khó thế

70,80

Số đó chia hết cho 2 và 5 --> hàng đơn vị phải là 0 

  Vậy X có thể là 70 và 80 

(36 + 52) x 46 + (36 + 52) x 53 + 88

=   88      x 46 +        88     x     141

=      4048      +              12408

=                    16456

ta có :

\(8x\left(3x-8\right)+6x\left(-4x+7\right)=-88\)

\(\Leftrightarrow24x^2-64x-24x^2+42x=-88\Leftrightarrow-22x=-88\Leftrightarrow x=4\)

`8x (3x-8) +6x (-4x+7)=-88`

`-> 24x^2 - 64x - 24x^2 + 42x=-88`

`-> (24x^2 - 24x^2)+(-64x+42x)=-88`

`-> -22x=-88`

`->x=-88 : (-22)`

`->x=4`

Vậy `x=4`

23.17-23.14

=23.(17-14)

=23.3 = 69

23.(17-14)=23.3=69

Bài 5: 

a: BC=10cm

b: HA=4,8cm

HB=3,6(cm)

HC=6,4(cm)

Bài 6:

\(x^3=6+3\sqrt[3]{\left(3+2\sqrt{2}\right)\left(3-2\sqrt{2}\right)}\left(\sqrt[3]{3+2\sqrt{2}}+\sqrt[3]{3-2\sqrt{2}}\right)\\ \Leftrightarrow x^3=6+3x\sqrt[3]{1}\\ \Leftrightarrow x^3-3x=6\\ y^3=34+3\sqrt[3]{\left(17+12\sqrt{2}\right)\left(17-12\sqrt{2}\right)}\left(\sqrt[3]{17+12\sqrt{2}}+\sqrt[3]{17-12\sqrt{2}}\right)\\ \Leftrightarrow y^3=34+3y\sqrt[3]{1}\\ \Leftrightarrow y^3-3y=34\\ \Leftrightarrow P=x^3-3x+y^3-3y+1980=6+34+1980=2020\)

gfrưerrrrrrrrrrr

mình làm những bài bn chưa lm nhé

9B

10A

bài 2

have repainted

bàii 3

ride - walikking

swimming

watch

2 have repainted

4 have done 

8 have stepped

9 have you ever played

7) 1 riding -walking

2 swimming

3 watching

8)

2 my mother doesn't like listening to music

5 doing more exercises makes you healthier

còn lại ok nha

chịu ???????????????????

\(3x=4z\Rightarrow\dfrac{x}{4}=\dfrac{z}{3}\); \(\dfrac{x}{5}=\dfrac{y}{6}\)

\(\Rightarrow\dfrac{x}{20}=\dfrac{z}{15}=\dfrac{y}{24}\)

\(\Rightarrow\dfrac{x}{20}=\dfrac{z}{15}=\dfrac{y}{24}=\dfrac{x-y+z}{20-24+15}=\dfrac{121}{11}=11\)

\(\Rightarrow x=20.11=220;z=15.11=165;y=264\)

lèm bài mấy zị

làm hết à  :v

Bài 2:

Ta có:\(2\sqrt{48}< 2\sqrt{49}\) ; 

         \(3\sqrt{27}>3\sqrt{25}\)

mà \(2\sqrt{49}< 3\sqrt{25}\left(14< 15\right)\)

\(\Rightarrow3\sqrt{27}>3\sqrt{25}>2\sqrt{49}>2\sqrt{48}\)

\(\Rightarrow3\sqrt{27}>2\sqrt{48}\)

b)

Ta có:\(\sqrt{50}+\sqrt{2}>\sqrt{49}+\sqrt{1}\) 

        \(\sqrt{50+2}< \sqrt{64}\)

mà \(\sqrt{49}+\sqrt{1}=\sqrt{64}\left(8=8\right)\)

\(\Rightarrow\sqrt{50}+\sqrt{2}>8>\sqrt{50+2}\)

\(\Rightarrow\sqrt{50}+\sqrt{2}>\sqrt{50+2}\)

Bài 2

5 C

Bài 3

1 D

6 C

Còn lại ol r nhé

2) 5. C

3) 2. D

6. C

Còn lại ok nha