2/6 + 5/6
Đẳng thức nào sau đây là đúng?
56 + 52 = 56 . 2
56 . 52 = 56 + 2
56 . 52 = 56 . 2
56 - 52 = 56 - 2
56 - 52 = 56 : 2
56 : 52 = 56 - 2
56 : 52 = 56 : 2
56 + 52 = 56 + 2
5^6.5^2=5^6+2
5^6/5^2=5^6-2
5 mũ 6.5 mũ 2 = 5 mũ 6 + 2
5 mũ 6 : 5mu 2 = 5 ^6-2
Tìm x biết \(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^4}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)=2\(2^x\)
Sửa đề: 3^5+3^5+3^5; 2^x
=>\(2^x=\dfrac{4^5\cdot4}{3^5\cdot3}\cdot\dfrac{6^5\cdot6}{2^5\cdot2}\)
=>\(2^x=\left(\dfrac{4}{3}\right)^6\cdot\left(\dfrac{6}{2}\right)^6=4^6=2^{12}\)
=>x=12
>, <, = ?
6 – 5 … 2 | 6 – 1 … 4 + 1 |
6 – 4 … 2 | 5 – 3 … 5 – 2 |
5 – 2 … 2 | 6 – 3 … 6 – 2 |
Lời giải chi tiết:
6 – 5 < 2 | 6 – 1 = 4 + 1 |
6 – 4 = 2 | 5 – 3 < 5 – 2 |
5 – 2 > 2 | 6 – 3 < 6 – 2 |
\(x^3=\left(\sqrt[3]{5+2\sqrt{6}}+\sqrt[3]{5-2\sqrt{6}}\right)^3=\sqrt[3]{5+2\sqrt{6}}^3\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)^2}.\sqrt[3]{5-2\sqrt{6}}+3\sqrt[3]{5+2\sqrt{6}}.\sqrt[3]{\left(5-2\sqrt{6}\right)^2}+\sqrt[3]{5-2\sqrt{6}}^3\)
\(=5+2\sqrt{6}+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5+2\sqrt{6}}\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5-2\sqrt{6}}+5-2\sqrt{6}\)
\(=5+5+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5-2\sqrt{6}}\)
\(=10+ 3\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{5-2\sqrt{6}}\)
p/s : có bạn hỏi nên mình đăng , các bạn đừng report nhé
Tìm số tự nhiên n, biết rằng:
\(\dfrac {4^{5} + {4^{5}} +{4^{5}} + {4^{5}}}{{3^{5}} + {3^{5}} + {3^{5}}}\) . \(\dfrac{6^{5} + {6^{5}} + {6^{5}} + {6^{5}} + {6^{5}} + {6^{5}} }{2^{5} + 2^{5}} = 2^{n}\)
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)
\(\Rightarrow\dfrac{4^5.4}{3^5.3}.\dfrac{6^5.6}{2^5.2}=2^n\)
\(\Rightarrow\dfrac{4^5.4.6^5.6}{3^5.3.2^5.2}=2^n\)
\(\Rightarrow\dfrac{\left(2.2\right)^5.2.2.\left(3.2\right)^5.3.2}{3^5.3.2^5.2}=2^n\)
\(\Rightarrow\dfrac{2^5.2^5.2.2.3^5.2^5.3.2}{3^5.3.2^5.2}=2^n\)
Rút gọn vế trái ta có :
\(2^5.2.2.^5=2^n\)
\(\Rightarrow2^{12}=2^n\)
\(\Rightarrow n=12\) ( Thỏa mãn điều kiện \(n\in N\) )
Vậy n =12
Số tự nhiên n thỏa mãn:
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)
=>\(\dfrac{4^5\left(1+1+1+1\right)}{3^5\left(1+1+1\right)}.\dfrac{6^5\left(1+1+1+1+1+1\right)}{2^5\left(1+1\right)}=2^n\)
=>\(\dfrac{4^5.4}{3^5.3}.\dfrac{6^5.6}{2^5.2}=2^n\) =>\(\dfrac{4^6}{3^6}.\dfrac{6^6}{2^6}=2^n\)
=>\(\left(\dfrac{4.6}{3.2}\right)^6=2^n\) =>\(4^6=2^n\) =>\(2^{12}=2^n\) =>n=12.
9+2+5+3+7+8+4+7+4+7+2+4+2+9+6+4+65+6+7+4+6+4+6+3+7+4+8+5+9+08+87+1+2+3+4+2+3+2+5+6+767+5+75+6+4+6+5+66+5+7+546+46+43+6+3+6+4+6+7+8878+68+68+6+7+9+9
\(9+2+5+3+7+8+4+2+9+6+4+65+6+7+4+6+3+7+4+8+5+9+08+87+1+2+3+4+2+3+2+5+6+767+5+75+6+4+6+5+66+5+7+546+46+43+6+3+6+4+6+7+8878+68+68+6+7+9+9=10961\)
2+2+5+5+6+6+5+5+5+5+5+5555++55+6+6
2+2+5+5+6+6+5+5+5+5+5+5555+55+6+6=5673
do than kinh co vay ma ko biet tinh
>, <, =?
6…5 | 3…6 | 6…1 | 3…3 |
6…4 | 6…3 | 4…2 | 3…5 |
6…2 | 6…6 | 2…6 | 3…4 |
Lời giải chi tiết:
6 > 5 | 3 < | 6 > 1 | 3 = 3 |
6 > 4 | 6 > 3 | 4 > 2 | 3 < 5 |
6 > 2 | 6 = 6 | 2 < 6 | 3 < 4 |
Tính nhẩm
5 x 6 = ..... 2 x 6 = ..... 3 x 6 = ..... 4 x 6 = .....
6 x 5 = ..... 6 x 2 = ..... 6 x 3 = ..... 6 x 4 = .....
30 : 6 = ..... 12 : 6 = ..... 18 : 6 = ..... 24 : 6 = .....
30 : 5 = ..... 12 : 2 = ..... 18 : 3 = ..... 24 : 4 = .....
5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 5 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
Tính nhẩm:
5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 5 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
30 : 6 = 5 12 : 6 = 2 18 : 6 = 3 24 : 6 = 4
30 : 5 = 6 12 : 2 = 6 18 : 3 = 6 24 : 4 = 6
Học tốt <3
5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 6 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
30 : 6 = 5 12 : 6 = 2 18 : 6 = 3 24 : 6 = 4
30 : 5 = 6 12 : 2 = 6 18 : 3 = 6 24 : 4 = 6