thực hiện phép tính bằng cách hợp lí ?
\(B=1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)
\(\frac{636363.37-373737.63}{1+2+3+....+2006}\)
B=47/41.[12.(1+1/19-1/37-1/53)/3.(1+1/19-1/37-1/53):4.(1+1/17+1/19+1/2006)/5.(1+1/17+1/19+1/2006)].123/235
=47/41.[4:4/5].123/235
=47/41.5.123/235=3
C=63.10101.37-37.10101.63/1+2+3+...+2006
=0/1+2+3+...+2006=0
CẬU XEM LẠI CHO MÌNH NHA!
\(\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}=\frac{0}{1+2+3+...+2006}=0\)
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Tính hợp lí:
\(B=1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right)\)
B=\(1\frac{6}{41}\times\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}\div\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right)\times\frac{124242423}{237373735}\)
GIÚP MÌNH VỚI ! ^_^
Tính giá trị biểu thức:
A=\(1\frac{6}{41}\left[\frac{12+\frac{12}{19}+\frac{12}{37}+\frac{12}{53}}{3+\frac{9}{57}+\frac{3}{37}+\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right]\)
Tinh B=1\(\frac{6}{41}\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}.\frac{124242423}{2373735}\)
\(\frac{5}{23}x\frac{17}{6}+\frac{5}{23}x\frac{9}{26}\)
\(=\frac{5}{23}x\left(\frac{17}{26}+\frac{9}{26}\right)\)
\(=\frac{5}{23}x1=\frac{5}{23}\)
Thực hiện phép tính bằng cách hợp lí :
\(1\frac{6}{41}\times\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}\div\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right)\times\frac{124242423}{237373735}\)
Tính:
B =\(1\frac{6}{41}.\left(\frac{12+\frac{12}{9}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{12424242.3}{23737373.5}\)
Bạn đi hỏi các anh chị
Rồi anh chị chỉ cho
~~~ Chúc bạn học giỏi ~~~
Thực hiện phép tính bằng cách hợp lý:
\(1\frac{6}{41}.\left(\frac{\left(12+\frac{2}{19}-\frac{12}{37}-\frac{12}{53}\right)}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right)\)\(.\frac{124242423}{237373735}\)
Bài này về tỷ số
Khó lắm bạn ơi
Thông cảm cho mình
~~~ Chúc bạn học giỏi ~~~
cậu ấn vào câu hỏi tương tự là nó hiển thị ra các câu khác có câu trả lời đấy
a) \(E=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{48.49.50}\)
b) \(F=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
c) \(G=\frac{636363.37-373737.63}{1+2+3+...+2017}\)
d) \(H=\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2016}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{3016}}\right).\frac{124242423}{237373735}\)
giúp mk với ! Help me!
c) G = \(\frac{636363.37-373737.63}{1+2+3+...+2017}\)
G = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2017}\)
G = \(\frac{0}{1+2+3+...+2017}\)
=> G = 0
Vậy G = 0
a) \(E=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{48.49.50}\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{48.49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}.\frac{612}{1225}\)
\(\Rightarrow E=\frac{306}{1225}\)
Vậy...
b) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
d) Bạn xem lại đề nhé
