A/ \(\frac{4}{5}+\frac{1}{5}x=\left(-\frac{1}{28}\right)\)

\(\frac{1}{5}x=\left(-\frac{1}{28}\right)-\frac{4}{5}\)

\(\frac{1}{5}x=\left(-\frac{5}{140}\right)-\frac{112}{140}\)

\(\frac{1}{5}x=-\frac{117}{140}\)

\(x=\left(-\frac{117}{140}\right):\frac{1}{5}\)

\(x=\left(-\frac{117}{28}\right)\)

B/ \(\left(\frac{3x}{7}+1\right):\left(-4\right)=-\frac{1}{28}\)

\(\frac{3x}{7}+1=\left(-\frac{1}{28}\right).\left(-4\right)\)

\(\frac{3x}{7}+1=\frac{1}{7}\)

\(\frac{3x}{7}=\frac{1}{7}-1\)

\(\frac{3x}{7}=\frac{1}{7}-\frac{7}{7}\)

\(\frac{3x}{7}=-\frac{6}{7}\)

\(\Rightarrow3x=\left(-6\right)\)(theo cách l8)

\(\Rightarrow x=\left(-6\right):3=\left(-2\right)\)

a)   X=-117/28

b)   X=-4

Chưa chắc đã đúng nha bạn

a. \(\frac{4}{5}+\frac{1}{5}x=\frac{1}{28}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{1}{28}-\frac{4}{5}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{5}{140}-\frac{112}{140}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{-107}{140}\)

\(\Leftrightarrow x=\frac{-107}{140}\div\frac{1}{5}\)

\(\Leftrightarrow x=\frac{-107}{140}\times5\)

\(\Leftrightarrow x=\frac{-107}{28}=\)

b. \(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)

\(\Leftrightarrow\left(\frac{3x}{7}+\frac{7}{7}\right)=\frac{-1}{28}\times\left(-4\right)\)

\(\Leftrightarrow\frac{3x+1}{7}=\frac{1}{7}\)

\(\Leftrightarrow3x+1=1\)

\(\Leftrightarrow3x=1-1\)

\(\Leftrightarrow3x=0\Leftrightarrow x=0\)

a: \(x\in\left\{0;25\right\}\)

c: \(x\in\left\{0;5\right\}\)

a) 1/2x - 2/3x = 7/12

    -1/6x = 7/12

     x = \(\frac{7}{12}\div\frac{-1}{6}\)

     x = -7/2

b)  x: 12 = -2,5

     x = -2,5*12

     x = -30

c) 11/2x = 13/15

    x = 13/15:11/2

    x = 26/165

d) 3x/7 + 1 = (-1/28)*(-4)

    3x/7 + 1 = 1/7

    3x/7 = 1/7 - 1

    3x/7 = -6/7

    3x = -6

    x= -6/3

    x= -2

a) x(0.5 - 2/3 ) = 7/12

        (-1/6)x = 7/12

             x      = 7/12 : (-1/6)

            x      =-7/2

b) x :  12 = -2,5

   x= -2.5 * 12  =-30

c)   x = 13/15 : 5,5

    x  =26/125

d) 3x/7 + 1  =  -1/28 * (-4)

   3x/7 + 1   =1/7

  3x/7    = 1/7 -1

   3x/7  =-6/7

   3x    =-6/7 * 7 

  3x = -6

   x =-2

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( 3x/7 + 1 ) : (-4 ) = -1/28

 3x/7 + 1           = -1/28 x (-4 ) 

(3x/7 + 1           = 1/7

3x/7                  = 1/7  - 1

3x/7                  = -6/7

Suy ra 3x = -6

            x = -6 : 3

            x = -2

=>3x/7+1=-1/28x(-4)

=>3x/7+1=1/7

=>3x/7=1/7-1

=>3x/7=-6/7

=>3x=6

=>x=6:3=2

k mình đi

Ta có : (3x/7+1) : (-4) = -1/28

3x/7+1 = -1/28 . (-4)

3x/8 = 1/7

Do đó 3x.7/56 = 8/56

Suy ra 3x.7=8

Suy ra 3x =8 : 7

Suy ra 3x = 8/7

Suy ra x = 8/7 : 3

Do đó x = 8/21

\(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)

\(\Leftrightarrow\dfrac{3x}{7}+1=\dfrac{-1}{28}.\left(-4\right)\)

\(\Leftrightarrow\dfrac{3x}{7}+1=\dfrac{1}{7}\)

\(\Leftrightarrow\dfrac{3x}{7}=\dfrac{1}{7}-1\)

\(\Leftrightarrow\dfrac{3x}{7}=\dfrac{-6}{7}\)

\(\Leftrightarrow3x=-6\)

\(\Leftrightarrow x=-2\)

Mình không viết lại đề nữa nhé! Dấu " ; " đổi thành dấu " : " (phép chia)\(\Leftrightarrow\dfrac{3x+7}{7}\cdot\left(-\dfrac{1}{4}\right)=-\dfrac{1}{28}\)

\(\Leftrightarrow\dfrac{-3x-7}{28}=-\dfrac{1}{28}\)

\(\Rightarrow-3x-7=-1\)

\(\Leftrightarrow3x=-6\)

\(\Leftrightarrow x=-2\)

Vậy x = -2

\(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)

⇔ \(\left(\dfrac{3x}{7}+\dfrac{7}{7}\right):\dfrac{-4}{1}=\dfrac{-1}{28}\)

⇔ \(\dfrac{3x+7}{7}:\dfrac{-4}{1}=\dfrac{-1}{28}\)

⇔ \(\dfrac{3x+7}{7}.\dfrac{1}{-4}=\dfrac{-1}{28}\)

⇔ \(\dfrac{3x+7}{-28}=\dfrac{-1}{28}\)

⇔ 28.(3x + 7) = -1.(-28)

⇔ 84x + 196 = 28

⇔ 84x = 28 - 196

⇔ 84x = -168

⇔ x = -2