1,10²⁰và 90¹⁰

ta có:+,10²⁰=(10²)¹⁰=100¹⁰

        +,90¹⁰=90¹⁰

vì 100¹⁰>90¹⁰=>10²⁰>90¹⁰

2,(1/16)¹⁰ và (1/2)⁵⁰

ta có:+, (1/16)¹⁰=(1/16)¹⁰

         +,(1/2)⁵⁰=(1/2⁵)¹⁰=(1/32)¹⁰

vì (1/16)¹⁰>(1/32)¹⁰=>(1/16)¹⁰>(1/2)⁵⁰

k mik nhé

\(a,\)  \(10^{20}=10^{10+10}=10^{10}.10^{10}\)

        \(90^{10}=9^{10}.10^{10}\)

  Vì \(10^{10}.10^{10}>9^{10}.10^{10}\)

    \(\Rightarrow10^{20}>90^{10}\)

Vậy \(10^{20}>90^{10}\)

\(b,\)\(\left(\frac{1}{16}\right)^{10}=\frac{1^{10}}{16^{10}}=\frac{1}{\left(4^2\right)^{10}}=\frac{1}{4^{20}}\)

   \(\left(\frac{1}{2}\right)^{50}=\frac{1^{50}}{2^{50}}=\frac{1}{\left(2^2\right)^{25}}=\frac{1}{4^{25}}\)

Vì \(\frac{1}{4^{20}}>\frac{1}{4^{25}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

                         ~~~~~~~~~~Hok tốt~~~~~~~~~~~

Bài 3: 

Ta có: \(10^{20}=10^{2.10}=\left(10^2\right)^{10}=100^{10}\)

Vì \(90< 100\)\(\Rightarrow90^{10}< 100^{10}\)

hay \(10^{20}>90^{10}\)

Câu 1.99²⁰và 9999¹⁰

⁼(99²)¹⁰=9801¹⁰

Vậy 9801¹⁰<9999¹⁰ suy ra  99²⁰<9999¹⁰

Câu 2. 3⁵⁰⁰và 7³⁰⁰

 3⁵⁰⁰=(3⁵)¹⁰⁰=243¹⁰⁰

7³⁰⁰=(7³)¹⁰⁰=343¹⁰⁰

Vậy 243¹⁰⁰<343¹⁰⁰ => 3⁵⁰⁰<7³⁰⁰

ta có 10²⁰=(10²)¹⁰=100¹⁰>9¹⁰

Vậy 10²⁰>9¹⁰

Chúc học tốt!

10^20 và 9^10

10^20=(10^2)^10=100^10

Vì 100^10>9^10=>10^20>9^10

Vậy 10^20>9^10

giải chi tiết giúp mình nhé

\(2^{333}< 3^{222}\)

a

nAK.DNX. 0pwi9dOjkciopjopoijasd

=

\(4^{20}=\left(2^2\right)^{20}=2^{40}\)

\(8^{10}=\left(2^3\right)^{10}=2^{30}\)

\(2^{40}>2^{30}\)\(\Rightarrow4^{20}>8^{10}\)

\(4^{20}=\left(2^2\right)^{20}=2^{40}\)

\(8^{10}=\left(2^3\right)^{10}=2^{30}\)

\(\Rightarrow2^{40}>2^{30}\)

\(\Rightarrow4^{20}>8^{10}\)