\(\left|2x-1\right|=\dfrac{3}{2}\\ \Rightarrow\left[{}\begin{matrix}2x-1=\dfrac{3}{2}\\2x-1=-\dfrac{3}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

Thay \(x=\dfrac{5}{4}\) vào D ta có:

\(D=4x+3=4.\dfrac{5}{4}+3=5+3=8\)

Thay \(x=-\dfrac{1}{4}\) vào D ta có:

\(D=4.\dfrac{-1}{4}+3=-1+3=2\)

Để \(D=\dfrac{3}{2}\)

\(\Leftrightarrow4x+3=\dfrac{3}{2}\\ \Leftrightarrow4x=-\dfrac{3}{2}\\ \Leftrightarrow x=-\dfrac{3}{8}\)

\(\left|2x-1\right|=\dfrac{3}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=\dfrac{3}{2}\\2x-1=\dfrac{-3}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{5}{2}\\2x=\dfrac{-1}{2}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{-1}{4}\end{matrix}\right.\)

\(x=\dfrac{5}{4}\text{ thì }D=4.\dfrac{5}{4}+3=5+3=8\)

\(x=\dfrac{-1}{4}\text{ thì }D=4.\left(\dfrac{-1}{4}\right)+3=\left(-1\right)+3=2\)

\(D=\dfrac{-5}{2}\Leftrightarrow4x+3=\dfrac{-5}{2}\)

               \(\Leftrightarrow4x=\dfrac{-11}{2}\)

               \(\Leftrightarrow x=\dfrac{-11}{8}\)

giúp mình với

Chọn B

ai không giúp mik với

=48.1/3.16

=16.16

=256

giúp mình với

\(\dfrac{6\times8\times11}{33\times16}=\dfrac{3\times2\times8\times11}{11\times3\times8\times2}=1\)