-1997*1996+1/-1995*(-1997)+1996

=-1997*(1995+1)+1/-1*1995*(-1)*1997+1996

=-1997*1995+(-1997)+1/1995*1997+1996

=-1*1997*1995+(-1996)/1995*1997+1996

=-1

a) \(\dfrac{1997x1996-1}{1995x1997+1996}=\dfrac{1997x\left(1995+1\right)-1}{1995x1997+1996}\)

\(=\dfrac{1997x1995+1997-1}{1995x1997+1996}=\dfrac{1997x1995+1996}{1995x1997+1996}=1\)

b) \(\dfrac{1997x1996-995}{1995x1997+1002}=\dfrac{1997x\left(1995+1\right)-995}{1995x1997+1002}\)

\(=\dfrac{1997x1995+1997-995}{1995x1997+1002}=\dfrac{1997x1995+1002}{1995x1997+1002}=1\)

\(\dfrac{1998.1996+1997+1995}{1997.1996-1995.1996}\)

\(=\dfrac{1998.1996}{1997.1996-1995.1996}+\dfrac{1997+1995}{1997.1996-1995.1996}\)

\(=\dfrac{1998.1996}{1996\left(1997-1995\right)}-\dfrac{1997-1995}{1996\left(1997-1995\right)}\)

\(=\dfrac{1998}{1997-1995}-\dfrac{1}{1996}\)

\(=\dfrac{1998}{2}-\dfrac{1}{1996}\)

\(=999-\dfrac{1}{1996}\)

\(\approx998,99\)

1000

 tự làm là hạnh phúc của mỗi công dân.

$\frac{1988.1996+1997+1995}{1997.1996-1995.1996}$

=> $\frac{1996.(1988+2)}{1996.(1997-1995)}$

=> $\frac{1996.1990}{1996.2}$

=> $\frac{1990}{2}$

=> 995

\(\frac{1988\cdot1996+1997+1995}{1997\cdot1996-1995\cdot1996}\)

=\(\frac{1996\cdot\left(1988+2\right)}{1996\cdot\left(1997-1995\right)}\)

=\(\frac{1996\cdot1990}{1996\cdot2}\)

=\(\frac{1990}{2}\)=995

KQ = 995

Mình mới giải xong, mất tiêu bài rồi KQ=1000

\(...=\dfrac{1998x1996+1996+1+1996-1}{\left(1997-1995\right)x1996}\)

\(=\dfrac{1998x1996+2x1996}{2x1996}=\dfrac{1996\left(1998+2\right)}{2x1996}=\dfrac{2000}{2}=1000\)

KQ = 995 nha

995

-1x1996+1/-1995x(-1)+1996=-1996+1/1995+1996

-3984016,001

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