-150\)

\(=27\cdot\left(75+25\right)-150\)

\(=27\cdot100-150\)

\(=2700-150\)

\(=2550\)

b) \(12:\left\{390:\left|500-\left(125+35\cdot7\right)\right|\right\}\)

\(=12:\left\{390:\left|500-\left(125+245\right)\right|\right\}\)

\(=12:\left\{390:\left|500-370\right|\right\}\)

\(=12:\left\{390:130\right\}\)

\(=12:3\)

\(=3\)

a) 27.(75+25)-150=27.100-150=2550

a,3900.                     b,4

a)27.75+25.27-150

=27.(75+25)-150

=27.100-150

=2700-150

=2550

\(a,27.75+25.27-150\)

\(=27.\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

\(b,12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)

\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)

\(=12:\left[390:\left(500-370\right)\right]\)

\(=12:\left(390:130\right)\)

\(=12:3\)

\(=4\)

a) \(27\cdot75+25\cdot27-150\)

\(=27\cdot100-150\)

\(=2700-150\)

\(=2550\)

b) \(12\div\left\{390\div\left[500-\left(125+35\cdot7\right)\right]\right\}\)

\(=12\div\left\{390\div\left[500-370\right]\right\}\)

\(=12\div\left(390\div130\right)\)

\(=12\div3\)

\(=4\)

a: Ta có: \(\left(8\cdot5^7+5^6-5^5\right):5^5\)

\(=8\cdot5^2+5-1\)

\(=200+4=204\)

b: Ta có: \(\left(9^{30}-27^{19}\right):3^{57}+\left(125^9-25^{12}\right):5^{24}\)

\(=3^{60}:3^{57}-3^{57}:3^{57}+5^{27}:5^{24}-5^{24}:5^{24}\)

\(=27-1+125-1\)

=150

a. (8,5⁷ - 5⁵ + 5⁶) : 5⁵

= (8,5⁷ : 5⁵) - (5⁵ : 5⁵) + (5⁶ : 5⁵)

= 1,7² - 1 + 5

= 2,89 - 1 + 5

= 6,89

b. (9³⁰ - 27¹⁹) : 3⁵⁷ + (125⁹ - 25¹²) : 5²⁴

= (9³⁰ : 3⁵⁷) - (27¹⁹ : 3⁵⁷) + (125⁹ : 5²⁴) - (25¹² : 5²⁴)

= 3³ - 1 + 125 - 1

= 27 - 1 + 125 - 1

= 150

c. (10¹² + 5¹¹ . 2⁹ - 5¹³ - 2⁸) : 4 . 5⁵ . 10⁶

= (10¹² + 2,5 , 10¹⁰ - 5¹³ - 2⁸) : 1,25 . 10¹⁰

= (10¹² : 1,25 . 10¹⁰) + (2,5 . 10¹⁰ : 1,25 . 10¹⁰) - (5¹³ : 1,25 . 10¹⁰) - (2⁸ : 1,25 . 10¹⁰)

= 80 + 2 - \(\dfrac{25}{256}\) - \(\dfrac{1}{48828125}\)

= 81,90234373 \(\approx\) 82

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)