\(2Al+3S\underrightarrow{t^0}Al_2S_3\)

\(Fe+S\underrightarrow{t^0}FeS\)

\(Pb+S\underrightarrow{t^0}PbS\)

\(2Na+S\underrightarrow{t^0}Na_2S\)

a) 2 Al + 3 S -to-> Al2S3

b) Fe + S -to-> FeS

c) Pb + S -to-> PbS

d) 2 Na + S -to-> Na2S

a. S + Al → Al₂S₃.

b. Fe + S → FeS.

c. Pb + S → PbS.

d. Na + S → Na₂S.

                (Tất cả các phản ứng trên đều có nhiệt độ nha.)

\(Mg+S\rightarrow\left(t^o\right)MgS\)

\(Zn+S\rightarrow\left(t^o\right)ZnS\)

\(Fe+S\rightarrow\left(t^o\right)FeS\)

\(2Al+3S\rightarrow\left(t^o\right)Al_2S_3\)

Phương trình hóa học:

Mg + S → MgS

Fe + S → FeS

Zn + S → ZnS

2Al + 3S → Al2S3

\(Mg+S\underrightarrow{t^o}MgS\\ Zn+S\underrightarrow{t^o}ZnS\\ Fe+S\underrightarrow{t^o}FeS\\ 2Al+3S\underrightarrow{t^o}Al_2S_3\)

S+Mg->MgS

S+Zn->ZnS

S+Se->FeS

3S+2Al->Al2S3

Câu 1 :

a,

\(K+O_2\underrightarrow{^{to}}K_2O\)

\(2Ca+O_2\underrightarrow{^{to}}2CaO\)

\(3Fe+2O_2\underrightarrow{^{to}}Fe_3O_4\)

\(C+O_2\underrightarrow{^{to}}CO_2\)

\(S+O_2\underrightarrow{^{to}}SO_2\)

b,

\(CH_4+2O_2\underrightarrow{^{to}}CO_2+2H_2O\)

\(C_2H_4+3O_2\underrightarrow{^{to}}2CO_2+2H_2O\)

\(C_2H_2+\frac{5}{2}O_2\underrightarrow{^{to}}2CO_2+H_2O\)

\(2CO+O_2\underrightarrow{^{to}}2CO_2\)

Câu 2 :

\(S+Zn\underrightarrow{^{to}}ZnS\)

\(3S+2Al\underrightarrow{^{to}}Al_2S_3\)

\(S+Mg\underrightarrow{^{to}}MgS\)

\(S+Cu\underrightarrow{^{to}}CuS\)

\(S+Fe\underrightarrow{^{to}}FeS\)

Bài 1 :

\(d_{A/H2}=17\Leftrightarrow M_A=17.2=34\left(\frac{g}{mol}\right)\)

\(d_{A/kk}=0,55\Leftrightarrow M_A=0,55.29=15,95\left(\frac{g}{mol}\right)\)

\(d_{A/H2S}=0,425\Leftrightarrow M_A==0,425.34=14,45\left(\frac{g}{mol}\right)\)

Bài 2:

\(S+Zn\underrightarrow{^{to}}ZnS\)

\(3S+2Al\rightarrow Al_2S_3\)

\(S+Mg\underrightarrow{^{to}}MgS\)

\(S+Cu\underrightarrow{^{to}}CuS\)

\(S+Fe\underrightarrow{^{to}}FeS\)

Phương trình hóa học:

\(Mg+S\rightarrow MgS\)

\(Fe+S\rightarrow FeS\)

\(Zn+S\rightarrow ZnS\)

\(2Al+3S\rightarrow Al_2S_3\)

\(a.Zn+H_2SO_4\rightarrow ZnSO_4+H_2\\ b.Zn+2AgNO_3\rightarrow Zn\left(NO_3\right)_2+2Ag\\ c.2Na+S\xrightarrow[]{t^0}Na_2S\\ d.Ca+Cl_2\xrightarrow[]{t^0}CaCl_2\\ e.MgO+2HNO_3\rightarrow Mg\left(NO_3\right)_2+H_2O\\ f.Fe+2HCl\rightarrow FeCl_2+H_2\\ g.CuO+2HCl\rightarrow CuCl_2+H_2O\\ h.2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\\ i.Cl+2NaOH\rightarrow NaCl+NaClO+H_2O\\ k.MgO_2+4HCl_{đặc}\xrightarrow[nhẹ]{đun}MgCl_2+Cl_2+2H_2O\)

Bàu 1

a) 4P+5O2--->2P2O5

S+O2--->SO2

3Fe+2O2--->Fe3O4

C2H4+3O2-->2CO2+2H2O

4Na+O2--->2Na2O

trừ phản ứng C2H4 thì tất cả đề là phản ứng hóa hợp

Bài 2

2H2+O2--->2H2O

2Mg+O2--->2MgO

2Cu+O2--->2CuO

S+O2--->SO2

4Al+3O2--->2Al2O3

C+O2---->CO2

4P+5O2--->2P2O5

Bài 1 :

a,

\(4P+5O_2\underrightarrow{^{to}}2P_2O_5\) (1)

\(S+O_2\underrightarrow{^{to}}SO_2\)(2)

\(3Fe+2O_2\underrightarrow{^{to}}Fe_3O_4\)(3)

\(C_2H_4+3O_2\underrightarrow{^{to}}2CO_2\uparrow+2H_2O\)(4)

\(4Na+O_2\underrightarrow{^{to}}2Na_2O\)(5)

\(2Ca+O_2\underrightarrow{^{to}}2CaO\)(6)

b, PHản ứng hóa hợp : (1) ; (2) ; (3) ;(5) ; (6)

Bài 2 :

\(2H_2+O_2\underrightarrow{^{to}}2H_2O\)

\(2Mg+O_2\underrightarrow{^{to}}2MgO\)

\(2Cu+O_2\underrightarrow{^{to}}2CuO\)

\(S+O_2\underrightarrow{^{to}}SO_2\)

\(4Al+3O_2\underrightarrow{^{to}}2Al_3O_3\)

\(C+O_2\underrightarrow{^{to}}CO_2\)

\(4P+5O_2\underrightarrow{^{to}}2P_2O_5\)

Bài 1 mk ko chắc lắm nha b.B nào biết chắc đáp án đúng thì chỉ mk nha.

có hợp chất nhôm sunfua nữa hả bn?