Tim x, biet :
a, x - 150 : 75 = 18
b, 41 - ( 2x - 5 ) = 32
c, 180 + 5 ( x - 13 ) = 100
d, 420 - [ 41 - 2x - 5 ] = 40
e, ( x + 1 ) + ( x + 2 ) + ( x + 3) + ,...............+ ( x + 100 = 5150 )
moi nguoi giup minh nha ! cam on ^^
tim x thuoc z
1)26-|x+9|=-13
2)|x+7|-13=25
tim x biet
1)123-3.(x+4)=23
2)720:[41-(2x-5)]=23.5
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
tìm số tự nhiên a:92.4-27+315
tim so tu nhien x:720:[41-(2x-5)]=23.5
tìm số tự nhiên x:(x+1)+(x+2)+(x+3)+...+(x+100)=5750
khong quy dong tu so va mau so hay so sanh
a) 13/17 va 15/19
tim x biet
a) \(\frac{2}{3}\times x+\frac{3}{4}=3\)
b, 720:[41-(2x x-5)]=120
a)13/17 < 15/19
a) 2/3 x X + 3/4 = 3
2/3 x X = 3 - 3/4
2/3 x X = 9/4
X = 9/4 : 2/3
X = 27/8
a. Ta có : \(\frac{13}{17}=\frac{247}{323};\frac{15}{19}=\frac{255}{323}\)
Vì 255 > 247 nên 247/323 < 255/323
Hay \(\frac{13}{17}< \frac{15}{19}\)
b. \(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(\frac{2}{3}\times x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
c. \(720:\left[41-\left(2\times x-5\right)\right]=120\)
\(\left[41-\left(2\times x-5\right)\right]=720:120\)
\(41-\left(2\times x-5\right)=6\)
\(2\times x-5=35\)
\(2\times x=40\)
\(x=20\)
a)\(\frac{13}{17}>\frac{15}{19}\)
b)\(720\div[41-(2x\times5)]=120\) c)\(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(41-(2x\times5)=270\div120\) \(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(41-(2x-5)=6\) \(\frac{2}{3}\times x=\frac{9}{4}\)
\(2x-5=41-6\) \(x=\frac{9}{4}\div\frac{2}{3}\)
\(2x-5=35\) \(x=\frac{9}{4}\times\frac{3}{2}\)
\(2x=35+5\) \(x=\frac{27}{8}\)
\(2x=40\)
\(x=40\div2\)
\(x=20\)
Tìm số tự nhiên x:
a)720:[41-(2x-5)]=23 .5
b)(x+1)+(x+2)+(x+3)+.... +(x+100)=5750
Tim x biet
A, 5/9 + x/-1 = -1/3
B, 1/5 + 2/20 + 121/165 <x< 1/2 + 156/72 + 1/3 ( x thuoc N)
C, x + 5/3 = 1/81
D, x-1/3 + 3x-5/2 + 2x/9 + -5x+3/9 = 210/420
a: -x+5/9=-1/3
nên x=5/9+1/3=5/9+3/9=8/9
b: \(\Leftrightarrow\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{11}{15}< x< \dfrac{1}{2}+\dfrac{13}{12}+\dfrac{1}{3}\)
=>31/30<x<23/12
mà x là số nguyên
nên \(x\in\varnothing\)
c: x+5/3=1/81
nên x=1/81-135/81=-134/81
Tìm số tự nhiên x, biết rằng:
a, 720 : [41 - (2x - 5) ] = 2^3 . 5
b, (x +1) + (x +2) +...+(x +100) = 5750
a728:[41-(2x-5)]=8.5
b (x+1)+(x+2)+(x+3)+...+(x+100)=5750
Tìm x
(x+1) + (x+2) + ...+(x+100)=5750
720 : [41- (2x-5)] =23 .5
a ) (x+1)+...+(x+100)
= (x+x+..+x)+(1+..+100)
=100x + (100+1).100:2
=100x + 5050
=5750
<=> 100x = 5750 - 5050
<=> 100x = 700
=> x = 700 : 100 = 7
b) 720 : [ 41-(2x-5)]= 40
41-(2x-5) = 720 : 40
41-(2x-5) = 18
2x-5 = 41-18= 23
2x = 23+5 = 28
=> x = 28:2 = 14
Chúc Bạn Học Tốt
Nếu sai thì thông cảm ạ
Tìm số tự nhiên x biết rằng
720:[41-(2x-5)]=23.5
(x+1)+(x+2)+(x+3)+…+(x+100)=5750
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7