a, \(16.64.8^2:\left[4^3.2^5.16\right]\)
b, \(\left[125^3.7^5-175^5:5\right]:2016^{2017}\)
tinh
(125^3.7^5-175^5:5 ) : 2018^2019
16.64.8^2. ( 4^3.2^5.16 )
mong moi nguoi giup do
tính
16.64.8^2:(4^3.2^5.16)
(125^3.7^5-175^5:5):2001^2002
Bài 1
c)(125^3.7^5-175^5/5)/2001^2002
d)16.64.8^2/(4^3.2^5.16)
a, \(\frac{45^3.20^4.18^2}{180^5}\)
b, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
c, \(\left(125^3.7^5-175^5:5\right):2016^{2017}\)
d, \(16.64.8^2:\left(4^3.2^5.16\right)\)
e,\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^9.27^6}\)
Đề bài: Tính bằng cách hợp lí.
\(\frac{45^3.20^4.18^2}{180^5}=\frac{\left(3^2.5\right)^3.\left(2^2x5\right)^4.\left(2x3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)
\(=\frac{3^6.5^3.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)\(=\frac{3^{10}.5^7.2^{10}}{2^{10}.3^{10}.5^5}=\frac{5^7}{5^5}=5^2\)
Tính;
(6^2+7^2+8^2+9^2+10^2)-(1^2+2^2+3^2+4^2+5^2)
(125^3.7^5-175^5:5):2001^2002
16.64.8^2:(4^3.2^5.16)
(125^3.75-175^5:5):2001^2002
16.64.8^2:(4^3.2^5.16)
tinh (125^3.7^5+175^5:5) : 2016^2017
CỨU!!!!!!!!!!!!
(125^3.7^5+175^5:5) : 2016^2017=0
chắc chắn 100%%%%%%%%%%%%%%%%%%%%%%%% lun ak
Bài 1: Rút gọn biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\) \(B=\frac{15.3^{11}+4.27^4}{9^7}\) \(C=\left(125^3.7^5-175^5:5\right):2016^{2017}\)
Bài 2: Tìm x:
a)\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)b)\(\left|\frac{3}{13}x^2+\frac{1}{2}\right|-\frac{3}{4}=\frac{5}{6}\)
Bài 1: Rút gọn biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\) \(B=\frac{15.3^{11}+4.27^4}{9^7}\) \(C=\left(125^3.7^5-175^5:5\right):2016^{2017}\)
Bài 2: Tìm x:
a)\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)b)\(\left|\frac{3}{13}x^2+\frac{1}{2}\right|-\frac{3}{4}=\frac{5}{6}\)