\(\frac{\left|x\right|}{186}=\left(1-\frac{303030}{313131}\right)+\left(\frac{616161}{626262}-1\right)+\left(\frac{929291}{939393}-1\right)\)

<=> \(\frac{\left|x\right|}{186}=-\frac{303030}{313131}+\frac{616161}{626262}+\frac{929292}{939393}+1-1-1\)

<=> \(\frac{\left|x\right|}{186}=-\frac{30}{31}+\frac{61}{62}+\frac{92}{93}+1-1-1\)

<=> \(\frac{\left|x\right|}{186}=\frac{61}{62}+\frac{92}{93}-1-\frac{30}{31}\)

<=> \(\frac{\left|x\right|}{186}=-\frac{1.31}{31}+\frac{61}{62}+\frac{92}{91}-\frac{30}{31}\)

Lấy MSC là 168, ta có:

<=> \(\frac{\left|x\right|}{186}=\frac{-186}{186}+\frac{183}{186}+\frac{184}{186}-\frac{180}{186}\)

<=> \(\frac{\left|x\right|}{186}=\frac{-186+183+184-180}{186}\)

<=> \(\frac{\left|x\right|}{186}=\frac{1}{186}\)

<=> |x| = 1

<=> \(\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

=> \(\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

x/186 = (1 - 303030/313131) + (616161/626262 - 1) + (929292/939393 - 1)

x/186 = 1 - 30/31 + 61/62 - 1 + 92/93 - 1

x/186 = 61/62 - 30/31 + 92/93 - 1

x/186 = 1/62 - 1/93

x/186 = 1/186

x = 1

\(\pm3\)

\(\frac{|x|}{186}=\left(1-\frac{30}{31}\right)+\left(\frac{60}{61}-1\right)\)

\(\Leftrightarrow|x|=186\left(\frac{1}{31}-\frac{1}{61}\right)\)

\(\Leftrightarrow|x|=6-\frac{186}{61}\)

\(\Leftrightarrow|x|=\frac{180}{61}\)

\(\Leftrightarrow x=\pm\frac{180}{61}\)

\(\frac{|x|}{186}=\left(1-\frac{303030}{313131}\right)+\left(\frac{616161}{626262}-1\right)\)

\(\frac{|x|}{186}=\left(1-\frac{30}{31}\right)+\left(\frac{61}{62}-1\right)\)

\(\frac{|x|}{186}=1-\frac{30}{31}+\frac{61}{62}-1\)

\(\frac{|x|}{186}=\left(1-1\right)+\left(\frac{61}{62}-\frac{30}{31}\right)\)

\(\frac{|x|}{186}=\frac{1}{62}\)

\(\Rightarrow|x|=186.\frac{1}{62}\)

\(|x|=3\)

\(\Rightarrow x=\pm3\)

\(1-\frac{303030}{313131}+\frac{616161}{626262}-1+\frac{929292}{939393}-1=\left(1-\frac{30}{31}\right)+\left(\frac{61}{62}-1\right)+\left(\frac{92}{93}-1\right)\)

\(=\frac{1}{31}-\frac{1}{62}-\frac{1}{93}=\frac{1}{186}\)

=> \(\frac{\left|x\right|}{186}=\frac{1}{186}\)=> |x| = 1 => x = 1 hoặc x = - 1

Vậy...............

303030/313131=30/31(1)

616161/626262=61/62(2)

929292/939393=92/92(3)

từ 1,2,3=>tự làm

phải làm mới đc **** chứ !

x = 184

xim may ban trnh bay chi tiet duoc khong 

cam on rat nhieu

a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)

b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)

\(\dfrac{-5}{6}-\left(\dfrac{-3}{8}+\dfrac{1}{10}\right)\)
\(\dfrac{-5}{6}-\dfrac{-3}{8}-\dfrac{1}{10}\)
 

a,   11/13 - ( 5/42 - x ) = - (5/28 - 11/13)

    11/13 - (5/42 - x) = - 5/28 + 11/13

    - (5/42 - x) + 5/28 = -11/13 + 11/13

 - 5/42 + x + 5/28 = 0

- 5/42 + x = 0 - 5/28

- 5/42 + x = - 5/28

x = -5/28 +5/42

x = - 5/84

b, / x + 4/15 \ - / - 3,75 \ = - / - 2,15 \

./ x + 4/15 \ - 3,75 = - 2,15

/ x + 4/15 \ = -2,15 + 3,75

/ x + 4/15 \ = 1,6

x + 4 / 15 = 1,6                      hoặc x+ 4/15 = - 1,6

x = 1,6 - 4/15                                   x = - 1,6 -4/15

x = 4/3                                              x = -28/15

Vậy x = 4/3 hoặc x = - 28/15

c, ( 0,25 - 30% x ) . 1/3 = 1/4 - 31/6

( 1/4 - 3/10 x ) . 1/3 = - 59/12

( 1/4 - 3/10 x ) = - 59/12 : 1/3

1/4 - 3/10 x = - 59/4

3/10 x = 1/4 + 59/4

3/10 x = 15

x = 15 : 3/10

x = 50

d, ( x - 1/2 ) : 1/3 + 5/7 = 68/7

( x - 1/2 ) : 1/3 = 68/7 - 5/7

( x - 1/2 ) : 1/3 = 63/7

( x - 1/2 ) = 63/7 . 1/3

x -1/2 = 3 

x = 3 + 1/2

x = 7/2

/ là phân số nha

11/13-(5/42-x)=(15/28-11/13)

11/13-(5/42-x)=-37/182

(5/42-x)=11/13+37/182

(5/42-x)=191/182

x=5/42-191/182

x=-254/273

vậy x=-254/273

bạn ấn vào chữ M nằm ngang ở dưới câu hỏi khi bạn trả lời là sẽ ấn được phân số nhé 

còn gửi câu trả lời cũng tương tự 

\(b,x+\frac{1}{3}=\frac{2}{5}-\left(-\frac{1}{3}\right)\)

\(< =>x+\frac{1}{3}=\frac{2}{5}+\frac{1}{3}\)

\(< =>x=\frac{1}{3}-\frac{1}{3}+\frac{2}{5}=\frac{2}{5}\)

\(c,\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)

\(< =>\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}=-\frac{29}{70}\)

\(< =>x=\frac{-29}{70}:\frac{2}{3}=-\frac{7}{140}\)

\(d,\frac{3}{7}-x=\frac{1}{4}-\left(-\frac{3}{5}\right)\)

\(< =>\frac{3}{7}-\frac{1}{4}-\frac{3}{5}=x\)

\(< =>x=-\frac{59}{140}\)

\(e,-\frac{21}{12}x+\frac{1}{3}=-\frac{2}{3}\)

\(< =>-\frac{21}{12}x=-\frac{2}{3}-\frac{1}{3}=-1\)

\(< =>x=\frac{12}{21}\)