a, 2^3=8, 2^4=16,2^5=32, 2^6=64, 2^7=128, 2^8=256, 2^9=512, 2^10=1024

b, 3^2=9, 3^3=27, 3^4=81, 3^5=243

c, 4^2=16, 4^3=64, 4^4=256

d, 5^2=25, 5^3=125, 5^4=625

e, 6^2=36, 6^3=216, 6^4= 1296

\(\left(2x-7\right)\cdot5^{40}=5^{38}\cdot5^2\)

\(\left(2x-7\right)\cdot5^{40}=5^{40}\)

\(2x-7=1\)

\(2x=8\)

\(x=4\)

Câu 1:

1;   125 : 5²

   =   5³ : 5²

   =      5¹

2; 27⁵ : 81³

 = (3³)⁵ : (3⁴)³

 = 3¹⁵ : 3¹²

= 3³ 

3; 8⁴.16⁵.32

= (2³)⁴.(2⁴)⁵.2⁵

= 2¹².2²⁰.2⁵

= 2³⁷

Câu 1

4; 27⁴.81¹⁰

= (3³)⁴.(3⁴)¹⁰

= 3¹².3⁴⁰

= 3⁵²

Câu 2:

1; 125⁵ = (5³)⁵ = 5¹⁵

    25⁵ = (5²)⁵ = 5¹⁰ < 5¹⁵ < 125⁵

2; 3²⁰⁰ = (3²)¹⁰⁰ = 9¹⁰⁰

     2³⁰⁰ = (2³)¹⁰⁰ = 8¹⁰⁰ < 9¹⁰⁰ < 3²⁰⁰

mình không biết thật

#)Giải :

\(\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{4}\right)^{20}=\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{-25}\)

Cảm ơn bạn nha

\(9x^2-6x+1-9x^2-9x=-15x+1\)

\(\left(3x-1\right)^2-9x\left(x+1\right)\)

\(=9x^2-6x+1-9x^2-9x\)

=-15x+1

Có: 7-3.\(\frac{-1}{4}^2\)

= 7-3. \(\frac{1}{16}\)

= 7- \(\frac{3}{16}\)

= \(\frac{112}{16}\)-\(\frac{3}{16}\)

= \(\frac{109}{16}\)

2^0 x 2^9 : 8 

= 1 x 512 : 8 

= 64

nha bạn 

Bằng 64

=64 nha

HT