\(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=1+1=2\)

2

= 2

a, \(x\in\left\{-5;-4;-3;-2;-1;0;1;2;3;4;5\right\}\)

Tổng các x thoả mãn: (-5+5)+(-4+4)+(-3+3)+(-2+2)+(-1+1)+0=0+0+0+0+0+0=0

b, \(x\in\left\{-3;-2;-1;0;1;2\right\}\)

Tổng các x thoả mãn: (-2+2) + (-1+1) + 0 + (-3) = 0 + 0 + 0 + (-3) = -3

c, \(x\in\left\{-1;0;1;2;3;4\right\}\)

Tổng các x thoả mãn: (-1+1) + 0 + 2 + 3 + 4 = 9

Tương tự cháu làm các câu d,e,f rồi gửi lên lại thầy check cho hí

\(\text{a) -5 ≤ x < 6 }\)

\(x\in\left\{-5;-4;-3;-2;-1;0;1;2;3;4;5\right\}\)

\(\text{b) -4 < x < 3}\)

\(x\in\left\{-3;-2;-1;0;1;2\right\}\)
\(\text{c) -1 ≤ x ≤ 4}\)

\(x\in\left\{-1;0;1;2;3;4\right\}\)               

\(\text{d) -5 < x < 2}\)

\(x\in\left\{-4;-3;-2;-1;0;1\right\}\)
\(\text{e) -5 < x < 5 }\)

\(x\in\left\{-4;-3;-2;-1;0;1;2;3;4\right\}\)

\(\text{f) -6 < x ≤ 4}\)

\(x\in\left\{-5;-4;-3;-2;-1;0;1;2;3;4\right\}\)

a,|x|=5

\(\Rightarrow x=\pm5\)

b,|x-2|=0

\(\Rightarrow x-2=0\)

x=0+2

x=2

\(\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}\)

=>\(\frac{x}{3}=\frac{11}{21}\)

=>x=\(\frac{11}{21}\cdot3=\frac{33}{21}\)

=>x=\(\frac{11}{7}\)

=>x/3 =11/21

Theo tính chất p số = nhau

=>x.21=3.11

x        =33:21=11/7

\(x=\dfrac{4}{7}:\dfrac{3}{5}=\dfrac{4\times5}{7\times3}=\dfrac{20}{21}\)

=>x=4/7:3/5

x=4/7 x 5/3

x=20/21

\(\dfrac{3}{5}\times x=\dfrac{4}{7}\\ x=\dfrac{4}{7}:\dfrac{3}{5}\\ x=\dfrac{4}{7}\times\dfrac{5}{3}\\ x=\dfrac{20}{21}\)

Câu 2: 

a: \(1DE_{16}=478_{10}\)

c: \(65_{10}=\text{1000001}_2\)

a, Ta có : \(\frac{x}{y}=\frac{1}{3}\Leftrightarrow\frac{x}{1}=\frac{y}{3}\)

Áp dụng t/c dãy tỉ số bằng nhau ta có : 

\(\frac{x}{1}=\frac{y}{3}=\frac{x-3y}{1-3.3}=\frac{1}{\frac{2}{-8}}=-\frac{1}{16}\)

\(x=-\frac{1}{16};y=-\frac{3}{16}\)

Ai giúp mik nhé

a: \(=1-\dfrac{7}{10}=\dfrac{3}{10}\)

b: \(=\dfrac{42}{36}+\dfrac{15}{36}-\dfrac{2}{36}-\dfrac{36}{36}=\dfrac{19}{36}\)

c: \(=\dfrac{144}{48}+\dfrac{132}{48}-\dfrac{4}{48}-\dfrac{9}{48}=\dfrac{263}{48}\)