24x 5= ?
Kết quả của phép rút gọn biểu thức 6x(4x – 5) – 24x 2 là:
A. 30x
B – 30x
C. – 24x 2
D. 24x 2
\(6x\left(4x-5\right)-24x^2=24x^2-30x-24x^2=-30x\)
ý B
6x^3+(-24x^5)
\(6x^3-24x^5=6x^3\left(1-4x^2\right)=6x^3\left(1-2x\right)\left(1+2x\right)\)
(24X + 5^3) - 4.5^4=5^4
Bài làm
( 24x + 53 ) - 4.54 = 54
( 24x + 53 ) - 4.625 = 625
( 24x + 53 ) - 2500 = 625
( 24x + 53 ) = 625 + 2500
( 24x + 53 ) = 3125
24x + 125 = 3125 - 125
24x = 3000
x = 3000 : 24
x = 125
Vậy x = 125
# Chúc bạn học tốt #
( 24x + 53 ) - 4 . 54 = 54
( 24x + 125 ) - 4 . 625 = 626
( 24x + 125 ) - 2500 = 625
24x + 125 = 625 + 2500
24x + 125 = 3125
24x = 3125 - 125
24x = 3000
x = 3000 : 24
x = 125
Học tốt !
\(24x^2-20x+5=0\)
\(24x^2-20x+5=0\)
\(\Leftrightarrow x^2-\dfrac{5}{6}x+\dfrac{5}{24}=0\)
\(\Leftrightarrow x^2-2\cdot\dfrac{5}{12}\cdot x+\left(\dfrac{5}{12}\right)^2+\dfrac{5}{144}=0\)
\(\Leftrightarrow\left(x-\dfrac{5}{12}\right)^2+\dfrac{5}{144}=0\)
=> PTVN
Ta có : \(24x^2-20x+5=24\left(x^2-\dfrac{20}{24}x+\dfrac{5}{24}\right)=24\left[\left(x^2-2.\dfrac{20}{48}.x+\dfrac{25}{144}+\dfrac{5}{144}\right)\right]=24\left[\left(x-\dfrac{20}{48}\right)^2+\dfrac{5}{144}\right]\ge\dfrac{24.5}{144}=\dfrac{5}{6}>0\left(\forall x\right)\)
Do đó không có giá trị nào của x thỏa mãn.
(18x^6y^6 - 12x^5y^5 + 24x^3y^5) : 6x^3y^5.
16x^3y^4/24x^2y^5
\(\dfrac{16x^3y^4}{24x^2y^5}=\dfrac{2x}{3y}\)
-12(x-5)+7(3-x)=5 30(x+2)-6(x-5)-24x=100
(x+1-5)+7(3-x)=5 30(x+2)-6(x-5)-24x=100
(x+1)+(x+3)+(x+5)+........+(x+99)=0
\(\text{-12(x-5)+7(3-x)=5 }\)
\(-12x+60+21-7x=5\)
\(-12x-7x=5-21-60\)
\(-19x=-76\)
\(x=-76:\left(-19\right)\)
\(x=4\)
\(\text{ 30(x+2)-6(x-5)-24x=100}\)
\(30x+60-6x+30-24x=100\)
\(30x-6x-24x=100-30-60\)
\(0=10\)
\(\Rightarrow x\)ko tồn tại
\(\text{(x+1-5)+7(3-x)=5 }\)
\(x+1-5+21-7x=5\)
\(x-7x=5-21+5-1\)
\(-6x=-12\)
\(x=\left(-12\right):\left(-6\right)\)
\(x=2\)
\(\text{(x+1)+(x+3)+(x+5)+........+(x+99)=0}\)
\(\text{(x+1)+(x+3)+...+(x+99)=0}\)
tổng các số hang là\(\frac{\left(99+1\right)}{2}=50\)(số hạng)
=>\(\text{(x+1)+(x+3)+...+(x+99)=0}\)<=> \(\text{50.x+(1+3+5+..+99)=0}\)
<=>\(\text{50.x+(99+1)}\)\(.\frac{50}{2}=0\)<=> \(\text{50.x+2500=0=}\)>\(x=\frac{-2500}{50}=-50\)
chúc bạn học tốt
√2x-5 +√7-2x=4x^2-24x+38
1-(5/3/8+x-7/5/24x)/16/2/3=0