Ta có:

2020/2021 = 20/21 = 100/105

2727/3535 = 27/35 = 81/105

Do 100 > 81 nên 100/105 > 81/105

Vậy 2020/2021 > 2727/3535

không có gì đâu bạn !!!

3535/3534  <  2323/2322

\(\frac{3636}{3535}+\frac{5454}{4242}\)

\(=\frac{36}{35}+\frac{54}{42}\)

= \(\frac{36}{35}+\frac{9}{7}\)

= \(\frac{36}{35}+\frac{45}{35}\)

= \(\frac{81}{35}\)

81/35

a,\(\frac{2015.2016+2015-1}{2014+2015.2016}=\frac{2015.2016+2014}{2014+2015.2016}=1\)\(1\)

b,\(=1-\frac{1}{5}+\frac{1}{5}...-\frac{1}{2011}+\frac{1}{2011}-\frac{1}{2015}=1-\frac{1}{2015}=\frac{2014}{2015}\)

c,\(=\frac{12}{35}+\frac{12}{35}+\frac{12}{35}+\frac{12}{35}=\frac{12}{35}.4=\frac{48}{35}\)

48/35 nha

b>=1-1/5+1/5-1/9+...+1/2011-1/2015

 =1-1/2015

=2014/2015

c>=12/35+12/35+12/35+12/35

=12/35x4

=48/35

A=\(\frac{3535.232323}{353535.2323}\)=\(\frac{35.23}{35.23}\)=1

B=\(\frac{3535}{3534}\)>1

=> A <B

B lớn hơn nhé,mình nhầm
!!!!!!!!!!!!!!!!!

3535/4848=5*707/8*606=5/8

=>3535/4848=5/8

\(\frac{3535}{4848}=\frac{5.707}{8.606}=\frac{5}{8}.\frac{707}{606}\)

vì \(\frac{707}{606}>1\Rightarrow\frac{5}{8}.\frac{707}{606}>\frac{5}{8}\)(nhân 2 vế cho \(\frac{5}{8}\))

vậy \(\frac{3535}{4848}>\frac{5}{8}\)

\(\frac{505050}{707070}=\frac{505050:101010}{707070:101010}\)= \(\frac{5}{7}\)

\(\frac{2525}{3535}=\frac{2525:505}{3535:505}=\frac{5}{7}\)

Vậy hai phân số \(\frac{2525}{3535}\)và \(\frac{505050}{707070}\)bằng nhau

rút gọn \(\frac{2525}{3535}\)=\(\frac{5}{7}\);\(\frac{505050}{707070}\)=\(\frac{5}{7}\)

vì \(\frac{5}{7}\)=​\(\frac{5}{7}\)\(\Rightarrow\)\(\frac{2525}{3535}\)=\(\frac{505050}{707070}\)

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