0,(8)=8/9

3,(5)=32/9

-17,(23)=-1706/99

-0,(45)=-45/99

0,3(8)=(38-1)/90=37/90

cách làm nữa bn ơi, mink ghi rõ rồi mà

1) \(0,\left(8\right)=\frac{8}{9}\) ( đây là quy tắc )
2) \(3,\left(5\right)=3+0,\left(5\right)=\frac{27}{9}+\frac{5}{9}=\frac{32}{9}\)
3) \(-17,\left(23\right)=-\left[17+0,\left(23\right)\right]=-\left[\frac{1683}{99}+\frac{23}{99}\right]=-\frac{1706}{99}\)
4) \(-0,\left(45\right)=-\frac{45}{99}=-\frac{5}{11}\) ( đây là quy tắc )
5) \(0,3\left(8\right)=0,3+0,0\left(8\right)=\frac{3}{10}+\frac{8}{9}:10=\frac{27}{90}+\frac{8}{90}=\frac{35}{90}=\frac{7}{18}\)

0,(32) =32/99

1,(5) =14/9

0,(25) =25/99

do ban k cho minh nha

\(0,\left(34\right)=0\left(01\right).34=\dfrac{1}{99}\)

\(0,\left(5\right)=0,\left(1\right).5=\dfrac{1}{9}.5=\dfrac{5}{9}\)

\(0,\left(123\right)=0,\left(001\right).123=\dfrac{1}{999}.123=\dfrac{123}{999}=\dfrac{41}{333}\)

\(\dfrac{34}{99};\dfrac{5}{9};\dfrac{41}{333}.\)

bn muốn tìm chu kì tí nữa mik ns sau

bay h mik lm bài 3

50,93x49,15-50,83x49,21

=\(2503,2095-2496.2095=6.4399\approx6.44\)

\(0,\left(1\right)=\dfrac{1}{9}\)

\(0,\left(01\right)=\dfrac{1}{99}\)

\(1,\left(8\right)=\dfrac{187}{99}=\dfrac{187:11}{99:11}=\dfrac{17}{9}\)

\(0,\left(27\right)=\dfrac{27}{99}=\dfrac{27:9}{99:9}=\dfrac{3}{11}\)