(67/111+2/33-15/117).(1/3-1/4-1/12)=(67/111+2/33-15/117).0=0

\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)

= \(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

= \(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).0\)

= \(0\)

= 0

(67/111+2/33-15/117) . (1/3-1/4-1/12)

= (67/111+2/33-15/117) .  0

=          2836/5291         .  0

=             0

đáp án là 0 nha em

\(C=\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)x\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)

\(\Rightarrow C=\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)x\left(\frac{1}{12}-\frac{1}{12}\right)\)

\(\Rightarrow C=\left(\frac{67}{11}+\frac{2}{33}-\frac{15}{117}\right)x0\)

\(\Rightarrow C=0\)

C=(67/111 +2/33 −15/117 )x(1/3 −1/4 −1/12 )

= 1/3 - 1/4 - 1/12 = 0

mà bao nhiêu nhân 0 vẫn bằng 0

vậy C = 0

c: \(=\dfrac{4}{9}\left(\dfrac{5}{7}+\dfrac{2}{5}+\dfrac{2}{7}-\dfrac{7}{5}\right)=\dfrac{4}{9}\cdot\left(1-1\right)=0\)

d: \(=\dfrac{4-3-1}{12}\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\)

(67/111+2/33-5/117)x(1/3-25%-1/12)
=-335*x/1285713

ve 2 bang 0 

con ve 1 o can tinh du co lon 

vi 0 nhan bao nhieu cung bang o

ai giup mik giai di

\(=\)\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)\times\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

\(=\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right)\times0\)

\(=0\)

\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)

=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{12}-\frac{1}{12}\right)\)

=\(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).0\)

=0