A: Al..................................................D:Al₂O₃

B: Ca(AlO₂)₂.....................................E:AlCl₃

C: Al(OH)₃

Ta có các phương trình phản ứng sau:

Al + Ca(OH)₂ + H₂O ➞ Ca(AlO₂)₂ + H₂

Ca(AlO₂)₂ + 2 HCl + 2 H₂O ➞ 2 Al(OH)₃ + CaCl₂

2 Al(OH)₃ ➞_t^O Al₂O₃ + 3 H₂O

2 Al₂O₃ ➞(đpnc) 4 Al + 3 O₂

2 Al + 3 FeO ➞ Al₂O₃ + 3 Fe

Al₂O₃ + 6 HCl ➞ 2 AlCl₃ + 3 H₂O

2 AlCl₃ + 3 Mg ➞ 2 Al + 3 MgCl₂

A là CuO hoặc Cu(OH)₂

a

\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\\ CuSO_4+2NaOH\rightarrow Cu\left(OH\right)_2+Na_2SO_4\)

b

\(Mg+Cl_2\underrightarrow{t^o}MgCl_2\)

\(MgCl_2+2NaOH\rightarrow Mg\left(OH\right)_2+2NaCl\)

c

\(2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O\)

\(Na_2SO_4+BaCl_2\rightarrow BaSO_4+2NaCl\)

d

\(K_2CO_3+CaCl_2\rightarrow CaCO_3+2KCl\)

\(CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2\)

1) Na₂O + H₂O \(\rightarrow\)2NaOH

2) 2NaOH+ SO₂ \(\rightarrow\)Na₂SO₃ + H₂O

3) Na₂SO₃ + H₂SO_{4\(\rightarrow\)} Na₂SO₄ + H₂O+ CO₂

4)SO₂ + 2KOH \(\rightarrow\)K₂SO₃ + H₂O

1.Na2O+H2O--->2NaOH

2.2NaOH+SO2--->Na2SO3+H2O

3.Na2SO3+H2SO4--->Na2SO4+H2O+CO2

4.2KOH+SO2--->K2SO3+H2O

1)(-C6H10O5-)n +nH2O -axit ;t^o-> nC6H12O6

2) C6H12O6 --men ; 30^o-32^oC--> 2C2H5OH + 2CO2

3) C2H5OH + 3O2 -t^o-> 2CO2 + 3H2O

4) CO2 + 2NaOH -> Na2CO3 + H2O

5) Na2CO3 + 2CH3COOH -> 2CH3COONa + H2O + CO2

6) 2C2H5OH + 2Na -> 2C2H5ONa + H2

7) C2H5OH + CH3COOH -> H2O + CH3COOC2H5

(đk: H2SO4 đ ; t^o)

(1) (C₆H₁₀O₅)_n + nH2O => nC₆H₁₂O₆

(2) C₆H₁₂O₆ => (men rượu, t^o) 2CO₂ + 2C₂H₅OH

(3) C2H5OH + 3O2 => (t^o) 2CO2 + 3H2O

(4) CO2 + 2NaOH => Na2CO3 + H2O

(5) Na2CO3 + 2CH3COOH => 2CH3COONa + CO2 + H2O

(6) C2H5OH + Na => C2H5ONa + 1/2 H2

(7) C2H5OH + CH3COOH => (t^o,xt: H2SO4đ) <pứ hai chiều> CH3COOC2H5 + H2O

C2H5OH+3O2-to>2CO2+3H2O

b>

CO+O2-to>CO2

CO2+NaOH->NaHCO3

2NaHCO3-to>Na2CO3+H2O

Na2CO3+HCl->NaCl+H2O+CO2

NaCl+H2O-đp>NaOH+Cl2+H2

\(a) C_2H_5OH + 3O_2 \xrightarrow{t^o} 2CO_2 + 3H_2O\\ b)\\ (1)2CO + O_2 \xrightarrow{t^o} 2CO_2\\ (2)CO_2 + NaOH \to NaHCO_3\\ (3)2NaHCO_3 \xrightarrow{t^o} Na_2CO_3 + CO_2 + H_2O\\ (4) Na_2CO_3 + 2HCl \to 2NaCl +C O_2 + H_2O\\ (5) 2NaCl + 2H_2O \xrightarrow{điện\ phân\ dung\ dịch} 2NaOH + H_2+ Cl_2 \)

c

B

\(n_{C_4H_6} = n.n_{cao\ su} = n.\dfrac{1000}{54n} = \dfrac{500}{27}(kmol)\\ n_{C_2H_5OH} = 2.\dfrac{1}{60\%}.n_{C_4H_6} = \dfrac{5000}{81}(kmol)\\ n_{C_6H_{12}O_6} = \dfrac{1}{2}.\dfrac{1}{80\%}.n_{C_2H_5OH} = \dfrac{3125}{81}(kmol)\\ m_{gỗ} = \dfrac{m_{C_6H_{12}O_6}}{35\%} = \dfrac{\dfrac{3125}{81}.180}{35\%} = 19841,25(kg)\)