Please giup minh nha
Rut gon
c,6^2 . 6^4 -4^3 (3^6 -1)
10+2-3+2+2+2+3+5+9-5-5-4-6+6+8+7+8+9-6+4-5+3-6+3-6+3+5+4+6-3+5-3+4-4+4=
giup minh nhanh nha
6^6*3^6*2^6
10^2*5^3*2^4
GIAI GIUP MINH NHA !!!!!!!
Tinh nhanh:
m)5^1+5^2+5^3+...+5^199+5^200
n)3^0-3^2+3^3-3^4+...+3^2017-3^2018+3^2019-3^2020
o)6+6*9+6*9^2+6*9^3+...+6*9^99
p)(-1)*(-1^2)*(-1^3)*(-1^4)*...*(-1^99)*-(1^100)
Giup minh nhe!
Đặt \(A=5+5^2+5^3+....+5^{199}+5^{200}\)
\(\Leftrightarrow5A=5\left(5+5^2+5^3+....+5^{199}+5^{200}\right)\)
\(\Leftrightarrow5A=5^2+5^3+5^4+....+5^{200}+5^{201}\)
\(\Leftrightarrow5A-A=\left(5^2+5^3+5^4+....+5^{200}+5^{201}\right)-\left(5+5^2+5^3+....+5^{199}+5^{200}\right)\)
\(\Leftrightarrow4A=5^{201}-5\)
\(\Leftrightarrow A=\frac{5^{201}-5}{4}\)
Tim so nguyen x, biet :
a) (1/2 - 1/3) . 6x + 6x + 2 = 615 + 618.
b) (1/2 - 1/6) . 3x + 4 - 4 . 3x = 316 - 4 . 313.
Minh dang can gap. Ai biet thi chi giup minh voi nhe! Cam on moi nguoi .
3/2*3*4 + 3/3*4*5 + 3/4*5*6 +..............+ 3/100*101*102
giup minh ti minh dang can gap traong 1 tieng
mk nghĩ câu hỏi này ko xứng tầm lớp 5 đâu!
\(\frac{3}{2.3.4}+\frac{3}{3.4.5}+...+\frac{3}{100.101.102}\)
\(=\frac{3}{2}\left(\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{100.101}-\frac{1}{101.102}\right)\)
\(=\frac{3}{2}\left(\frac{1}{6}-\frac{1}{101.102}\right)\)
1/4+3/4:-6/-7
giai chi tiet giup minh
6/5/12:2/3/4+11/1/4 x(1/3-1/5)
Giup minh nha minh can gap ngay bay gio
mk viết đáp án rồi bn tự giải nha
=169/15
Dien ki hieu toan hoc :
1 1 1 = 6
2 2 2 = 6
3 3 3 =6
4 4 4 =6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 =6
9 9 9 =6
10 10 10 = 6
giup minh voi minh tk cho
(1 + 1 + 1)! = 6
2 + 2 + 2 = 6
3 * 3 - 3 =6
5 + 5 / 5 = 6
6 + 6 - 6 = 6
7 + 7 / 7 = 6
mình biết chừng đó thoy
(1+1+1)!=6
2+2+2=6
3*3-3=6
căn4+ căn+ căn 4=6
căn9*căn9-căn9=6
c
4^5 * 9^4 - 2 * 6^9
--------------------------
2^10 * 3^8 + 6^8 * 20
giup minh nha