\(\dfrac{12}{7}+\dfrac{8}{22}\)
Ét o ét
Tìm 1 phân số \(\dfrac{x}{y}\) sao cho: \(\dfrac{7}{9}\)<\(\dfrac{x}{y}\)<\(\dfrac{7}{8}\) giải thích hộ mik luôn nha!
ét o ét
\(\dfrac{7}{9}< \dfrac{x}{y}< \dfrac{7}{8}\)
\(\dfrac{56}{72}< \dfrac{x}{y}< \dfrac{63}{72}\)
\(\dfrac{x}{y}=\left\{\dfrac{57}{72};\dfrac{58}{72};\dfrac{59}{72};\dfrac{60}{72};\dfrac{61}{72};\dfrac{62}{72}\right\}\)
6. ÉT O ÉT
\(\dfrac{9}{7}\) và \(\dfrac{5}{6}\) \(\dfrac{4}{7}\) và \(\dfrac{8}{21}\) \(\dfrac{2}{5};\dfrac{1}{3}\) và \(\dfrac{1}{2}\) \(\dfrac{1}{3};\dfrac{4}{3}\) và\(\dfrac{1}{5}\)
a: 9/7>1>5/6
b: 4/7=12/21>8/21
c: 2/5=12/30
1/3=10/30
1/2=15/30
mà 10<12<15
nên 1/3<2/5<1/2
a)\(\dfrac{7}{-25}+\dfrac{-8}{25}\)
ét o ét
b)\(\dfrac{-18}{24}-\dfrac{15}{21}\)
a: =-7/25-8/25=-15/25=-3/5
b: =-3/4-5/7=-21/28-20/28=-41/28
\(\dfrac{7}{5}X\dfrac{2}{5}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}X\dfrac{1}{2}\)
35864:175
247x328
ÉT O ÉT
247 X 328 = 81016
35864:175= 35864/175
\(\dfrac{7}{5}x\dfrac{2}{5}=\dfrac{14}{25}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}x\dfrac{1}{2}=\dfrac{3}{4}+5x\dfrac{1}{2}=\dfrac{5}{2}\)
7/5 x 2/5 = 14/25
3/4 + 5/4 : 1/4 x 1/2 = 13/4
6. ÉT O ÉT
\(\dfrac{125}{90}=\dfrac{25}{...}\) / \(\dfrac{84}{91}=\dfrac{...}{13}\) / \(\dfrac{75}{...}=\dfrac{25}{15}=\dfrac{...}{3}\)
\(\dfrac{6}{7}=\dfrac{...}{21}=\dfrac{54}{...}=\dfrac{...}{126}\)
125/90=25/18
84/91=12/13
75/45=25/15=5/3
125/90=25/18
84/91=12/13
75/45=25/15=5/3
6/7=18/21=54/63=104/126
125/90 = 25/18
84/91 = 12/13
75/45 = 25/15 = 5/3
6/7 = 18/21 = 54/63 = 108/126
\(\dfrac{3}{8}\) của 160 kg là 20 kg
đúng hay sai
sossss, ét o ét, éc o éc
\(\dfrac{7}{8}+y=5\)
3042 x 35 - 9045 : 201
ÉT O ÉT
\(y=5-\dfrac{7}{8}=\dfrac{40}{8}-\dfrac{7}{8}=\dfrac{33}{8}\)
3042 x 35 - 9045 : 201
= 106470 - 45 =106425
a.\(\dfrac{7}{8}+y=5\)
\(y=5-\dfrac{7}{8}\)
\(y=\dfrac{33}{8}\)
b.\(3042\times35-9045:201\)
\(=106470-45\)
\(=106425\)
\(\dfrac{7}{8}+y=5\)
3042 x 35 - 9045 : 201
ÉT O ÉT
\(15-\dfrac{x}{2}=\dfrac{3}{7}\)
ét ô ét
\(15-\dfrac{x}{2}=\dfrac{3}{7}\)
\(\dfrac{x}{2}=15-\dfrac{3}{7}=\dfrac{15\cdot7-3}{7}=\dfrac{102}{7}\)
\(x=\dfrac{102}{7}\cdot2=\dfrac{204}{7}\)
\(15-\dfrac{x}{2}=\dfrac{3}{7}\)
\(\dfrac{x}{2}=15-\dfrac{3}{7}\)
\(\dfrac{x}{2}=\dfrac{102}{7}\)
\(x\times7=102\times2\)
\(x\times7=204\)
\(x=204\div7\)
\(x=\dfrac{204}{7}\)