Tính hợp lý :
a)( 68 × 1866 + 68 × 36 + 340 × 20 ) ÷ 2002
b)( 5 × 3^5 + 17 × 3^4 ) ÷ 6^3
tÍNH BẰNG CÁCH HỢP LÝ:
a.4525-(864-999)-(36+3999)
b.(-35).68+32.(-35)
c.(-23).43+77.(-43)
d.(-25).68+(-34).(-250)
e.1-2+3-4++5-6+...+2017-2018+2019
f.1+3-5-7+9+11-...-397-399
tính hợp lí
a 36*105-36*5
b 2*169*12-3*68-24
c 2*56*24-3*36*16+4*12*95-6*3*8*5
a) 36.105-36.5
= 36(105-5)
=36.100
= 3600
tíc mình nha
Đặt tính rồi tính
a)68 : 2 69 : 3 44 : 4 99 : 3
............ ............ ........... ...........
............ ............ ........... ...........
............ ............ ........... ...........
b)42 : 6 45 : 5 36 : 4 16 : 2
............ ............ ........... ...........
............ ............ ........... ...........
............ ............ ........... ...........
bài 1 tính hợp lý
3200:40+60:15-135:5+7
36*68+56*64*......-36*12
S=2018+2016+2014+....+2-2017-2015-3-1
Dùng tính chất để tính
a) 17/5 . -31/125 . 1/2 . 10/17 . -1/23
b) (11/4 . -5/9 - 4/9 . 11/4) . 8/33
c) (17/28 + 18/29 - 19/30 - 20/31) . (-5/12 + 1/4 + 1/6)
d) -1/4 . 15^2/11 + 68/4 . -1/11
e) -9/25 . 53/3 - (-3/5)^2 .22/3
tính bằng cách hợp lý( tính nhanh):
a) 53:52+96.
b) 21*16+37*31+21*63
c) 35*48+65*68+20*35
d)711:79-62+23*2
a)0,75 + 15/6 : 5 - 1/36 . (-3)2 + (-2020/2021)
b)45. 94 - 2 . 69/210 . 38 + 68 . 20
b: \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{11}\cdot3^9}\)
\(=\dfrac{1}{2}\cdot\dfrac{-2}{3}=\dfrac{-1}{3}\)
Sửa đề câu a) phải là (-2020/2021)0
Xin lỗi mn
\(a,=\dfrac{3}{4}+\dfrac{15}{6}\cdot\dfrac{1}{5}-\dfrac{1}{36}\cdot9-\dfrac{2020}{2021}=\dfrac{3}{4}+\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{2020}{2021}=1-\dfrac{2020}{2021}=\dfrac{1}{2021}\\ b,=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^9\cdot3^8\left(2+5\right)}=\dfrac{2\left(-2\right)}{3}=-\dfrac{4}{3}\)
Thực hiện phép tính (Tính hợp lý nếu có thể)
a) -10/13 + 5/17 – 3/13 + 12/17 – 11/20
b) 3/4 + -5/6 – 11/-12
c) [13. 4/9 + 2. 1/9] – 3. 4/9
d) 1,25 : 15/20 + [25% – 5/6] : 4. 2/3
Tìm x, biết
a)x – 1/3 = 5/14 . -7/6
b) 3/4 + 1/4 x = 0,2
c) 1/12 .x2 = 1. 1/3
a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
d; 1,25 : \(\dfrac{15}{20}\) + [25% - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)
= 1,25 x \(\dfrac{20}{15}\) + [\(\dfrac{1}{4}\) - \(\dfrac{5}{6}\)] : 4.\(\dfrac{2}{3}\)
= \(\dfrac{5}{3}\) - \(\dfrac{7}{12}\) : 4 x \(\dfrac{2}{3}\)
= \(\dfrac{5}{3}\) - \(\dfrac{7}{48}\).\(\dfrac{2}{3}\)
= \(\dfrac{5}{3}\) - \(\dfrac{7}{72}\)
= \(\dfrac{113}{72}\)
1, Thực hiện phép tính ( tính hợp lý nếu có thể) A, -1/12+4/3 B,(-4/14-3/15)-(1/5-20/35- -1)7 C, 3/5+ -5/20+30/75+ -7/4 D, 5/6. -12/13 + 7/13 E, 2/-9 - 5/-36 - 1/4 F, 2/23 +-5/12+7/18+21/23+ -7/12
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18