50 % + \(\frac{7}{12}\) - \(\frac{1}{2}\)
125 - 25 : 3 * 12
( 2013 * 2014 + 2014 * 2015 + 2015 * 2016 ) * ( 1 + \(\frac{1}{3}\) - \(\frac{4}{3}\) )
17,75 + 16, 25 +14,75 + 13,25 + ... 4,25 + 2,75 + 1,25
Những câu hỏi liên quan
1.
a) (2013*2014+2014*2015+2015*2016) * \(\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)
b) 17,75 +16,25 + 14,75 + 13,25 +.....+ 4,25 +2,75 +1,25
Giải rõ ràng giúp mk ạ...!!!!
1.
a,\(\left(2013\times2014+2014\times2015+2015\times2016\right)\times\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)
\(=\left(2013\times2014+2014\times2015+2015\times2016\right)\times\left(1\frac{1}{3}-1\frac{1}{3}\right)\)
\(=\left(2013\times2014+2014\times2015+2015\times2016\right)\times0\)
\(=0\)
b, \(17,75+16,25+14,75+13,25+...+4,25+2,75+1,25\)
\(=\left(17,75+1,25\right)+\left(16,25+2,75\right)+...+9,75\)
\(=19\times7+9,75\)
\(=142,75\)
Hok Tốt!!!!
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\(a,\left(2013×2014+2014×2015+2015×2016\right)×\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)
\(=A×\left(1+\frac{1}{3}-\frac{4}{3}\right)\)
\(=A×\left(\frac{4}{3}-\frac{4}{3}\right)\)
\(=A×0\)
\(=0\)
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1a. (2013*2014+2014*2015+2015*2016) * \(\left(1+\frac{1}{3}-1\frac{1}{3}\right)\)
= (2013*2014+2014*2015+2015*2016) * 0
= 0
b. 17,75 + 16,25 + 14,75 + 13,25 + ... + 4,25 + 2, 75 + 1,25
= (17,75+1,25) + (16,25+2,75)+... + 9,75
= 19 x 7 + 9,75
= 142,75
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A ( 2013 x 2014 + 2014 x 2015 + 2015 x 2016 ) x ( 1 + 1/3 - 1 và 1/3 )
B 17,75 + 16,25 + 14,75 + 13,25 + .........+ 4,25 + 2,75 + 1,25
A.
Xét \(1+\frac{1}{3}-1\frac{1}{3}=1\frac{1}{3}-1\frac{1}{3}=0\)
=> A = 0 ( vì số nào nhân vs 0 cx bằng 0 )
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Bài 1 : Tính :a)frac{left(13frac{1}{4}-2frac{5}{27}-10frac{5}{6}right)times230frac{1}{5}+46frac{3}{4}}{left(1frac{3}{10}+frac{10}{3}right)divleft(12frac{1}{3}-14frac{2}{7}right)}b) frac{2^{12}times3^5-4^6times9^2}{left(2^4times3right)^6+8^4times3^5}-frac{5^{10}times7^3-25^5times49^2}{left(125times7right)^3+5^9times14^3}c)Pfrac{frac{1}{2}+frac{1}{3}+frac{1}{4}+....+frac{1}{2016}}{frac{2015}{1}+frac{2014}{2}+frac{2013}{3}+....+frac{1}{2015}}
Đọc tiếp
Bài 1 : Tính :
a)\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\times230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
b) \(\frac{2^{12}\times3^5-4^6\times9^2}{\left(2^4\times3\right)^6+8^4\times3^5}-\frac{5^{10}\times7^3-25^5\times49^2}{\left(125\times7\right)^3+5^9\times14^3}\)
c)P=\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2016}}{\frac{2015}{1}+\frac{2014}{2}+\frac{2013}{3}+....+\frac{1}{2015}}\)
Xem thêm câu trả lời
thực hiện phép tính bằng cách thuận tiệna, 50% + 7/12 -1/2 b,2014 . 65+2014.45-2014.10c,125-25:3.12 d,(2013.2014+2014.2015+2015+2016)+(1+1/3-1và 1/3)e,17,75+16,25+14,75+13,25+...........+4,25+2,75+1,25đúng hết thì mình tick cho nha!
Đọc tiếp
thực hiện phép tính bằng cách thuận tiện
a, 50% + 7/12 -1/2 b,2014 . 65+2014.45-2014.10
c,125-25:3.12 d,(2013.2014+2014.2015+2015+2016)+(1+1/3-1và 1/3)
e,17,75+16,25+14,75+13,25+...........+4,25+2,75+1,25
đúng hết thì mình tick cho nha!
50% + 7/12 - 1/2
= 1/2 + 7/12 - 1/2
= (1/2 - 1/2) + 7/12
= 0 + 7/12 = 7/12
b) 2014 . 65 + 2014 . 45 - 2014 .10
= 2014 . (65 + 45 - 10)
= 2014 . 100 = 201400
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\(2014.65+2014.45-2014.10\)
\(=2014.\left(65+45-10\right)\)
\(=2014.100=201400\)
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\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2015}+\frac{1}{2016}}{\frac{2015}{1}+\frac{2014}{2}+\frac{2013}{3}+...+\frac{1}{2014}+\frac{1}{2015}}\)
xét mẫu(chỗ 1/2014 sửa lại thành 2/2014)
=(1/2015+1)+(2/2014+1)+...+(2013/3+1)+(2014/2+1)+(2015/1-2014)
=2016/2015+2016/2014+...+2016/3+2016/2+1
=2016.(1/2016+1/2015+...+1/4+1/3+1/2)
=> A= 1/2016
mún dễ hỉu hơn hãy gửi tin nhắn cho mik
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Giải phương trình
\(\frac{x}{2-12}+\frac{x+1}{2013}+\frac{x+2}{2014}+\frac{x+3}{2015}+\frac{x+4}{2016}=5\)
Phải là \(\frac{x}{2012}\)
\(\frac{x}{2012}-1+\frac{x+1}{2013}-1+\frac{x+2}{2014}-1+\frac{x+3}{2015}-1+\frac{x+4}{2016}-1=0\)
\(\Leftrightarrow\left(x-2012\right)\left(\frac{1}{2012}+\frac{1}{2013}+\frac{1}{2014}+\frac{1}{2015}+\frac{1}{2016}\right)=0\)
\(\Leftrightarrow x=2012\)
Vậy ...
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tính kết quả
\(\frac{1}{2016}-\frac{1}{2016}.2015-\frac{1}{2015}.2014-\frac{1}{2014}.2013-...-\frac{1}{3}.2-\frac{1}{2}.1\)
\(\frac{1}{2016}-\frac{1}{2016}.2015-\frac{1}{2015}.2014-\frac{1}{2014}.2013-...-\frac{1}{3}.2-\frac{1}{2}.1\)
Tính nhanh biểu thức trên
A =\(\frac{2015+\frac{2014}{2}+\frac{2013}{3}+\frac{2012}{4}+\frac{2011}{5}+.....+\frac{1}{2015}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+......+\frac{1}{2016}}=\)
tìm A
Xét tử: \(2015+\frac{2014}{2}+\frac{2013}{3}+...+\frac{1}{2015}\)
\(=\left(1+1+...+1\right)+\frac{2014}{2}+\frac{2013}{3}+...+\frac{1}{2015}\)( trong ngoặc có 2015 số 1 )
\(=\left(1+\frac{2014}{2}\right)+\left(1+\frac{2013}{3}\right)+...+\left(1+\frac{1}{2015}\right)+1\)
\(=\frac{2016}{2}+\frac{2016}{3}+\frac{2016}{4}+...+\frac{2016}{2015}+\frac{2016}{2016}\)
\(=2016\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2016}\right)\)
Ghép tử và mẫu \(\frac{2016\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2016}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2016}}=2016\)
Vậy \(A=2016\)
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