Tính : a, 3.7*3.8+8.3+3.7-0.4*3.7*5.
B, 2.5*9.5*4+19.5*10
3.7*3.8+8.3*3.7-0.4*3.7*5
3.7x3.8+8.3x3.7-0.4x3.7x5=1523.142
cho mình nha
3.7*3.8+8.3*3.7-0.4*3.7*5
=3,7*(3,8+8,3-0,4*5) = 3,7*10,1=37,37
Tính bằng cách thuận tiện nhất :
a / 2 x 4 x 8 x 0.5 x 0.125 x 0.25 x ( 0.4321 + 0.5679 )
b /3.7 x 3.8 + 8.3 x 3.7 - 0.4 x 3.7 x 5
a, 2 x 4 x 8 x 0,5 x 0,125 x 0,25 x ( 0,4321 + 0,5679 )
= ( 2 x 0,5 ) x ( 4 x 0,25 ) x ( 0,125 x 8 ) x ( 0,4321 + 0,5679 )
= 1 x 1 x 1 x ( 0,4321 + 0,5679 )
= 1 x ( 0,4321 + 0,5679 )
= 1 x 1 = 1
b, 3,7 x 3,8 + 8,3 x 3,7 - 0,4 x 3,7 x 5
= 3,7 x ( 3,8 + 8,3 ) - ( 0,4 x 5 ) x 3,7
= 3,7 x 12,1 - 2 x 3,7
= 3,7 x ( 12,1 - 2 )
= 3,7 x 10,1 = 37,37
\(P=\dfrac{2.5^{22}-9.5^{20}}{25^{10}}:\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
Đặt P= \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\) : \(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)
Có : \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\)
= \(\dfrac{\left(2.5-9\right).5^{21}}{\left(5^2\right)^{10}}\)= \(\dfrac{\left(10-9\right).5^{21}}{5^{20}}\)=\(\dfrac{5^{21}}{5^{20}}\)= 5 (1)
Có: \(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)
= \(\dfrac{5.\left[7^{14}.\left(3.7-19\right)\right]}{\left[7^{15}.\left(3+7\right)\right]}\)=\(\dfrac{5.7^{14}.2}{7^{15}.10}\)=\(\dfrac{10.7^{14}}{7^{15}.10}\)=\(\dfrac{1}{7}\) (2)
Từ (1) và (2) suy ra:
A= 5:\(\dfrac{1}{7}\)=5.7=35
Vậy A=35 hay \(\dfrac{2.5^{22}-9.5^{21}}{25^{10}}\):\(\dfrac{5.\left(3.7^{15}-19.7^{14}\right)}{\left(7^{16}+3.7^{15}\right)}\)= 35
\(P=\dfrac{2.5^{22}-9.5^{20}}{25^{10}}:\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(=\dfrac{5^{20}\left(2.5^2-9\right)}{5^{20}}:\dfrac{5.7^{14}\left(3.7-19\right)}{7^{15}\left(7+3\right)}\)
\(=\left(2.5^2-9\right):\dfrac{5\left(3.7-19\right)}{7.10}\)
\(=\dfrac{7.10\left(2.5^2-9\right)}{5\left(3.7-19\right)}\)
\(=\dfrac{7.2\left(2.5^2-9\right)}{3.7-19}\)
\(=\dfrac{14.41}{21-19}\)
\(=\dfrac{14}{2}\cdot41=7.41=287\)
Thực hiện phép tính;
a)\(\frac{2.5^{22}-9.5^{21}}{25^{10}}\)
b) \(\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=\frac{5.\left[7^{14}\left(3.7-19\right)\right]}{7^{15}\left(7+3\right)}=\frac{5.7^{14}.2}{7^{15}.10}=\frac{2}{7.2}=\frac{2}{14}=\frac{1}{7}\)
a) \(\frac{2.5^{22}-9.5^{21}}{25^{10}}=\frac{5^{21}.\left(2.5-9\right)}{\left(5^2\right)^{10}}=\frac{5^{21}.1}{5^{20}}=5\)
b) \(\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}=\frac{5.7^{14}.\left(3.7-19\right)}{7^{15}.\left(7+3\right)}=\frac{5.7^{14}.2}{7^{15}.10}=\frac{1}{7}\)
a) \(\frac{2.5^{22}-9.5^{21}}{25^{10}}=\frac{2.5^{20}.5^2-9.5^{20}.5}{25^{10}}=\frac{\left(5^2\right)^{10}\left(2.5^2-9.5\right)}{25^{10}}=\frac{25^{10}\left(2.5^2-9.5\right)}{25^{10}}=2.5^2-9.5=5\left(2.5-9\right)=5.\left(10-9\right)=5.1=5\)
\(\frac{2.5^{22}-9.5^{21}}{25^{10}}+\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
thuc hien phep tinh \(A=\frac{2.5^{22}-9.5^{21}}{25^{10}}\div\frac{5.\left(3.7^{15}-14\right)}{7^{15}.3.7^{15}}\)
Thực hiện phép tính: \(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(=\frac{5^{21}.\left(2.5-9\right)}{5^{20}}:\frac{5.7^{14}\left(3.7-19\right)}{7^{15}\left(7+3\right)}\)
\(=5:\frac{5.2}{7.10}\)
\(=5:\frac{1}{7}\)
\(=35\)
Thực hiện phép tính: \(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\\ =\frac{5^{21}.\left(10-9\right)}{5^{20}}.\frac{7^{15}.\left(7+3\right)}{5.7^{14}.\left(21-19\right)}\\ =5.\frac{70}{10}\\ =5.7\\ =35\)
\(\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
\(=\frac{5^{20}\left(2.5^2-9.5\right)}{5^{20}}:\frac{5.7^{14}\left(3.7-19\right)}{7^{14}\left(7^2+3.7\right)}\)
\(=\left(50-45\right):\frac{5\left(21-19\right)}{49+21}\)
\(=5.\frac{70}{10}=35\)