1) \(\dfrac{5}{10}=\dfrac{5:5}{10:5}=\dfrac{1}{2}\)

\(\dfrac{-18}{-27}=\dfrac{-18:\left(-9\right)}{-27:\left(-9\right)}=\dfrac{2}{3}\)

\(\dfrac{-42}{105}=\dfrac{-42:21}{105:21}=\dfrac{-2}{5}\)

\(\dfrac{75}{-135}=\dfrac{75:\left(-15\right)}{-135:\left(-15\right)}=\dfrac{-5}{9}\)

\(\dfrac5{10}=\dfrac{5.1}{5.2}=\dfrac12\\\dfrac{-18}{-27}=\dfrac{(-9).2}{(-9).3}=\dfrac23\\\dfrac{-42}{105}=\dfrac{21.(-2)}{21.5}=\dfrac{-2}5\\\dfrac{75}{-135}=\dfrac{(-15).(-5)}{(-15).9}=\dfrac{-5}9\)

`5/10=1/2`

`-18/-27=2/3`

-42/105=-2/5`

`75/-135=-5/9``

\(\dfrac{15}{27}=\dfrac{5}{9};\dfrac{35}{55}=\dfrac{7}{11};\dfrac{101}{909}=\dfrac{1}{9}\)

15/ 27 rút gọn thành 5/9

35/55 rút gọn thành 7/11

101/909 rút gọn thành 1/9

- Các phân số còn lại đều tối giản.

3/5 , 5/9 , 9/20 , 7/11 , 17/27 , 1/9

\(a.\dfrac{5}{10}=\dfrac{1}{2}=\dfrac{1\times3}{2\times3}=\dfrac{3}{6}\)

\(\dfrac{25}{75}=\dfrac{1}{3}=\dfrac{1\times2}{3\times2}=\dfrac{2}{6}\)

\(b.\dfrac{42}{56}=\dfrac{3}{4}=\dfrac{3\times2}{4\times2}=\dfrac{6}{8}\)

\(\dfrac{18}{48}=\dfrac{3}{8}\)

\(c.\dfrac{27}{81}=\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12}\)

\(\dfrac{57}{76}=\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)

\(\dfrac{35}{84}=\dfrac{5}{12}\)

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a.3/6 va 2/6     b.24/32 va12/32  c.912/2736  2052/2736 1140/2736 

a )   − 18 − 27 = ( − 18 ) : ( − 9 ) ( − 27 ) : ( − 9 ) = 2 3

b )   45 − 24 = 45 : ( − 3 ) ( − 24 ) : ( − 3 ) = − 15 8

27/81=1/3

57/76=3/4

35/84=5/12

27/81=1/3

57/76=3/4

35/84=5/12

567895464468457899999 hư đi em 

1) Các phân số tối giản là: \(\frac{1}{5};\frac{5}{7};\frac{-2}{9}\)

2) a) \(\frac{28}{36}=\frac{28:4}{36:4}=\frac{7}{9}\)

    b) \(\frac{-63}{90}=\frac{-63:9}{90:9}=\frac{-7}{10}\)

   c)  \(\frac{40}{-120}=\frac{40:40}{-120:40}=\frac{-1}{3}\)

3) a) \(\frac{2.4}{6.18}=\frac{2.2.2}{2.3.3.2.3}=\frac{2}{27}\)

   b)  \(\frac{3.5.7}{6.9.14}=\frac{3.5.7}{2.3.9.2.7}=\frac{5}{36}\) 

    c) \(\frac{4.7-4.5}{64}=\frac{4.\left(7-5\right)}{64}=\frac{4.2}{64}=\frac{8}{64}=\frac{1}{8}\)

4) Muốn rút gọn một phân số chưa tối giản, ta tìm ƯCLN của cả hai số ở tử và mẫu, rồi cùng đem cả tử và mẫu chia cho số chung vừa tìm được.

Kết quả rút gọn làn lượt là:  1 2 ; 1 2 ; − 1 5 ; 1 2 ; 3 8 ; 2 3 ; 3 2 ; − 5 9

\(\dfrac{24}{32}=\dfrac{24:8}{32:8}=\dfrac{3}{4}\)

\(\dfrac{45}{6}=\dfrac{45:3}{6:3}=\dfrac{15}{2}\)

\(\dfrac{75}{100}=\dfrac{75:25}{100:25}=\dfrac{3}{4}\)

\(\dfrac{27}{63}=\dfrac{27:9}{63:9}=\dfrac{3}{7}\)

\(\dfrac{24}{32}=\dfrac{24:8}{32:8}=\dfrac{3}{4}\)

\(\dfrac{75}{100}=\dfrac{75:25}{100:25}=\dfrac{3}{4}\)

\(\dfrac{45}{60}=\dfrac{45:15}{60:15}=\dfrac{3}{4}\)

\(\dfrac{27}{63}=\dfrac{27:9}{63:9}=\dfrac{3}{7}\)