\(=\dfrac{10}{8};\dfrac{3}{8}\)

\(=\dfrac{36}{30};\dfrac{25}{30}\)

\(=\dfrac{65}{20};\dfrac{12}{20}\)

\(a,\dfrac{3}{4}:\dfrac{6}{x}=\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{4}:\dfrac{5}{4}\\ \dfrac{6}{x}=\dfrac{3}{5}\\ x=6:\dfrac{3}{5}\\ x=10\\ b,\left(x+\dfrac{7}{4}\right)\times\dfrac{2}{3}=6\\ x+\dfrac{7}{4}=6:\dfrac{2}{3}\\x+\dfrac{7}{4}=9\\ x=9-\dfrac{7}{4}\\ x=\dfrac{29}{4}\)

giúp mình đi, sao dạo này ít ngừi giúp qué zại

a) \(\dfrac{3}{4}\div\dfrac{6}{x}=\dfrac{5}{4}\)

            \(\dfrac{6}{x}=\dfrac{3}{4}\div\dfrac{5}{4}\)

            \(\dfrac{6}{x}=\dfrac{3}{5}\)

            \(x=\left(6\div3\right)\times5\)

           \(x=10\)

b) \(\left(x+\dfrac{7}{4}\right)\times\dfrac{2}{3}=6\)

     \(x+\dfrac{7}{4}=6\div\dfrac{2}{3}\)

     \(x+\dfrac{7}{4}=9\)

     \(x=9-\dfrac{7}{4}\)

    \(x=\dfrac{29}{4}\)

giúp mình với

a. x + 3/10= 25/8

x = 25/8-3/10

x = 113/40

b. x/35 = 4/5-5/7

x/35 = 3/35

vậy x=3

\(x+\dfrac{3}{10}=4-\dfrac{7}{8}\)

\(x+\dfrac{3}{10}=\dfrac{25}{8}\)

        \(x=\dfrac{25}{8}-\dfrac{3}{10}\)

       \(x=\dfrac{113}{40}\)

\(\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)

        \(\dfrac{x}{35}=\dfrac{4}{5}-\dfrac{5}{7}\)

        \(\dfrac{x}{35}=\dfrac{3}{35}\)

    =>x=3

<=> 11 - 15 - x = x - 25 + 9

<=>   -x - x       = - 25 + 9 - 11 + 15

<=> - 2x           = -12

<=>    x            = -12 : (- 2)

<=>    x            = 6

Tìm số nguyên x biết:

\(11-\left(15+x\right)=x-\left(25-9\right)\)

\(11-\left(15+x\right)=x-16\)

      \(11-15-x=x-16\)

                 \(-x-x=-16-11+15\)

                       \(-2x=-16-11+15\)

                      \(-2x=-27+15\)

                      \(-2x=-12\)

                         \(-x=-12:2\)

                          \(-x=-6\)

\(=>x=6\)

Vậy \(x=6\)

x/4 = y/7 và x x y = 112

x/4 = y/7 = k

suy ra : x/4 = k suy ra x = 4 . k 

            y/7 = k suy ra y = 7 . k 

ta có : x . y = 28 suy ra 4k . 7k

                                   28k² = 28

                                       k^{2 = 28}

                                                    ^{k    = -1 và + 1}

^{vì k = 1 ta có} 

^{x = 4 ; y = 7}

^{vì k = -1}

^{x = - 4 ; y = - 7}

^{vậy x = (4 ; -4 ) ; y = ( 7 ; -7 )}

Đặt x/4 =y/7 = k 

=> x= 4k; y= 7k 

Thay x= 4k; y= 7k vào xy = 112 :

(tự làm)

k mình nha bạn mình trả lời đầu tiên 

\(\left(x+\frac{1}{3}\right)\left(\frac{3}{4}-2x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{3}=0\\\frac{3}{4}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\x=\frac{3}{8}\end{cases}}\)

Vậy \(x\in\left\{\frac{-1}{2};\frac{3}{8}\right\}\)

Làm đầy đủ hộ mình đi được k bạn

\(a,1\frac{1}{3}+\frac{2}{3}x=5\frac{1}{3}\)

\(\Rightarrow\frac{4}{3}+\frac{2}{3}x=\frac{16}{3}\)

\(\Rightarrow\frac{2}{3}x=\frac{16}{3}-\frac{4}{3}\)

\(\Rightarrow\frac{2}{3}x=4\)

\(\Rightarrow x=4:\frac{2}{3}=4.\frac{3}{2}=6\)

Vậy x=6

\(b,\left(x+\frac{1}{3}\right)\left(\frac{3}{4}-2x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{3}=0\\\frac{3}{4}-2x=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\-2x=\frac{3}{4}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\x=\frac{-3}{8}\end{cases}}\)

Vậy.................

\(c,\frac{-4}{5}x+1\frac{1}{3}x=-1\frac{1}{3}\)

\(\Rightarrow\frac{-4}{5}x+\frac{4}{3}x=\frac{-4}{3}\)

\(\Rightarrow\frac{-2}{3}x=\frac{-4}{3}\)

\(\Rightarrow x=\frac{-4}{3}:\frac{-2}{3}=\frac{-4}{3}.\frac{3}{-2}=2\)

Vậy x=2

bài 1: 

2(x^2-9).4(x^2-1)

=(2x^2-18)(4x^2-4)

=8x^4-8x^2-72x^2+72

=8x^4-80x^2+72

\(Bai1:2\left(x-3\right)\left(x+3\right)+4\left(x-1\right)\left(x+1\right)\)

\(=2\left(x^2-9\right)+4\left(x^2-1\right)\)

\(=2x^2-18+4x^2-4\)

\(=6x^2-22\)

\(Bai2:-\left(6x-1\right)\left(3-2x\right)+\left(3x-2\right)\left(4x-3\right)=17\)

\(\Leftrightarrow-\left(18x-12x^2-3+2x\right)+12x^2-9x-8x+6=17\)

\(\Leftrightarrow-18x+12x^2+3-2x+12x^2-9x-8x+6=17\)

\(\Leftrightarrow24x^2-37x+9-17=0\)

\(\Leftrightarrow24x^2-37x-8=0\)

Đề sai??