cảm ơn mọi người

a)\(2.x=6\)

\(\Rightarrow x=6:2=3\)

Vậy x=3

b)\(3^x.3=243\)

\(3^{x+1}=3^5\)

\(\Rightarrow x+1=5\)

\(\Rightarrow x=5-1=4\)

Vậy x=4

c)\(2^x.10^2=1024\)

\(2^x.100=1024\)

\(\Rightarrow2^x=1024:100\)

\(2^x=1,024\)

\(\Rightarrow\)Không có x thỏa mãn

Vậy k thể tìm dduocj x thỏa mãn

Chúc bạn học tốt

a]= 3

b]4

c]1024

mk ko tìm x thỏa mãn được 

a/ \(2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)

Vậy...

b/ \(\left(x+3\right)^2=81\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=9\\x+3=-9\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=6\\x=-12\end{matrix}\right.\)

Vậy ....

c/ \(3^{x+3}=243\)

\(\Leftrightarrow3^{x+3}=3^5\)

\(\Leftrightarrow x+3=5\)

\(\Leftrightarrow x=2\)

Vậy ....

d/ \(\left(2x-5\right)^3=64\)

sai đề thì p

a)   \(3^{x.3}=3^5\)

=> x.3=5

<=>x=5/3

b) x^3=8^2

<=> x^3=(2^3)2

<=>x=2^2

<=>x=4

c) x^20=x

x=1 hoac =0  

chúc bn học tốt 

a. (3x-1)⁵=32                b. (9x-1)²=(2x-3)²

=>(3x-1)⁵=2³                       =>9x-1=2x-3

=>3x-1=2                      =>9x-1-2x+3=0

=>3x=3                         =>7x+2=0

=>x=1                           =>7x=-2 

                                    =>x=-2/7

\(27^3.9^4.243=3^{3.3}.3^{2.4}.3^5\)

\(3^9.3^8.3^5=3^{22}\)

\(25^3.125^2=5^{2.3}.5^{3.2}=5^6.5^6=5^{12}\)

b: \(\left(2x+1\right)^2=25\)

=>\(\left[{}\begin{matrix}2x+1=5\\2x+1=-5\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}2x=4\\2x=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)

c: \(\left(1-3x\right)^3=64\)

=>\(\left(1-3x\right)^3=4^3\)

=>1-3x=4

=>3x=1-4=-3

=>x=-3/3=-1

d: \(\left(4-x\right)^3=-27\)

=>\(\left(4-x\right)^3=\left(-3\right)^3\)

=>4-x=-3

=>x=4+3=7

e: \(x^2-5x=0\)

=>\(x\left(x-5\right)=0\)

=>\(\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)