12-\(\frac{12}{7}\)+\(\frac{12}{8}\)-\(\frac{12}{11}\)
11-\(\frac{11}{7}\)+\(\frac{11}{8}\)-\(\frac{11}{11}\)
\(\frac{-11}{12}.\frac{7}{8}+\frac{11}{12}.\left(\frac{-15}{16}\right)-\frac{11}{12}\)
=11/12*(-7/8+(-15/16)-1)
=11/12*(-45/16)
=-165/64
study well
k nha
ai k đúng cho mk mk trả lại gấp dôi
Trả lời
-11/12.7/8+11/12.(-15/16)-11/12
=-11/12(7/8+15/16-1)
=-11/12.13/16
=-143/192
Chắc z, sai sai
\(\frac{-11}{12}.\frac{7}{8}+\frac{11}{12}.\left(\frac{-15}{16}\right)-\frac{11}{12}\)
\(=\frac{11}{12}\left(\frac{-7}{8}-\frac{15}{16}-1\right)\)
\(=\frac{11}{12}\left(\frac{-14}{16}-\frac{15}{16}-\frac{16}{16}\right)\)
\(=\frac{11}{12}.\frac{-45}{16}=\frac{-165}{48}\)
\(\frac{\frac{5}{12}+\frac{1}{8}-\frac{7}{11}}{\frac{49}{11}-\frac{7}{8}-\frac{35}{12}}\)
\(\frac{5-\frac{5}{3}-\frac{5}{9}-\frac{5}{27}}{-8+\frac{8}{3}+\frac{8}{9}+\frac{8}{27}}:\frac{15-\frac{15}{11}-\frac{15}{121}}{16-\frac{16}{11}-\frac{16}{121}}\)
Tính:
a)\(\frac{5}{-7}+\frac{-7}{-8}-\frac{2}{7}+\frac{1}{8}-\frac{-1}{12}+\frac{-13}{12}\)
b)\(\frac{-3}{8}-\frac{12}{11}+\frac{3}{-5}+\frac{11}{8}-\frac{-1}{11}-\frac{2}{5}\)
Mình đang cần gấp . Bạn nào giúp thì mình cảm ơn nhiều !!!!!
a) =-5/7 +7/8-2/7+1/8- -1/12+ -13/12
=(-5/7-2/7)+(7/8+1/8)-(-1/12--13/12)
=-7/7+8/8 - 12/12
= -1+1+1
=1
b)= ( -3/8+11/8)-(12/11+ -1/11)+(-3/5- 2/5)
= 1- 1 + (-1)
=-1
12-\(\frac{12}{7}\)+\(\frac{12}{8}\)-\(\frac{12}{11}\)
11;\(\frac{11}{7}\) +\(\frac{11}{8}\)-\(\frac{11}{11}\)
đây la phân sô đây cac ban . tu sô la phân sô va mâu sô cung co phân sô
\(E = \frac{7}{19}. \frac{8}{11} + \frac{7}{19}. \frac{3}{11} + \frac{12}{19}\)
E = 7/19 . 8/11 + 7/19 . 3/11 +12/19
= 7/19 . ( 8/11 + 3/11 ) + 12/19
= 7/19 . 11/11 + 12/19
= 7/19 . 1 + 12/19
= 7/19 + 12/19
= 7 + 12 / 19
= 19/19
= 1
A=\(\frac{7}{19}x\frac{8}{11}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{7}{19}.\frac{8}{11}.\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\left(\frac{7}{19}\right)^2.\frac{8}{11}.\frac{11}{3}+\frac{12}{19}\)
\(\Rightarrow A=\left(\frac{7}{19}\right)^2.\frac{8}{3}+\frac{12}{19}\)
\(\Rightarrow A=\frac{392}{1083}+\frac{12}{19}\)
\(\Rightarrow A=\frac{1076}{1083}\)
Ta có 27^5=3^3^5=3^15
243^3=3^5^3=3^15
Vậy A=B
2^300=2^(3.100)=2^3^100=8^100
3^200=3^(2.100)=3^2^100=9^100
Vậy A<B
A=\(\frac{7}{19}x\frac{8}{11}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{56}{209}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{3971}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{1083}+\frac{12}{19}\)
\(A=\frac{1076}{1083}\)
\(\frac{X-6}{7}+\frac{X-7}{8}+\frac{X-8}{9}=\frac{X-9}{10}+\frac{X-10}{11}+\frac{X-11}{12}\)
\(\frac{x}{10}=\frac{y}{6}=\frac{z}{21}\)và \(5x+y-2z=28\)
\(\frac{6}{7}+\frac{9}{8}:9-\frac{3}{16}.2 \)
\(\frac{3}{11}.\frac{7}{12}+\frac{15}{38}+\frac{3}{11}.\frac{-19}{12}+\frac{23}{38}\)
6/7+9/8:9/1-3/16.2/1
6/7+9/8.1/9-3/16.2/1
6/7+1/8-3/8
48/56+7/56-21/56
17/28
3/11.[(7/12+-19/12)+(15/38+23/38)]
3/11.[-1+1]
3/11.0
0
\(\frac{6}{7}+\frac{9}{8}:9-\frac{3}{16}.2\)
\(=\frac{6}{7}+\frac{9}{8}.\frac{1}{9}-\frac{3}{8}\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3}{8}\)
\(=\frac{17}{28}\)