2x̣(2x-6)(3x-5)=0 

=> 2x=0 hoặc 2x-6=0 hoặc 3x-5=0

x=0 hoặc x=6/2=3 hoặc x=5/3

vì x E N nên x=0 hoặc x=3

\(A=\left\{25;26;27;28;29;30\right\}\\ B=\left\{11;12;13;14\right\}\\ C=\left\{1;2;5;10\right\}\\ D=\left\{14;16;18;20\right\}\)

\(A=\left\{25;26;27;28;29;30\right\}\)

\(B=\left\{11;12;13;14\right\}\)

\(C=\left\{1;2;5;10\right\}\)

\(D=\left\{14;16;18;20\right\}\)

Bài 1:

\(N=2x^2+4y^2-2x-4y+15=2\left(x^2-x+\dfrac{1}{4}\right)+\left(4y^2-4y+1\right)+\dfrac{27}{2}=2\left(x-\dfrac{1}{2}\right)^2+\left(2y-1\right)^2+\dfrac{27}{2}\ge\dfrac{27}{2}\)

\(minN=\dfrac{27}{2}\Leftrightarrow x=y=\dfrac{1}{2}\)

Bài 2:

\(\Leftrightarrow4x^2+12x+9-25x^2+50x-25=0\)

\(\Leftrightarrow21x^2-62x+16=0\)

\(\Leftrightarrow\left(3x-8\right)\left(7x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=\dfrac{2}{7}\end{matrix}\right.\)

Ta có : x² - 2x + 1 = 25

=> x² - 2.x.1 + 1² = 25

=> (x - 1)² = 25

Mà 25 = 5² ; (-5)²

=> \(\orbr{\begin{cases}\left(x-1\right)^2=5^2\\\left(x-1\right)^2=\left(-5\right)^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)

Vậy x = {-4;6}

b) (5 - 2x)² + 1 = 25

<=> (5 - 2x)² = 24 

\(\Rightarrow\orbr{\begin{cases}5-2x=\sqrt{24}\\5-2x=-\sqrt{24}\end{cases}}\Rightarrow\orbr{\begin{cases}2x=5-2\sqrt{6}\\2x=5+2\sqrt{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5-2\sqrt{6}}{2}\\x=\frac{5+2\sqrt{6}}{2}\end{cases}}\)

a) đặt [41-(2x-5)] là a <=> 1440 : a = 48
=> a = 30 <=> [41-(2x-5)] = 30   => 41-(2x-5) =30
<=> -(2x-5) = -11 <=> 2x-5 = 11 <=> 2x = 16 <=> x=2

b) tương tự câu a
gợi ý đáp án : x = 210

Đáp án là D