\(A=1.2+2.3+...+25.26\)

\(\Rightarrow3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+25.26.\left(27-24\right)\)

\(=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+25.26.27-24.25.26\)

\(\Rightarrow3A=25.26.27\)

\(\Rightarrow A=25.26.9\)

M=1.2+2.3+3.4+...+19.20

3.M=1.2.3+2.3.3+3.4.3+...+19.20.3

3.M=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+19.20.(21-18)

3.M=(1.2.3-0.1.2)+(2.3.4-1.2.3)+(3.4.5-2.3.4)+...+(19.20.21-18.19.20)

Những cái bị gạch là giản ước.

3.M=19.20.21-0.1.2

3.M=7980-0

3.M=7980

M=7980:3

M=2660

Vậy M=2660

Dấu . là dấu nhân

2432902008176640000

\(\frac{1}{1x2}+\frac{1}{1x3}+...+\frac{1}{999x1000}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{999}-\frac{1}{1000}\)

\(=1-\frac{1}{1000}\)

\(=\frac{999}{1000}\)

1/1x2+1/2x3+1/3x4+...+1/999x1000

=1-1/2+1/2-1/3+1/3-1/4+...+1/999-1/1000

=1-1/1000

=1000/1000-1/1000

=999/1000

999 / 1000

\(\frac{3}{1.2}+\frac{3}{2.3}+\frac{3}{3.4}+...+\frac{3}{14.15}\)

\(=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{14.15}\right)\)

\(=3.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{14}-\frac{1}{15}\right)\)

\(=3.\left(1-\frac{1}{15}\right)\)

\(=3.\frac{14}{15}\)

\(=\frac{14}{5}\)

Cảm ơn bạn rất nhiều nhé

:D

\(C=1.2+2.3+3.4+...+x.\left(x-1\right)\)

\(\Rightarrow3C=1.2.3+2.3.3+3.4.3+...+x.\left(x-1\right).3\)

\(\Rightarrow3C=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+x.\left(x-1\right).\left[\left(x+1\right)-\left(x-2\right)\right]\)

\(\Rightarrow3C=\left(1.2.3-0.12\right)+\left(2.3.4-1.2.3\right)+\left(3.4.5-2.3.4\right)+...+\left[x.\left(x-1\right)\left(x+1\right)-x.\left(x-1\right)\left(x-2\right)\right]\)

\(\Rightarrow3C=-0.1.2+x.\left(x-1\right)\left(x+1\right)\)

\(\Rightarrow3C=x.\left(x-1\right)\left(x+1\right)\)

\(\Rightarrow C=\dfrac{x.\left(x-1\right)\left(x+1\right)}{3}\)

3C=1x2x3+2x3x3+3x4x3+...+Xx(X+1)=

=1x2x3+2x3x(4-1)+3x4x(5-2)+...+Xx(X+1)[(X+2)-(X-1)]=

=1x2x3-1x2x3+2x3x4-2x3x4+3x4x5-...-(X-1)xXx(X+1)+Xx(X+1)x(X+2)=

=Xx(X+1)(X+2)

`x/(x+1)=1/(1xx2)+1/(2xx3)+1/(3xx4)+...+1/(31xx32)`

`=>x/(x+1)=1-1/2+1/2-1/3+1/3-1/4+...+1/31-1/32`

`=>x/(x+1)=1-1/32`

`=>x/(x+1)=31/32`

`=>32x=31(x+1)`

`=>32x=31x+31`

`=>32x-31x=31`

`=>x=31`

31/31

A=1*2+2*3+...+2014*2015

3A=1*2*3+2*3*(4-1)+...+2014*2015*(2016-2013)

3A=1*2*3+2*3*4-1*2*3+...+2014*2015*2016-2013*2014*2015

3A=2014*2015*2016

A=2014*2015*2016/3

A=2727117120